結果
問題 | No.41 貯金箱の溜息(EASY) |
ユーザー |
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提出日時 | 2014-10-16 23:28:48 |
言語 | C++11(廃止可能性あり) (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 6 ms / 5,000 ms |
コード長 | 2,692 bytes |
コンパイル時間 | 825 ms |
コンパイル使用メモリ | 85,264 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-12-30 09:20:17 |
合計ジャッジ時間 | 1,350 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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ファイルパターン | 結果 |
---|---|
other | AC * 2 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:62:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 62 | scanf("%d", &T); | ~~~~~^~~~~~~~~~ main.cpp:75:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 75 | scanf("%lld", &M); | ~~~~~^~~~~~~~~~~~
ソースコード
#define _CRT_SECURE_NO_WARNINGS#include <string>#include <vector>#include <algorithm>#include <numeric>#include <set>#include <map>#include <queue>#include <iostream>#include <sstream>#include <cstdio>#include <cmath>#include <ctime>#include <cstring>#include <cctype>#include <cassert>#include <limits>#include <unordered_set>#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))#define rer(i,l,u) for(int (i)=(int)(l);(i)<=(int)(u);++(i))#define reu(i,l,u) for(int (i)=(int)(l);(i)<(int)(u);++(i))#if defined(_MSC_VER) || __cplusplus > 199711L#define aut(r,v) auto r = (v)#else#define aut(r,v) typeof(v) r = (v)#endif#define each(it,o) for(aut(it, (o).begin()); it != (o).end(); ++ it)#define all(o) (o).begin(), (o).end()#define pb(x) push_back(x)#define mp(x,y) make_pair((x),(y))#define mset(m,v) memset(m,v,sizeof(m))#define INF 0x3f3f3f3f#define INFL 0x3f3f3f3f3f3f3f3fLLusing namespace std;typedef vector<int> vi; typedef pair<int,int> pii; typedef vector<pair<int,int> > vpii;typedef long long ll; typedef vector<long long> vl; typedef pair<long long,long long> pll; typedef vector<pair<long long,long long> > vpll;typedef vector<string> vs; typedef long double ld;template<typename T, typename U> inline void amin(T &x, U y) { if(y < x) x = y; }template<typename T, typename U> inline void amax(T &x, U y) { if(x < y) x = y; }template<int MOD>struct ModInt {static const int Mod = MOD;unsigned x;ModInt(): x(0) { }ModInt(signed sig) { int sigt = sig % MOD; if(sigt < 0) sigt += MOD; x = sigt; }ModInt(signed long long sig) { int sigt = sig % MOD; if(sigt < 0) sigt += MOD; x = sigt; }int get() const { return (int)x; }ModInt &operator+=(ModInt that) { if((x += that.x) >= MOD) x -= MOD; return *this; }ModInt &operator-=(ModInt that) { if((x += MOD - that.x) >= MOD) x -= MOD; return *this; }ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; }ModInt operator+(ModInt that) const { return ModInt(*this) += that; }ModInt operator-(ModInt that) const { return ModInt(*this) -= that; }ModInt operator*(ModInt that) const { return ModInt(*this) *= that; }};typedef ModInt<1000000009> mint;int main() {int T;scanf("%d", &T);const int X = 111111, MaxM = (int)(ll)(1e10 / X);vector<mint> dp(MaxM+1, 0);dp[0] = 1;rer(i, 1, 9) {rer(j, 0, MaxM-i)dp[i + j] += dp[j];}vector<mint> dpsum(MaxM+2, 0);rer(i, 0, MaxM)dpsum[i+1] = dpsum[i] + dp[i];rep(ii, T) {long long M;scanf("%lld", &M);mint ans = dpsum[(int)(M / X) + 1];printf("%d\n", ans.get());}return 0;}