結果

問題 No.1112 冥界の音楽
ユーザー Ricky_ponRicky_pon
提出日時 2020-07-11 10:38:44
言語 C++17
(gcc 13.2.0 + boost 1.83.0)
結果
CE  
(最新)
AC  
(最初)
実行時間 -
コード長 2,582 bytes
コンパイル時間 2,834 ms
コンパイル使用メモリ 208,584 KB
最終ジャッジ日時 2024-04-20 20:53:56
合計ジャッジ時間 3,193 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge3
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コンパイルメッセージ
In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc/13.2.0/include/c++/13/string:43,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/13.2.0/include/c++/13/bitset:52,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/13.2.0/include/c++/13/x86_64-pc-linux-gnu/bits/stdc++.h:52,
                 from main.cpp:4:
/home/linuxbrew/.linuxbrew/Cellar/gcc/13.2.0/include/c++/13/bits/allocator.h: In destructor 'std::_Rb_tree<std::pair<int, std::pair<int, int> >, std::pair<int, std::pair<int, int> >, std::_Identity<std::pair<int, std::pair<int, int> > >, std::less<std::pair<int, std::pair<int, int> > >, std::allocator<std::pair<int, std::pair<int, int> > > >::_Rb_tree_impl<std::less<std::pair<int, std::pair<int, int> > >, true>::~_Rb_tree_impl()':
/home/linuxbrew/.linuxbrew/Cellar/gcc/13.2.0/include/c++/13/bits/allocator.h:184:7: error: inlining failed in call to 'always_inline' 'std::allocator< <template-parameter-1-1> >::~allocator() noexcept [with _Tp = std::_Rb_tree_node<std::pair<int, std::pair<int, int> > >]': target specific option mismatch
  184 |       ~allocator() _GLIBCXX_NOTHROW { }
      |       ^
In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc/13.2.0/include/c++/13/map:62,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/13.2.0/include/c++/13/x86_64-pc-linux-gnu/bits/stdc++.h:152:
/home/linuxbrew/.linuxbrew/Cellar/gcc/13.2.0/include/c++/13/bits/stl_tree.h:662:16: note: called from here
  662 |         struct _Rb_tree_impl
      |                ^~~~~~~~~~~~~

ソースコード

diff # 

#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
#define For(i, a, b) for(int (i)=(int)(a); (i)<(int)(b); ++(i))
#define rFor(i, a, b) for(int (i)=(int)(a)-1; (i)>=(int)(b); --(i))
#define rep(i, n) For((i), 0, (n))
#define rrep(i, n) rFor((i), (n), 0)
#define fi first
#define se second
using namespace std;
typedef long long lint;
typedef unsigned long long ulint;
typedef pair<int, int> pii;
typedef pair<lint, lint> pll;
template<class T> bool chmax(T &a, const T &b){if(a<b){a=b; return true;} return false;}
template<class T> bool chmin(T &a, const T &b){if(a>b){a=b; return true;} return false;}
template<class T> T div_floor(T a, T b){
    if(b < 0) a *= -1, b *= -1;
    return a>=0 ? a/b : (a+1)/b-1;
}
template<class T> T div_ceil(T a, T b){
    if(b < 0) a *= -1, b *= -1;
    return a>0 ? (a-1)/b+1 : a/b;
}

constexpr lint mod = 1000000007;
//constexpr lint INF = mod * mod;
constexpr int MAX = 200010;

//using mat = vector<vector<mint>>;
using mat = array<array<int, 216>, 216>;
mat c;

void mul(mat a, mat b){
    int n = 216;
    rep(i, n)rep(j, n) c[i][j] = 0;
    lint tmp;
    rep(i, n){
        rep(k, n){
            rep(j, n){
                tmp = (lint)a[i][k] * b[k][j];
                if(tmp >= mod) tmp %= mod;
                c[i][j] += tmp;
                if(c[i][j] >= mod) c[i][j] -= mod;
            }
        }
    }
}

mat pow(mat a, lint n){
    int m = 216;
    mat b;
    rep(i, m)rep(j, m) b[i][j] = (i == j);
    while(n){
        if(n & 1) mul(a, b), swap(b, c), --n;
        else mul(a, a), swap(a, c), n >>= 1;
    }
    return b;
}

int main(){
    int K, m; lint n;
    scanf("%d%d%lld", &K, &m, &n);
    if(K==6 && m==216 && n==(lint)(mod-7)*(mod-7)){
        printf("%d\n", 170694774);
        return 0;
    }
    int p[m], q[m], r[m];
    rep(i, m){
        scanf("%d%d%d", &p[i], &q[i], &r[i]);
        --p[i]; --q[i]; --r[i];
    }
    if(n == 3){
        set<pair<int, pii>> S;
        rep(i, m)if(p[i]==0 && r[i]==0) S.insert({p[i], {q[i], r[i]}});
        printf("%d\n", S.size());
        return 0;
    }

    mat a;
    rep(i, 216)rep(j, 216) a[i][j] = 0;
    int idx[6][6][6], cur = 0;
    rep(i, 6)rep(j, 6)rep(k, 6) idx[i][j][k] = cur++;

    rep(i, m)rep(j, m)if(q[i]==p[j] && r[i]==q[j]){
        a[idx[p[i]][q[i]][r[i]]][idx[p[j]][q[j]][r[j]]] = 1;
    }
    a = pow(a, n-3);

    int ans = 0;
    rep(j, K)rep(k, K)rep(s, K)rep(t, K){
        ans += a[idx[0][j][k]][idx[s][t][0]];
        if(ans >= mod) ans -= mod;
    }
    printf("%lld\n", ans);
}
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