結果
問題 | No.1016 三目並べ |
ユーザー | stoq |
提出日時 | 2020-07-10 07:59:54 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 3,375 bytes |
コンパイル時間 | 5,205 ms |
コンパイル使用メモリ | 413,252 KB |
実行使用メモリ | 6,820 KB |
最終ジャッジ日時 | 2024-10-09 16:47:58 |
合計ジャッジ時間 | 5,821 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,816 KB |
testcase_01 | AC | 1 ms
6,820 KB |
testcase_02 | AC | 2 ms
6,816 KB |
testcase_03 | AC | 2 ms
6,820 KB |
testcase_04 | AC | 2 ms
6,816 KB |
testcase_05 | AC | 2 ms
6,816 KB |
testcase_06 | AC | 2 ms
6,820 KB |
testcase_07 | WA | - |
testcase_08 | WA | - |
testcase_09 | WA | - |
testcase_10 | WA | - |
ソースコード
#define MOD_TYPE 1 #pragma region Macros #include <bits/stdc++.h> using namespace std; #include <boost/multiprecision/cpp_int.hpp> #include <boost/multiprecision/cpp_dec_float.hpp> using Int = boost::multiprecision::cpp_int; using lld = boost::multiprecision::cpp_dec_float_100; /* #pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") */ using ll = long long int; using ld = long double; using pii = pair<int, int>; using pll = pair<ll, ll>; using pld = pair<ld, ld>; template <typename Q_type> using smaller_queue = priority_queue<Q_type, vector<Q_type>, greater<Q_type>>; constexpr ll MOD = (MOD_TYPE == 1 ? (ll)(1e9 + 7) : 998244353); //constexpr ll MOD = 1; constexpr int INF = (int)1e9 + 10; constexpr ll LINF = (ll)4e18; constexpr double PI = acos(-1.0); constexpr double EPS = 1e-11; constexpr int Dx[] = {0, 0, -1, 1, -1, 1, -1, 1, 0}; constexpr int Dy[] = {1, -1, 0, 0, -1, -1, 1, 1, 0}; #define REP(i, m, n) for (ll i = m; i < (ll)(n); ++i) #define rep(i, n) REP(i, 0, n) #define REPI(i, m, n) for (int i = m; i < (int)(n); ++i) #define repi(i, n) REPI(i, 0, n) #define MP make_pair #define MT make_tuple #define YES(n) cout << ((n) ? "YES" : "NO") << "\n" #define Yes(n) cout << ((n) ? "Yes" : "No") << "\n" #define possible(n) cout << ((n) ? "possible" : "impossible") << "\n" #define Possible(n) cout << ((n) ? "Possible" : "Impossible") << "\n" #define Yay(n) cout << ((n) ? "Yay!" : ":(") << "\n" #define all(v) v.begin(), v.end() #define NP(v) next_permutation(all(v)) #define dbg(x) cerr << #x << ":" << x << "\n"; inline void init_main() { cin.tie(0); ios::sync_with_stdio(false); cout << setprecision(30) << setiosflags(ios::fixed); } template <typename T> inline bool chmin(T &a, T b) { if (a > b) { a = b; return true; } return false; } template <typename T> inline bool chmax(T &a, T b) { if (a < b) { a = b; return true; } return false; } inline ll CEIL(ll a, ll b) { return (a + b - 1) / b; } template <typename A, size_t N, typename T> inline void Fill(A (&array)[N], const T &val) { fill((T *)array, (T *)(array + N), val); } template <typename T, typename U> constexpr istream &operator>>(istream &is, pair<T, U> &p) noexcept { is >> p.first >> p.second; return is; } template <typename T, typename U> constexpr ostream &operator<<(ostream &os, pair<T, U> &p) noexcept { os << p.first << " " << p.second; return os; } #pragma endregion void solve() { int n; cin >> n; string s; cin >> s; set<string> st = {"ooo", "oo-", "o-o", "-oo"}; rep(i, n - 2) { string t = s.substr(i, 3); if (st.count(t)) { cout << 'O' << "\n"; return; } } rep(i, n) { if (s[i] != '-') continue; s[i] = 'o'; int cnt = 0; for (int j = i - 2; j <= i + 2; j++) { if (j < 0 or j >= n or s[j] != '-') continue; bool b1 = j - 2 >= 0 and s[j - 2] == 'o' and s[j - 1] == 'o'; bool b2 = j - 1 >= 0 and j + 1 < n and s[j - 1] == 'o' and s[j + 1] == 'o'; bool b3 = j + 2 < n and s[j + 2] == 'o' and s[j + 1] == 'o'; if (b1 or b2 or b3) cnt++; } if (cnt >= 2) { cout << 'O' << "\n"; return; } s[i] = '-'; } cout << 'X' << "\n"; } int main() { init_main(); int testcase; cin >> testcase; rep(ti, testcase) { solve(); } }