結果
問題 | No.1035 Color Box |
ユーザー |
|
提出日時 | 2020-06-24 10:42:34 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 23 ms / 2,000 ms |
コード長 | 4,969 bytes |
コンパイル時間 | 1,051 ms |
コンパイル使用メモリ | 117,188 KB |
実行使用メモリ | 8,064 KB |
最終ジャッジ日時 | 2024-07-03 20:02:53 |
合計ジャッジ時間 | 2,444 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 36 |
ソースコード
/*** author: otera**/#include<iostream>#include<string>#include<cstdio>#include<cstring>#include<vector>#include<cmath>#include<algorithm>#include<functional>#include<iomanip>#include<queue>#include<deque>#include<ciso646>#include<random>#include<map>#include<set>#include<complex>#include<bitset>#include<stack>#include<unordered_map>#include<utility>#include<cassert>using namespace std;//#define int long longtypedef long long ll;typedef unsigned long long ul;typedef unsigned int ui;typedef long double ld;const int inf=1e9+7;const ll INF=1LL<<60 ;const ll mod=1e9+7 ;#define rep(i,n) for(int i=0;i<n;i++)#define per(i,n) for(int i=n-1;i>=0;i--)#define Rep(i,sta,n) for(int i=sta;i<n;i++)#define rep1(i,n) for(int i=1;i<=n;i++)#define per1(i,n) for(int i=n;i>=1;i--)#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)typedef complex<ld> Point;const ld eps = 1e-8;const ld pi = acos(-1.0);typedef pair<int, int> P;typedef pair<ld, ld> LDP;typedef pair<ll, ll> LP;#define fr first#define sc second#define all(c) c.begin(),c.end()#define pb push_back#define debug(x) cerr << #x << " = " << (x) << endl;template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }// modint: mod 計算を int を扱うように扱える構造体template<int MOD> struct Fp {long long val;constexpr Fp(long long v = 0) noexcept : val(v % MOD) {if (val < 0) val += MOD;}constexpr int getmod() { return MOD; }constexpr Fp operator - () const noexcept {return val ? MOD - val : 0;}constexpr Fp operator + (const Fp& r) const noexcept { return Fp(*this) += r; }constexpr Fp operator - (const Fp& r) const noexcept { return Fp(*this) -= r; }constexpr Fp operator * (const Fp& r) const noexcept { return Fp(*this) *= r; }constexpr Fp operator / (const Fp& r) const noexcept { return Fp(*this) /= r; }constexpr Fp& operator += (const Fp& r) noexcept {val += r.val;if (val >= MOD) val -= MOD;return *this;}constexpr Fp& operator -= (const Fp& r) noexcept {val -= r.val;if (val < 0) val += MOD;return *this;}constexpr Fp& operator *= (const Fp& r) noexcept {val = val * r.val % MOD;return *this;}constexpr Fp& operator /= (const Fp& r) noexcept {long long a = r.val, b = MOD, u = 1, v = 0;while (b) {long long t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}val = val * u % MOD;if (val < 0) val += MOD;return *this;}constexpr bool operator == (const Fp& r) const noexcept {return this->val == r.val;}constexpr bool operator != (const Fp& r) const noexcept {return this->val != r.val;}friend constexpr ostream& operator << (ostream &os, const Fp<MOD>& x) noexcept {return os << x.val;}friend constexpr istream& operator >> (istream &is, Fp<MOD>& x) noexcept {return is >> x.val;}friend constexpr Fp<MOD> modpow(const Fp<MOD> &a, long long n) noexcept {if (n == 0) return 1;auto t = modpow(a, n / 2);t = t * t;if (n & 1) t = t * a;return t;}};// 二項係数ライブラリtemplate<class T> struct BiCoef {vector<T> fact_, inv_, finv_;constexpr BiCoef() {}constexpr BiCoef(int n) noexcept : fact_(n, 1), inv_(n, 1), finv_(n, 1) {init(n);}constexpr void init(int n) noexcept {fact_.assign(n, 1), inv_.assign(n, 1), finv_.assign(n, 1);int MOD = fact_[0].getmod();for(int i = 2; i < n; i++){fact_[i] = fact_[i-1] * i;inv_[i] = -inv_[MOD%i] * (MOD/i);finv_[i] = finv_[i-1] * inv_[i];}}constexpr T com(int n, int k) const noexcept {if (n < k || n < 0 || k < 0) return 0;return fact_[n] * finv_[k] * finv_[n-k];}constexpr T fact(int n) const noexcept {if (n < 0) return 0;return fact_[n];}constexpr T inv(int n) const noexcept {if (n < 0) return 0;return inv_[n];}constexpr T finv(int n) const noexcept {if (n < 0) return 0;return finv_[n];}};const int MOD = 1000000007;//const int MOD = 998244353;using mint = Fp<MOD>;BiCoef<mint> bc;void solve() {int n, m; cin >> n >> m;mint ans = 0;bc.init(200200);for(int i = m; i >= 1; -- i) {if(i % 2 == m % 2) ans += bc.com(m, i) * modpow((mint)i, n);else ans -= bc.com(m, i) * modpow((mint)i, n);}cout << ans << endl;}signed main() {ios::sync_with_stdio(false);cin.tie(0);//cout << fixed << setprecision(10);//int t; cin >> t; rep(i, t)solve();solve();return 0;}