結果
問題 | No.847 Divisors of Power |
ユーザー | heno239 |
提出日時 | 2020-06-20 08:48:49 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 9 ms / 2,000 ms |
コード長 | 3,223 bytes |
コンパイル時間 | 1,056 ms |
コンパイル使用メモリ | 117,600 KB |
実行使用メモリ | 20,032 KB |
最終ジャッジ日時 | 2024-07-03 16:50:07 |
合計ジャッジ時間 | 2,326 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 26 |
ソースコード
#include<iostream> #include<string> #include<cstdio> #include<vector> #include<cmath> #include<algorithm> #include<functional> #include<iomanip> #include<queue> #include<ciso646> #include<random> #include<map> #include<set> #include<bitset> #include<stack> #include<unordered_map> #include<utility> #include<cassert> #include<complex> #include<numeric> using namespace std; //#define int long long typedef long long ll; typedef unsigned long long ul; typedef unsigned int ui; constexpr ll mod = 1000000007; const ll INF = mod * mod; typedef pair<int, int>P; #define stop char nyaa;cin>>nyaa; #define rep(i,n) for(int i=0;i<n;i++) #define per(i,n) for(int i=n-1;i>=0;i--) #define Rep(i,sta,n) for(int i=sta;i<n;i++) #define rep1(i,n) for(int i=1;i<=n;i++) #define per1(i,n) for(int i=n;i>=1;i--) #define Rep1(i,sta,n) for(int i=sta;i<=n;i++) #define all(v) (v).begin(),(v).end() typedef pair<ll, ll> LP; typedef long double ld; typedef pair<ld, ld> LDP; const ld eps = 1e-12; const ld pi = acos(-1.0); ll mod_pow(ll x, ll n) { ll res = 1; while (n) { if (n & 1)res = res * x%mod; x = x * x%mod; n >>= 1; } return res; } struct modint { ll n; modint() :n(0) { ; } modint(ll m) :n(m) { if (n >= mod)n %= mod; else if (n < 0)n = (n%mod + mod) % mod; } operator int() { return n; } }; bool operator==(modint a, modint b) { return a.n == b.n; } modint operator+=(modint &a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; } modint operator-=(modint &a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; } modint operator*=(modint &a, modint b) { a.n = ((ll)a.n*b.n) % mod; return a; } modint operator+(modint a, modint b) { return a += b; } modint operator-(modint a, modint b) { return a -= b; } modint operator*(modint a, modint b) { return a *= b; } modint operator^(modint a, int n) { if (n == 0)return modint(1); modint res = (a*a) ^ (n / 2); if (n % 2)res = res * a; return res; } ll inv(ll a, ll p) { return (a == 1 ? 1 : (1 - p * inv(p%a, a)) / a + p); } modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); } const int max_n = 1 << 20; modint fact[max_n], factinv[max_n]; void init_f() { fact[0] = modint(1); for (int i = 0; i < max_n - 1; i++) { fact[i + 1] = fact[i] * modint(i + 1); } factinv[max_n - 1] = modint(1) / fact[max_n - 1]; for (int i = max_n - 2; i >= 0; i--) { factinv[i] = factinv[i + 1] * modint(i + 1); } } modint comb(int a, int b) { if (a < 0 || b < 0 || a < b)return 0; return fact[a] * factinv[b] * factinv[a - b]; } void solve() { int n, k, m; cin >> n >> k >> m; vector<LP> ps; for (int i = 2; i <= 40000; i++) { if (n%i == 0) { int cnt = 0; while (n%i == 0) { cnt++; n /= i; } ps.push_back({ i,cnt }); } } if(n>1)ps.push_back({ n,1 }); rep(i, ps.size()) { ps[i].second *= k; } ll ans = 0; function<void(int, ll)> dfs = [&](int id, ll s) { if (id == ps.size()) { ans++; return; } rep(j, ps[id].second+1) { if (s > m)break; dfs(id + 1, s); s *= ps[id].first; } }; dfs(0, 1); cout << ans << "\n"; } signed main() { //ios::sync_with_stdio(false); //cin.tie(0); //cout << fixed << setprecision(10); //int t; cin >> t; rep(i, t) solve(); stop return 0; }