結果

問題 No.1095 Smallest Kadomatsu Subsequence
ユーザー uzzy
提出日時 2020-06-26 22:06:25
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
CE  
(最新)
AC  
(最初)
実行時間 -
コード長 1,438 bytes
コンパイル時間 2,637 ms
コンパイル使用メモリ 180,424 KB
最終ジャッジ日時 2025-03-14 16:47:04
合計ジャッジ時間 4,556 ms
ジャッジサーバーID
(参考情報)
judge1 / judge2
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ただし、clay言語の場合は開発者のデバッグのため、公開されます。

コンパイルメッセージ
In file included from /usr/include/c++/13/string:43,
                 from /usr/include/c++/13/bitset:52,
                 from /usr/include/x86_64-linux-gnu/c++/13/bits/stdc++.h:52,
                 from main.cpp:3:
/usr/include/c++/13/bits/allocator.h: In destructor ‘std::_Rb_tree<int, int, std::_Identity<int>, std::less<int>, std::allocator<int> >::_Rb_tree_impl<std::less<int>, true>::~_Rb_tree_impl()’:
/usr/include/c++/13/bits/allocator.h:184:7: error: inlining failed in call to ‘always_inline’ ‘std::allocator< <template-parameter-1-1> >::~allocator() noexcept [with _Tp = std::_Rb_tree_node<int>]’: target specific option mismatch
  184 |       ~allocator() _GLIBCXX_NOTHROW { }
      |       ^
In file included from /usr/include/c++/13/map:62,
                 from /usr/include/x86_64-linux-gnu/c++/13/bits/stdc++.h:152:
/usr/include/c++/13/bits/stl_tree.h:662:16: note: called from here
  662 |         struct _Rb_tree_impl
      |                ^~~~~~~~~~~~~

ソースコード

diff #
プレゼンテーションモードにする

#pragma GCC optimize ("O2")
#pragma GCC target ("avx2")
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define rep(i, n) for(int i = 0; i < (n); i++)
#define rep1(i, n) for(int i = 1; i <= (n); i++)
#define co(x) cout << (x) << "\n"
#define cosp(x) cout << (x) << " "
#define ce(x) cerr << (x) << "\n"
#define cesp(x) cerr << (x) << " "
#define pb push_back
#define mp make_pair
#define chmin(x, y) x = min(x, y)
#define chmax(x, y) x = max(x, y)
#define Would
#define you
#define please
int main() {
cin.tie(0);
ios::sync_with_stdio(false);
int N;
cin >> N;
int A[200200];
rep(i, N) cin >> A[i];
int L[200200], R[200200];
int saishou = 1e9;
rep(i, N) {
chmin(saishou, A[i]);
L[i] = saishou;
}
saishou = 1e9;
for (int i = N - 1; i >= 0; i--) {
chmin(saishou, A[i]);
R[i] = saishou;
}
int kotae = 1e9;
rep1(i, N - 2) {
if (A[i] > L[i - 1] && A[i] > R[i + 1]) {
chmin(kotae, L[i - 1] + A[i] + R[i + 1]);
}
}
set<int> tmp;
rep1(i, N - 2) {
tmp.insert(A[i - 1]);
auto itr = tmp.lower_bound(A[i]);
if (itr != tmp.end()) {
L[i] = *itr;
}
else {
L[i] = 6e8;
}
}
tmp.clear();
for (int i = N - 2; i > 0; i--) {
tmp.insert(A[i + 1]);
auto itr = tmp.lower_bound(A[i]);
if (itr != tmp.end()) {
R[i] = *itr;
}
else {
R[i] = 6e8;
}
chmin(kotae, L[i] + R[i] + A[i]);
}
if (kotae > 5e8) {
co(-1);
}
else co(kotae);
Would you please return 0;
}
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