結果
問題 | No.1103 Directed Length Sum |
ユーザー | hamath |
提出日時 | 2020-07-03 22:57:47 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 1,837 ms / 3,000 ms |
コード長 | 5,608 bytes |
コンパイル時間 | 2,559 ms |
コンパイル使用メモリ | 232,980 KB |
実行使用メモリ | 123,832 KB |
最終ジャッジ日時 | 2024-09-17 04:39:08 |
合計ジャッジ時間 | 16,858 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,816 KB |
testcase_01 | AC | 2 ms
6,940 KB |
testcase_02 | AC | 691 ms
123,832 KB |
testcase_03 | AC | 580 ms
73,432 KB |
testcase_04 | AC | 961 ms
51,696 KB |
testcase_05 | AC | 1,837 ms
86,976 KB |
testcase_06 | AC | 486 ms
34,772 KB |
testcase_07 | AC | 81 ms
10,880 KB |
testcase_08 | AC | 132 ms
14,872 KB |
testcase_09 | AC | 47 ms
7,936 KB |
testcase_10 | AC | 208 ms
19,164 KB |
testcase_11 | AC | 1,009 ms
55,944 KB |
testcase_12 | AC | 558 ms
35,100 KB |
testcase_13 | AC | 219 ms
19,580 KB |
testcase_14 | AC | 34 ms
6,944 KB |
testcase_15 | AC | 355 ms
28,056 KB |
testcase_16 | AC | 1,152 ms
62,468 KB |
testcase_17 | AC | 1,239 ms
65,164 KB |
testcase_18 | AC | 243 ms
19,044 KB |
testcase_19 | AC | 1,095 ms
57,176 KB |
testcase_20 | AC | 60 ms
8,960 KB |
testcase_21 | AC | 123 ms
13,752 KB |
testcase_22 | AC | 865 ms
47,312 KB |
testcase_23 | AC | 436 ms
29,936 KB |
ソースコード
#ifdef LOCAL //#define _GLIBCXX_DEBUG #endif //#pragma GCC target("avx512f,avx512dq,avx512cd,avx512bw,avx512vl") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<ll, ll> P; typedef pair<int, int> Pi; typedef vector<ll> Vec; typedef vector<int> Vi; typedef vector<string> Vs; typedef vector<char> Vc; typedef vector<P> VP; typedef vector<vector<ll>> VV; typedef vector<vector<int>> VVi; typedef vector<vector<char>> VVc; typedef vector<vector<vector<ll>>> VVV; typedef vector<vector<vector<vector<ll>>>> VVVV; #define REP(i, a, b) for(ll i=(a); i<(b); i++) #define PER(i, a, b) for(ll i=(a); i>=(b); i--) #define rep(i, n) REP(i, 0, n) #define per(i, n) PER(i, n, 0) const ll INF=1e18+18; const ll MOD=1000000007; #define Yes(n) cout << ((n) ? "Yes" : "No") << endl; #define YES(n) cout << ((n) ? "YES" : "NO") << endl; #define ALL(v) v.begin(), v.end() #define rALL(v) v.rbegin(), v.rend() #define pb(x) push_back(x) #define mp(a, b) make_pair(a,b) #define Each(a,b) for(auto &a :b) #define rEach(i, mp) for (auto i = mp.rbegin(); i != mp.rend(); ++i) #ifdef LOCAL #define dbg(x_) cerr << #x_ << ":" << x_ << endl; #define dbgmap(mp) cerr << #mp << ":"<<endl; for (auto i = mp.begin(); i != mp.end(); ++i) { cerr << i->first <<":"<<i->second << endl;} #define dbgset(st) cerr << #st << ":"<<endl; for (auto i = st.begin(); i != st.end(); ++i) { cerr << *i <<" ";}cerr<<endl; #define dbgarr(n,m,arr) rep(i,n){rep(j,m){cerr<<arr[i][j]<<" ";}cerr<<endl;} #define dbgdp(n,arr) rep(i,n){cerr<<arr[i]<<" ";}cerr<<endl; #define dbgmint(n,arr) rep(i,n){cerr<<arr[i].x<<" ";}cerr<<endl; #define dbgarrmint(n,m,arr) rep(i,n){rep(j,m){cerr<<arr[i][j].x<<" ";}cerr<<endl;} #else #define dbg(...) #define dbgmap(...) #define dbgset(...) #define dbgarr(...) #define dbgdp(...) #define dbgmint(...) #define dbgarrmint(...) #endif #define out(a) cout<<a<<endl #define out2(a,b) cout<<a<<" "<<b<<endl #define vout(v) rep(i,v.size()){cout<<v[i]<<" ";}cout<<endl #define Uniq(v) v.erase(unique(v.begin(), v.end()), v.end()) #define fi first #define se second template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; } template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; } template<typename T1, typename T2> ostream &operator<<(ostream &s, const pair<T1, T2> &p) { return s<<"("<<p.first<<", "<<p.second<<")"; } template<typename T>istream& operator>>(istream&i,vector<T>&v) {rep(j,v.size())i>>v[j];return i;} // vector template<typename T> ostream &operator<<(ostream &s, const vector<T> &v) { int len=v.size(); for(int i=0; i<len; ++i) { s<<v[i]; if(i<len-1) s<<" "; } return s; } // 2 dimentional vector template<typename T> ostream &operator<<(ostream &s, const vector<vector<T> > &vv) { int len=vv.size(); for(int i=0; i<len; ++i) { s<<vv[i]<<endl; } return s; } //mint struct mint { ll x; // typedef long long ll; mint(ll x=0):x((x%MOD+MOD)%MOD){} mint operator-() const { return mint(-x);} mint& operator+=(const mint a) { if ((x += a.x) >= MOD) x -= MOD; return *this; } mint& operator-=(const mint a) { if ((x += MOD-a.x) >= MOD) x -= MOD; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= MOD; return *this;} mint operator+(const mint a) const { return mint(*this) += a;} mint operator-(const mint a) const { return mint(*this) -= a;} mint operator*(const mint a) const { return mint(*this) *= a;} mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } // for prime MOD mint inv() const { return pow(MOD-2);} mint& operator/=(const mint a) { return *this *= a.inv();} mint operator/(const mint a) const { return mint(*this) /= a;} }; istream& operator>>(istream& is, const mint& a) { return is >> a.x;} ostream& operator<<(ostream& os, const mint& a) { return os << a.x;} typedef vector<mint> Vmint; struct combination { vector<mint> fact, ifact; combination(int n):fact(n+1),ifact(n+1) { assert(n < MOD); fact[0] = 1; for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i; ifact[n] = fact[n].inv(); for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i; } mint operator()(int n, int k) { if (k < 0 || k > n) return 0; return fact[n]*ifact[k]*ifact[n-k]; } }; int solve(){ ll n; cin>>n; VV g(n); set<ll> st; rep(i,n){ st.insert(i); } rep(i,n-1){ ll u,v; cin>>u>>v; u--;v--; g[u].pb(v); st.erase(v); } //dbgset(st); dbg(g); ll root = *st.begin(); mint ans = 0; Vec sz(n); Vmint dp(n); auto dfs = [&](auto dfs, ll v, ll p)->ll { ll node = 1; Each(x, g[v]) { if(x != p) { node += dfs(dfs, x, v); } } return sz[v] = node; }; dfs(dfs, root, -1); dbg(sz) auto dfs2 = [&](auto dfs2, ll v, ll p)->mint { dp[v] = sz[v]-1; dbg(mp(v,dp[v])); Each(x, g[v]) { if(x != p) { dp[v] += dfs2(dfs2, x, v); } } return dp[v]; }; dfs2(dfs2, root, -1); dbg(dp) rep(i,n) ans += dp[i]; cout<<ans<<endl; return 0; } int main() { cin.tie(0); ios::sync_with_stdio(false); cout<<std::setprecision(10); solve(); }