結果

問題 No.1111 コード進行
ユーザー firiexpfiriexp
提出日時 2020-07-10 21:36:48
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 114 ms / 2,000 ms
コード長 3,135 bytes
コンパイル時間 1,143 ms
コンパイル使用メモリ 110,552 KB
最終ジャッジ日時 2025-01-11 18:06:03
ジャッジサーバーID
（参考情報） 		judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 48
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:68:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   68 |         scanf("%d %d %d", &a, &b, &c);
      |         ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~

ソースコード

diff # 

#include <iostream>
#include <algorithm>
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <numeric>
#include <bitset>
#include <cmath>

static const int MOD = 1000000007;
using ll = long long;
using u32 = unsigned;
using u64 = unsigned long long;
using namespace std;

template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;

template<u32 M = 1000000007>
struct modint{
    u32 val;
    modint(): val(0){}
    template<typename T>
    modint(T t){t %= (T)M; if(t < 0) t += (T)M; val = t;}

    modint pow(ll k) const {
        modint res(1), x(val);
        while(k){
            if(k&1) res *= x;
            x *= x;
            k >>= 1;
        }
        return res;
    }
    template<typename T>
    modint& operator=(T t){t %= (T)M; if(t < 0) t += (T)M; val = t; return *this;}
    modint inv() const {return pow(M-2);}
    modint& operator+=(modint a){val += a.val; if(val >= M) val -= M; return *this;}
    modint& operator-=(modint a){if(val < a.val) val += M-a.val; else val -= a.val; return *this;}
    modint& operator*=(modint a){val = (u64)val*a.val%M; return *this;}
    modint& operator/=(modint a){return (*this) *= a.inv();}
    modint operator+(modint a) const {return modint(val) +=a;}
    modint operator-(modint a) const {return modint(val) -=a;}
    modint operator*(modint a) const {return modint(val) *=a;}
    modint operator/(modint a) const {return modint(val) /=a;}
    modint operator-(){return modint(M-val);}
    bool operator==(const modint a) const {return val == a.val;}
    bool operator!=(const modint a) const {return val != a.val;}
    bool operator<(const modint a) const {return val < a.val;}
};
using mint = modint<MOD>;

template <class T, class U>
vector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }

template<class... Ts, class U>
auto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }

template<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }
template<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }

int main() {
    int n, m, k;
    cin >> n >> m >> k;
    vector<vector<pair<int, int>>> v(300);
    for (int i = 0; i < m; ++i) {
        int a, b, c;
        scanf("%d %d %d", &a, &b, &c);
        a--; b--;
        v[a].emplace_back(b, c);
    }
    auto dp = make_v(2, 300, k+1, mint(0));
    for (int i = 0; i < 300; ++i) {
        dp[1][i][0] = 1;
    }
    for (int i = 1; i < n; ++i) {
        int now = i&1, nxt = now^1;
        for (int j = 0; j < 300; ++j) {
            for (int l = 0; l <= k; ++l) {
                dp[nxt][j][l] = 0;
            }
        }
        for (int j = 0; j < 300; ++j) {
            for (int l = 0; l <= k; ++l) {
                for (auto &&e : v[j]) {
                    if(l+e.second <= k){
                        dp[nxt][e.first][l+e.second] += dp[now][j][l];
                    }
                }
            }
        }
    }
    mint ans = 0;
    for (int j = 0; j < 300; ++j) {
        ans += dp[n&1][j][k];
    }
    cout << ans.val << "\n";
    return 0;
}
0