結果
問題 | No.1004 サイコロの実装 (2) |
ユーザー | stoq |
提出日時 | 2020-07-06 08:20:05 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,881 bytes |
コンパイル時間 | 2,102 ms |
コンパイル使用メモリ | 201,064 KB |
実行使用メモリ | 13,760 KB |
最終ジャッジ日時 | 2024-09-24 17:09:18 |
合計ジャッジ時間 | 6,229 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
13,760 KB |
testcase_01 | AC | 2 ms
6,940 KB |
testcase_02 | AC | 2 ms
6,940 KB |
testcase_03 | AC | 2 ms
6,944 KB |
testcase_04 | AC | 2 ms
6,944 KB |
testcase_05 | AC | 2 ms
6,940 KB |
testcase_06 | AC | 2 ms
6,944 KB |
testcase_07 | AC | 2 ms
6,940 KB |
testcase_08 | AC | 2 ms
6,944 KB |
testcase_09 | AC | 2 ms
6,940 KB |
testcase_10 | WA | - |
testcase_11 | AC | 2 ms
6,940 KB |
testcase_12 | AC | 2 ms
6,940 KB |
testcase_13 | AC | 2 ms
6,940 KB |
testcase_14 | AC | 1 ms
6,940 KB |
testcase_15 | AC | 1 ms
6,940 KB |
testcase_16 | WA | - |
testcase_17 | AC | 2 ms
6,940 KB |
testcase_18 | AC | 2 ms
6,940 KB |
testcase_19 | WA | - |
testcase_20 | AC | 2 ms
6,944 KB |
testcase_21 | AC | 3 ms
6,940 KB |
testcase_22 | AC | 2 ms
6,940 KB |
testcase_23 | AC | 2 ms
6,944 KB |
testcase_24 | WA | - |
testcase_25 | WA | - |
testcase_26 | TLE | - |
testcase_27 | -- | - |
testcase_28 | -- | - |
testcase_29 | -- | - |
testcase_30 | -- | - |
testcase_31 | -- | - |
testcase_32 | -- | - |
testcase_33 | -- | - |
testcase_34 | -- | - |
testcase_35 | -- | - |
testcase_36 | -- | - |
testcase_37 | -- | - |
testcase_38 | -- | - |
testcase_39 | -- | - |
ソースコード
#define MOD_TYPE 1 #pragma region Macros #include <bits/stdc++.h> using namespace std; /* #include <boost/multiprecision/cpp_int.hpp> #include <boost/multiprecision/cpp_dec_float.hpp> using multiInt = boost::multiprecision::cpp_int; using lld = boost::multiprecision::cpp_dec_float_100; */ /* #pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") */ using ll = long long int; using ld = long double; using pii = pair<int, int>; using pll = pair<ll, ll>; using pld = pair<ld, ld>; template <typename Q_type> using smaller_queue = priority_queue<Q_type, vector<Q_type>, greater<Q_type>>; constexpr ll MOD = (MOD_TYPE == 1 ? (ll)(1e9 + 7) : 998244353); //constexpr ll MOD = 1; constexpr int INF = (int)1e9 + 10; constexpr ll LINF = (ll)4e18; constexpr double PI = acos(-1.0); constexpr double EPS = 1e-11; constexpr int Dx[] = {0, 0, -1, 1, -1, 1, -1, 1, 0}; constexpr int Dy[] = {1, -1, 0, 0, -1, -1, 1, 1, 0}; #define REP(i, m, n) for (ll i = m; i < (ll)(n); ++i) #define rep(i, n) REP(i, 0, n) #define REPI(i, m, n) for (int i = m; i < (int)(n); ++i) #define repi(i, n) REPI(i, 0, n) #define MP make_pair #define MT make_tuple #define YES(n) cout << ((n) ? "YES" : "NO") << "\n" #define Yes(n) cout << ((n) ? "Yes" : "No") << "\n" #define possible(n) cout << ((n) ? "possible" : "impossible") << "\n" #define Possible(n) cout << ((n) ? "Possible" : "Impossible") << "\n" #define Yay(n) cout << ((n) ? "Yay!" : ":(") << "\n" #define all(v) v.begin(), v.end() #define NP(v) next_permutation(all(v)) #define dbg(x) cerr << #x << ":" << x << "\n"; inline void init_main() { cin.tie(0); ios::sync_with_stdio(false); cout << setprecision(30) << setiosflags(ios::fixed); } template <typename T> inline bool chmin(T &a, T b) { if (a > b) { a = b; return true; } return false; } template <typename T> inline bool chmax(T &a, T b) { if (a < b) { a = b; return true; } return false; } inline ll CEIL(ll a, ll b) { return (a + b - 1) / b; } template <typename A, size_t N, typename T> inline void Fill(A (&array)[N], const T &val) { fill((T *)array, (T *)(array + N), val); } template <typename T, typename U> constexpr istream &operator>>(istream &is, pair<T, U> &p) noexcept { is >> p.first >> p.second; return is; } template <typename T, typename U> constexpr ostream &operator<<(ostream &os, pair<T, U> &p) noexcept { os << p.first << " " << p.second; return os; } #pragma endregion ll a, b, x; const ll m = 1LL << 32; ll f() { x = (a * x + b) % m; return x % 6 + 1; } void solve() { int n; cin >> a >> b >> x >> n; ll cnt1[2] = {}, cnt2[2] = {}; ll now1 = 0, now2 = 0; rep(i, n) { now1 += f(); cnt1[now1 % 2]++; now2 += f(); cnt2[now2 % 2]++; } cout << min(cnt1[0], cnt1[1]) << " " << min(cnt2[0], cnt2[1]) << "\n"; } int main() { init_main(); solve(); }