結果
問題 | No.1102 Remnants |
ユーザー | nehan_der_thal |
提出日時 | 2020-07-03 21:44:21 |
言語 | PyPy3 (7.3.15) |
結果 |
TLE
|
実行時間 | - |
コード長 | 2,258 bytes |
コンパイル時間 | 139 ms |
コンパイル使用メモリ | 82,284 KB |
実行使用メモリ | 124,624 KB |
最終ジャッジ日時 | 2024-09-16 23:50:50 |
合計ジャッジ時間 | 5,773 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 338 ms
100,740 KB |
testcase_01 | AC | 337 ms
93,652 KB |
testcase_02 | AC | 338 ms
93,648 KB |
testcase_03 | AC | 339 ms
93,672 KB |
testcase_04 | AC | 336 ms
93,680 KB |
testcase_05 | TLE | - |
testcase_06 | -- | - |
testcase_07 | -- | - |
testcase_08 | -- | - |
testcase_09 | -- | - |
testcase_10 | -- | - |
testcase_11 | -- | - |
testcase_12 | -- | - |
testcase_13 | -- | - |
testcase_14 | -- | - |
testcase_15 | -- | - |
testcase_16 | -- | - |
testcase_17 | -- | - |
testcase_18 | -- | - |
testcase_19 | -- | - |
testcase_20 | -- | - |
testcase_21 | -- | - |
testcase_22 | -- | - |
testcase_23 | -- | - |
testcase_24 | -- | - |
testcase_25 | -- | - |
testcase_26 | -- | - |
testcase_27 | -- | - |
ソースコード
k = 72 kk = k // 4 K = 1<<k nu = lambda L: int("".join([hex(K+a)[3:] for a in L[::-1]]), 16) st = lambda n: hex(n)[2:] li = lambda s, l, r: [int(a, 16) % P if len(a) else 0 for a in [s[-(i+1)*kk:-i*kk] for i in range(l, r)]] def grow(d, v, h): h += [0] * d f = [(-1 if (i+d) % 2 else 1) * fainv[i] * fainv[d-i] % P * h[i] % P for i in range(d+1)] nuf = nu(f) a = d * inv[v] % P t = [1] * (3*d+3) for i in range(1, 3*d+3): t[i] = t[i-1] * (a - d + i - 1) % P ti = [1] * (3*d+3) ti[-1] = pow(t[-1], P-2, P) for i in range(1, 3*d+3)[::-1]: ti[i-1] = ti[i] * (a - d + i - 1) % P iv = [1] * (3*d+3) for i in range(1, 3*d+3): iv[i] = ti[i] * t[i-1] % P ### g = [inv[i] for i in range(1, 2*d+2)] fg = li(st(nuf * nu(g)), d, d * 2 + 1) for i in range(d): h[i+d+1] = fg[i] * fa[d+i+1] % P * fainv[i] % P ### g = [iv[i] for i in range(1, 2*d+2)] fg = li(st(nuf * nu(g)), d, d * 2 + 1) for i in range(d+1): h[i] = h[i] * (fg[i] * t[d+i+1] % P * ti[i] % P) % P ### g = [iv[i] for i in range(d+2, 3*d+3)] fg = li(st(nuf * nu(g)), d, d * 2 + 1) for i in range(d): h[i+d+1] = h[i+d+1] * (fg[i] * t[2*d+i+2] % P * ti[d+i+1] % P) % P return h # Create a table of the factorial of the first v+2 multiples of v, i.e., [0!, v!, 2v!, ..., (v(v+1))!] def create_table(v): s = 1 X = [1, v+1] while s < v: X = grow(s, v, X) s *= 2 table = [1] for x in X: table.append(table[-1] * x % P) return table def fact(i, table): a = table[i//v] for j in range(i//v*v+1, i+1): a = a * j % P return a P = 10**9+7 N = 10**8 v = 1 << (N.bit_length() + 1) // 2 fa = [1] * (2*v+2) fainv = [1] * (2*v+2) for i in range(2*v+1): fa[i+1] = fa[i] * (i+1) % P fainv[-1] = pow(fa[-1], P-2, P) for i in range(2*v+1)[::-1]: fainv[i] = fainv[i+1] * (i+1) % P inv = [0] * (2*v+2) for i in range(1, 2*v+2): inv[i] = fainv[i] * fa[i-1] % P T = create_table(v) C = lambda n, k: fact(n, T) * pow(fact(k, T) * fact(n-k, T), P-2, P) % P N, M = map(int, input().split()) X = list(map(int, input().split())) R = 0 for i in range(N): R = (R + X[i]*C(i+M, i)*C(N-i+M-1, N-i-1)) % P print(R)