結果
| 問題 |
No.1142 XOR と XOR
|
| コンテスト | |
| ユーザー |
👑 null
|
| 提出日時 | 2020-06-27 01:39:10 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 4,871 bytes |
| コンパイル時間 | 1,678 ms |
| コンパイル使用メモリ | 141,144 KB |
| 最終ジャッジ日時 | 2025-01-11 12:29:18 |
|
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 WA * 1 RE * 1 |
| other | AC * 3 WA * 2 RE * 20 |
コンパイルメッセージ
main.cpp: In function ‘void scans(std::string&)’:
main.cpp:80:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
80 | scanf("%c", &c);
| ~~~~~^~~~~~~~~~
main.cpp:81:28: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
81 | if (c == '\n')scanf("%c", &c);
| ~~~~~^~~~~~~~~~
main.cpp:84:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
84 | scanf("%c", &c);
| ~~~~~^~~~~~~~~~
main.cpp: In function ‘void scanc(char&)’:
main.cpp:90:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
90 | scanf("%c", &c);
| ~~~~~^~~~~~~~~~
main.cpp:93:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
93 | scanf("%c", &c);
| ~~~~~^~~~~~~~~~
main.cpp: In function ‘int main()’:
main.cpp:183:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
183 | scanf("%d%d%d", &n, &m, &k);
| ~~~~~^~~~~~~~~~~~~~~~~~~~~~
main.cpp:185:23: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
185 | rep(i, n)scanf("%d", &a[i]);
| ~~~~~^~~~~~~~~~~~~
main.cpp:186:23: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
186 | rep(i, m)scanf("%d", &b[i]);
| ~~~~~^~~~~~~~~~
ソースコード
/*
このコード、と~おれ!
Be accepted!
∧_∧
(。・ω・。)つ━☆・*。
⊂ ノ ・゜+.
しーJ °。+ *´¨)
.· ´¸.·*´¨) ¸.·*¨)
(¸.·´ (¸.·'* ☆
*/
#include <cstdio>
#include <algorithm>
#include <string>
#include <cmath>
#include <cstring>
#include <vector>
#include <numeric>
#include <iostream>
#include <random>
#include <map>
#include <unordered_map>
#include <queue>
#include <regex>
#include <functional>
#include <complex>
#include <list>
#include <cassert>
#include <iomanip>
#include <set>
#include <stack>
#include <bitset>
////多倍長整数, cpp_intで宣言
//#include <boost/multiprecision/cpp_int.hpp>
//using namespace boost::multiprecision;
#pragma gcc target ("avx2")
#pragma gcc optimization ("Ofast")
#pragma gcc optimization ("unroll-loops")
#define rep(i, n) for(int i = 0; i < (n); ++i)
#define rep1(i, n) for(int i = 1; i <= (n); ++i)
#define rep2(i, n) for(int i = 2; i < (n); ++i)
#define repr(i, n) for(int i = n; i >= 0; --i)
#define reprm(i, n) for(int i = n - 1; i >= 0; --i)
#define printynl(a) printf(a ? "yes\n" : "no\n")
#define printyn(a) printf(a ? "Yes\n" : "No\n")
#define printYN(a) printf(a ? "YES\n" : "NO\n")
#define printim(a) printf(a ? "possible\n" : "imposible\n")
#define printdb(a) printf("%.50lf\n", a) //少数出力
#define printLdb(a) printf("%.50Lf\n", a) //少数出力
#define printdbd(a) printf("%.16lf\n", a) //少数出力(桁少なめ)
#define prints(s) printf("%s\n", s.c_str()) //string出力
#define all(x) (x).begin(), (x).end()
#define allsum(a, b, c) ((a + b) * c / 2LL) //等差数列の和、初項,末項,項数
#define pb push_back
#define rpriq priq<int, vector<int>, greater<int>>
#define deg_to_rad(deg) (((deg)/360.0L)*2.0L*PI)
#define rad_to_deg(rad) (((rad)/2.0L/PI)*360.0L)
#define Please return
#define AC 0
#define manhattan_dist(a, b, c, d) (abs(a - c) + abs(b - d)) /*(a, b) から (c, d) のマンハッタン距離 */
#define inf numeric_limits<double>::infinity();
#define linf numeric_limits<long double>::infinity()
using ll = long long;
constexpr int INF = 1073741823;
constexpr int MINF = -1073741823;
constexpr ll LINF = ll(4661686018427387903);
constexpr ll MOD = 1e9 + 7;
constexpr long double eps = 1e-6;
const long double PI = acosl(-1.0L);
using namespace std;
void scans(string& str) {
char c;
str = "";
scanf("%c", &c);
if (c == '\n')scanf("%c", &c);
while (c != '\n' && c != -1 && c != ' ') {
str += c;
scanf("%c", &c);
}
}
void scanc(char& str) {
char c;
scanf("%c", &c);
if (c == -1)return;
while (c == '\n') {
scanf("%c", &c);
}
str = c;
}
double acot(double x) {
return PI / 2 - atan(x);
}
ll LSB(ll n) { return (n & (-n)); }
/*-----------------------------------------ここからコード-----------------------------------------*/
/*
* @title modint
* @docs kyopro/docs/modint.md
*/
template<int mod>
struct modint {
int val;
modint() : val(0) {};
modint(ll x) : val(x >= 0 ? x % mod : (mod + x % mod) % mod) {};
modint& operator=(const modint& x) {
val = x.val;
return *this;
}
modint& operator+=(const modint& x) {
val += x.val;
if (val >= mod)val -= mod;
return *this;
}
modint& operator-=(const modint& x) {
val += mod - x.val;
if (val >= mod)val -= mod;
return *this;
}
modint& operator*=(const modint& x) {
val = (int)((ll)val * (ll)x.val % mod);
return *this;
}
modint& operator/=(const modint& x) {
int a = x.val, b = mod, u = 1, v = 0, t;
while (b > 0) {
t = a / b;
swap(a -= t * b, b);
swap(u -= t * v, v);
}
*this *= modint(u);
return *this;
}
modint operator+(const modint& x) const {
return (modint(*this) += x);
}
modint operator-(const modint& x) const {
return (modint(*this) -= x);
}
modint operator*(const modint& x) const {
return (modint(*this) *= x);
}
modint operator/(const modint& x) const {
return (modint(*this) /= x);
}
modint pow(ll n) {
modint ret(1), a(val);
while (n > 0) {
if (n % 2) ret *= a;
a *= a;
n /= 2;
}
return ret;
}
static int getmod() { return mod; };
};
int main() {
int n, m, k;
scanf("%d%d%d", &n, &m, &k);
vector<int> a(n), b(m), c(n + 1), d(m + 1);
rep(i, n)scanf("%d", &a[i]);
rep(i, m)scanf("%d", &b[i]);
rep(i, n)c[i + 1] = c[i] xor a[i];
rep(i, m)d[i + 1] = d[i] xor b[i];
vector<vector<modint<MOD>>> dp1(3, vector<modint<MOD>>(128)), dp2(3, vector<modint<MOD>>(128));
++n, ++m;
rep(i, n) {
dp1[0][c[i]] = 1;
rep(j, 2) {
rep(k, 128) {
dp1[2 - j][c[i] xor k] += dp1[1 - j][k];
}
}
}
rep(i, m) {
dp2[0][d[i]] = 1;
rep(j, 2) {
rep(k, 128) {
dp2[2 - j][d[i] xor k] += dp2[1 - j][k];
}
}
}
modint<MOD> ans = 0;
rep(i, 128) {
ans += dp1[2][i] * dp2[2][i xor k];
}
printf("%d\n", ans.val);
Please AC;
}
null