結果

問題 No.546 オンリー・ワン
ユーザー nanophoto12
提出日時 2020-06-28 21:08:44
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 2 ms / 2,000 ms
コード長 2,147 bytes
コンパイル時間 1,921 ms
コンパイル使用メモリ 197,744 KB
最終ジャッジ日時 2025-01-11 13:27:30
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 7
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#define M_PI 3.14159265358979323846 // pi
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef vector<ll> VI;
typedef pair<ll, ll> P;
typedef tuple<ll, ll, ll> t3;
typedef tuple<ll, ll, ll, ll> t4;
typedef tuple<ll, ll, ll, ll, ll> t5;
#define rep(a,n) for(ll a = 0;a < n;a++)
#define repi(a,b,n) for(ll a = b;a < n;a++)
using namespace std;
static const ll INF = 1e15;
const ll mod = 1000000007;
ll mpow(ll x, ll n) {
ll ans = 1; x %= mod;
while (n != 0) {
if (n & 1) ans = ans * x % mod;
x = x * x % mod;
n = n >> 1;
}
return ans;
}
ll inv_mod(ll a) { return mpow(a, mod - 2); }
class Factorial {
private:
vector<ll> fac;
vector<ll> ifac;
public:
Factorial(ll N) {
fac.push_back(1);
for (int i = 0; i < N; i++) fac.push_back(fac[i] * (i + 1) % mod);
ifac.resize(N + 1);
ifac[N] = inv_mod(fac[N]);
for (int i = 0; i < N; i++) ifac[N - 1 - i] = (ifac[N - i] * (N - i)) % mod;
}
ll fact(ll a) { return fac[a]; }
ll ifact(ll a) { return ifac[a]; }
ll cmb(ll a, ll b) {
if (a == 0 && b == 0) return 1;
if (a < b || a < 0 || b < 0) return 0;
ll tmp = ifact(a - b) * ifact(b) % mod;
return tmp * fac[a] % mod;
}
ll per(ll a, ll b) {
if (a == 0 && b == 0) return 1;
if (a < b || a < 0 || b < 0) return 0;
return fac[a] * ifac[a - b] % mod;
}
};
ll gcd(ll a, ll b) { while (b) a %= b, swap(a, b); return abs(a); }
ll lcm(ll a, ll b) { return a / gcd(a, b) * b; }
int main() {
ll n, l, h;
cin >> n >> l >> h;
vector<ll> cs(n);
rep(i, n) cin >> cs[i];
vector<ll> state(1 << n, 0);
rep(i, 1LL << n) {
ll x = 1;
rep(j, n) {
if (i & (1LL << j)) {
x = lcm(x, cs[j]);
if (x > h) break;
}
}
if (x > h) continue;
ll div = h / x - (l - 1) / x;
state[i] = div;
}
//1
//1 +
//12, 1 3, ..., 1n-1 -
//123, 1 3 4, ..., +
//1,2,3__builtin_popcountll
ll sum = 0;
rep(i, 1LL << n) {
auto p = __builtin_popcountll(i);
ll s = p % 2 == 1 ? 1 : -1;
sum += s * state[i] * p;
}
cout << sum << endl;
return 0;
}
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