結果
| 問題 |
No.261 ぐるぐるぐるぐる!あみだくじ!
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2015-09-19 03:40:17 |
| 言語 | Python3 (3.13.1 + numpy 2.2.1 + scipy 1.14.1) |
| 結果 |
AC
|
| 実行時間 | 33 ms / 5,000 ms |
| コード長 | 1,741 bytes |
| コンパイル時間 | 77 ms |
| コンパイル使用メモリ | 12,544 KB |
| 実行使用メモリ | 11,008 KB |
| 最終ジャッジ日時 | 2024-07-19 07:51:51 |
| 合計ジャッジ時間 | 2,493 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 37 |
ソースコード
def read_data():
N = int(input())
K = int(input())
amida = list(range(N))
for k in range(K):
x, y = map(int, input().split())
amida[x-1], amida[y-1] = amida[y-1], amida[x-1]
Q = int(input())
As = []
for q in range(Q):
a = list(map(int, input().split()))
As.append(a)
return N, amida, Q, As
def solve(N, amida, Q, As):
cycles = [0] * N
pos = [[-1] * N for n in range(N)]
for idx in range(N):
find_cycle(N, amida, idx, cycles, pos[idx])
shuffle = [chinese_remainder(a, cycles, pos) for a in As]
return shuffle
def find_cycle(N, amida, idx, cycles, mypos):
mypos[idx] = 0
a = amida[idx]
count = 1
while a != idx:
mypos[a] = count
a = amida[a]
count += 1
cycles[idx] = count
def chinese_remainder(a, cycles, pos):
xy = []
for ai, cycle, mypos in zip(a, cycles, pos):
x = mypos[ai - 1]
if x == -1:
return -1
xy.append((x, cycle))
return CRT(xy)
def gcd_ext(m, n):
x, y, u, v = 1, 0, 0, 1
while n:
k, m = divmod(m, n)
m, n = n, m
x, y, u, v = u, v, x - u * k, y - v * k
return m, x, y
def solve2(x1, y1, x2, y2):
gcd, a, b = gcd_ext(y1, y2)
lcm = y1 * y2 // gcd
k, r = divmod(x1 - x2, gcd)
if r != 0:
return -1, lcm
z = (x1 - k * a * y1) % lcm
return z, lcm
def CRT(xy):
x0, y0 = xy[0]
if len(xy) == 1:
return x0 if x0 else y0
for x1, y1 in xy[1:]:
x0, y0 = solve2(x0, y0, x1, y1)
if x0 == -1:
return -1
return x0 if x0 else y0
N, amida, Q, As = read_data()
shuffles = solve(N, amida, Q, As)
for shuffle in shuffles:
print(shuffle)