結果

問題 No.1087 転倒数の転倒数
ユーザー heno239
提出日時 2020-06-19 23:04:47
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 109 ms / 2,000 ms
コード長 3,745 bytes
コンパイル時間 1,428 ms
コンパイル使用メモリ 117,912 KB
実行使用メモリ 23,952 KB
最終ジャッジ日時 2024-11-14 07:30:48
合計ジャッジ時間 18,119 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 6
other AC * 31
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
using namespace std;
//#define int long long
typedef long long ll;
typedef unsigned long long ul;
typedef unsigned int ui;
constexpr ll mod = 1000000007;
const ll INF = mod * mod;
typedef pair<int, int>P;
#define stop char nyaa;cin>>nyaa;
#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;
typedef long double ld;
typedef pair<ld, ld> LDP;
const ld eps = 1e-12;
const ld pi = acos(-1.0);
ll mod_pow(ll x, ll n) {
    ll res = 1;
    while (n) {
        if (n & 1)res = res * x%mod;
        x = x * x%mod; n >>= 1;
    }
    return res;
}
struct modint {
    ll n;
    modint() :n(0) { ; }
    modint(ll m) :n(m) {
        if (n >= mod)n %= mod;
        else if (n < 0)n = (n%mod + mod) % mod;
    }
    operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
modint operator+=(modint &a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }
modint operator-=(modint &a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }
modint operator*=(modint &a, modint b) { a.n = ((ll)a.n*b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, int n) {
    if (n == 0)return modint(1);
    modint res = (a*a) ^ (n / 2);
    if (n % 2)res = res * a;
    return res;
}
ll inv(ll a, ll p) {
    return (a == 1 ? 1 : (1 - p * inv(p%a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }
const int max_n = 1 << 20;
modint fact[max_n], factinv[max_n];
void init_f() {
    fact[0] = modint(1);
    for (int i = 0; i < max_n - 1; i++) {
        fact[i + 1] = fact[i] * modint(i + 1);
    }
    factinv[max_n - 1] = modint(1) / fact[max_n - 1];
    for (int i = max_n - 2; i >= 0; i--) {
        factinv[i] = factinv[i + 1] * modint(i + 1);
    }
}
modint comb(int a, int b) {
    if (a < 0 || b < 0 || a < b)return 0;
    return fact[a] * factinv[b] * factinv[a - b];
}
vector<vector<int>> b3 = {
    {2,1,0},
  {5,3,4},
  {6,7,8}
};
vector<vector<int>> b2 = {
    {1,0 },
{ 2,3 },
};
int ans[1000][1000];
void solve() {
    int n, k; cin >> n >> k;
    if (k > n*(n - 1)) {
        cout << "No\n"; return;
    }
    cout << "Yes\n";
    if (n == 1) {
        cout << 1 << "\n"; return;
    }
    int le = 1, ri = n * n;
    rep(i, n) {
        if (n - i == 3 && k == 3) {
            rep(j, 3)rep(k, 3) {
                ans[i + j][i + k] = le + b3[j][k];
            }
            break;
        }
        if (n - i == 2 && k == 1) {
            rep(j, 2)rep(k, 2) {
                ans[i + j][i + k] = le + b2[j][k];
            }
            break;
        }
        int num = n - 1 - i;
        num *= 2;
        if (num <= k) {
            ans[i][i] = ri; ri--;
            for (int j = n - 1; j > i; j--) {
                ans[j][i] = le; le++;
            }
            for (int j = n - 1; j > i; j--) {
                ans[i][j] = le; le++;
            }
            k -= num;
        }
        else {
            ans[i][i] = le; le++;
            for (int j = i + 1; j < n; j++) {
                ans[j][i] = le; le++;
            }
            for (int j = i + 1; j < n; j++) {
                ans[i][j] = le; le++;
            }
        }
    }
    rep(i, n) {
        rep(j, n) {
            if (j > 0)cout << " ";
            cout << ans[i][j];
        }
        cout << "\n";
    }
}
signed main() {
    //ios::sync_with_stdio(false);
    //cin.tie(0);
    //cout << fixed << setprecision(10);
    //int t; cin >> t; rep(i, t)
        solve();
    stop
        return 0;
}
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