結果
問題 | No.1084 積の積 |
ユーザー | first_vil |
提出日時 | 2020-06-19 22:05:05 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 76 ms / 2,000 ms |
コード長 | 5,532 bytes |
コンパイル時間 | 2,228 ms |
コンパイル使用メモリ | 208,452 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-07-03 14:45:21 |
合計ジャッジ時間 | 4,033 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 1 ms
6,812 KB |
testcase_01 | AC | 2 ms
6,944 KB |
testcase_02 | AC | 2 ms
6,940 KB |
testcase_03 | AC | 1 ms
6,944 KB |
testcase_04 | AC | 60 ms
6,940 KB |
testcase_05 | AC | 7 ms
6,940 KB |
testcase_06 | AC | 23 ms
6,940 KB |
testcase_07 | AC | 2 ms
6,940 KB |
testcase_08 | AC | 2 ms
6,940 KB |
testcase_09 | AC | 12 ms
6,940 KB |
testcase_10 | AC | 2 ms
6,940 KB |
testcase_11 | AC | 4 ms
6,944 KB |
testcase_12 | AC | 31 ms
6,940 KB |
testcase_13 | AC | 69 ms
6,940 KB |
testcase_14 | AC | 24 ms
6,940 KB |
testcase_15 | AC | 22 ms
6,940 KB |
testcase_16 | AC | 73 ms
6,940 KB |
testcase_17 | AC | 27 ms
6,940 KB |
testcase_18 | AC | 45 ms
6,940 KB |
testcase_19 | AC | 65 ms
6,944 KB |
testcase_20 | AC | 14 ms
6,940 KB |
testcase_21 | AC | 23 ms
6,944 KB |
testcase_22 | AC | 17 ms
6,944 KB |
testcase_23 | AC | 37 ms
6,940 KB |
testcase_24 | AC | 32 ms
6,940 KB |
testcase_25 | AC | 59 ms
6,944 KB |
testcase_26 | AC | 67 ms
6,940 KB |
testcase_27 | AC | 68 ms
6,944 KB |
testcase_28 | AC | 71 ms
6,944 KB |
testcase_29 | AC | 72 ms
6,944 KB |
testcase_30 | AC | 76 ms
6,944 KB |
testcase_31 | AC | 69 ms
6,940 KB |
ソースコード
//四則演算 #pragma GCC target("avx") //並列計算 #pragma GCC optimize("O3") //条件分岐を減らす #pragma GCC optimize("unroll-loops") //浮動小数点演算 #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #include <bits/stdc++.h> using namespace std; using ll = long long; using ld = long double; using VI = vector<int>; using VL = vector<ll>; using VS = vector<string>; template<class T> using PQ = priority_queue<T, vector<T>, greater<T>>; #define FOR(i,a,n) for(int i=(a);i<(n);++i) #define eFOR(i,a,n) for(int i=(a);i<=(n);++i) #define rFOR(i,a,n) for(int i=(n)-1;i>=(a);--i) #define erFOR(i,a,n) for(int i=(n);i>=(a);--i) #define each(i, a) for(auto &i : a) #define SORT(a) sort(a.begin(),a.end()) #define rSORT(a) sort(a.rbegin(),a.rend()) #define fSORT(a,f) sort(a.begin(),a.end(),f) #define all(a) a.begin(),a.end() #define out(y,x) ((y)<0||h<=(y)||(x)<0||w<=(x)) #define tp(a,i) get<i>(a) #define line cout << "-----------------------------\n" #define ENDL(i,n) ((i) == (n) - 1 ? "\n" : " ") #define stop system("pause") constexpr ll INF = 1000000000; constexpr ll LLINF = 1LL << 60; constexpr ll mod = 1000000007; constexpr ll MOD = 998244353; constexpr ld eps = 1e-10; constexpr ld pi = 3.1415926535897932; template<class T>inline bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; }return false; } template<class T>inline bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; }return false; } inline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); } template<class T>inline istream& operator>>(istream& is, vector<T>& v) { for (auto& a : v)is >> a; return is; } template<class T>inline istream& operator>>(istream& is, deque<T>& v) { for (auto& a : v)is >> a; return is; } template<class T, class U>inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; } template<class T>inline vector<T> vec(size_t a) { return vector<T>(a); } template<class T>inline vector<T> defvec(T def, size_t a) { return vector<T>(a, def); } template<class T, class... Ts>inline auto vec(size_t a, Ts... ts) { return vector<decltype(vec<T>(ts...))>(a, vec<T>(ts...)); } template<class T, class... Ts>inline auto defvec(T def, size_t a, Ts... ts) { return vector<decltype(defvec<T>(def, ts...))>(a, defvec<T>(def, ts...)); } template<class T>inline void print(const T& a) { cout << a << "\n"; } template<class T, class... Ts>inline void print(const T& a, const Ts&... ts) { cout << a << " "; print(ts...); } template<class T>inline void print(const vector<T>& v) { for (int i = 0; i < v.size(); ++i)cout << v[i] << (i == v.size() - 1 ? "\n" : " "); } template<class T>inline void print(const vector<vector<T>>& v) { for (auto& a : v)print(a); } inline string reversed(const string& s) { string t = s; reverse(all(t)); return t; } template<int modulo> struct ModInt { int x; ModInt() : x(0) {} ModInt(long long y) : x(y >= 0 ? y % modulo : (modulo - (-y) % modulo) % modulo) {} ModInt& operator+=(const ModInt& p) { if ((x += p.x) >= modulo) x -= modulo; return *this; } ModInt& operator-=(const ModInt& p) { if ((x += modulo - p.x) >= modulo) x -= modulo; return *this; } ModInt& operator*=(const ModInt& p) { x = (int)(1LL * x * p.x % modulo); return *this; } ModInt& operator/=(const ModInt& p) { *this *= p.inverse(); return *this; } ModInt operator-() const { return ModInt(-x); } ModInt operator+(const ModInt& p) const { return ModInt(*this) += p; } ModInt operator-(const ModInt& p) const { return ModInt(*this) -= p; } ModInt operator*(const ModInt& p) const { return ModInt(*this) *= p; } ModInt operator/(const ModInt& p) const { return ModInt(*this) /= p; } bool operator==(const ModInt& p) const { return x == p.x; } bool operator!=(const ModInt& p) const { return x != p.x; } ModInt inverse() const { int a = x, b = modulo, u = 1, v = 0, t; while (b > 0) { t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); } return ModInt(u); } ModInt pow(int e) { long long a = 1, p = x; while (e > 0) { if (e % 2 == 0) { p = (p * p) % modulo; e /= 2; } else { a = (a * p) % modulo; e--; } } return ModInt(a); } friend ostream& operator<<(ostream& os, const ModInt<modulo>& p) { return os << p.x; } friend istream& operator>>(istream& is, ModInt<modulo>& a) { long long x; is >> x; a = ModInt<modulo>(x); return (is); } }; using modint = ModInt<mod>; int main() { init(); int n; cin >> n; VL a(n); cin >> a; if (*min_element(all(a)) == 0) { print(0); return 0; } vector<modint> b(n, 1), c(n, 1); FOR(i, 0, n) { if (0 < i) { b[i] *= b[i - 1]; c[i] *= c[i - 1]; } b[i] *= a[i]; c[i] *= b[i]; } modint ans = 1; FOR(i, 0, n) { if (0 < i)ans /= b[i - 1].pow(n - i) * c[i - 1]; ans *= c.back(); } ll cur = 1; for (int l = 0, r = 0; l < n; ++l) { for (; r < n && cur * a[r] < INF; ++r)cur *= a[r]; ans /= c.back(); ans *= c[r - 1]; if (0 < l)ans *= b[l - 1].pow(n - r); cur /= a[l]; } print(ans); return 0; }