結果
問題 | No.1115 二つの数列 / Two Sequences |
ユーザー |
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提出日時 | 2020-07-17 21:41:16 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 70 ms / 2,000 ms |
コード長 | 4,926 bytes |
コンパイル時間 | 1,110 ms |
コンパイル使用メモリ | 116,580 KB |
実行使用メモリ | 6,820 KB |
最終ジャッジ日時 | 2024-11-29 22:42:55 |
合計ジャッジ時間 | 3,486 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 5 |
other | AC * 35 |
ソースコード
#include <iostream>#include <string>#include <vector>#include <algorithm>#include <utility>#include <tuple>#include <cstdint>#include <cstdio>#include <map>#include <queue>#include <set>#include <stack>#include <deque>#include <unordered_map>#include <unordered_set>#include <bitset>#include <cctype>#include <functional>#include <ctime>#include <cmath>#include <limits>#include <numeric>#include <type_traits>#include <iomanip>#include <float.h>#include <math.h>using namespace std;using ll = long long;unsigned euclidean_gcd(unsigned a, unsigned b) {if (a < b) return euclidean_gcd(b, a);unsigned r;while ((r = a % b)) {a = b;b = r;}return b;}ll ll_gcd(ll a, ll b) {if (a < b) return ll_gcd(b, a);ll r;while ((r = a % b)) {a = b;b = r;}return b;}struct UnionFind {vector <ll> par;vector <ll> siz;UnionFind(ll sz_) : par(sz_), siz(sz_, 1LL) {for (ll i = 0; i < sz_; ++i) par[i] = i;}void init(ll sz_) {par.resize(sz_);siz.assign(sz_, 1LL);for (ll i = 0; i < sz_; ++i) par[i] = i;}ll root(ll x) {while (par[x] != x) {x = par[x] = par[par[x]];}return x;}bool merge(ll x, ll y) {x = root(x);y = root(y);if (x == y) return false;if (siz[x] < siz[y]) swap(x, y);siz[x] += siz[y];par[y] = x;return true;}bool issame(ll x, ll y) {return root(x) == root(y);}ll size(ll x) {return siz[root(x)];}};long long modpow(long long a, long long n, long long mod) {long long res = 1;while (n > 0) {if (n & 1) res = res * a % mod;a = a * a % mod;n >>= 1;}return res;}long long modinv(long long a, long long mod) {return modpow(a, mod - 2, mod);}vector<int> tpsort(vector<vector<int>>& G) {int V = G.size();vector<int> sorted_vertices;queue<int> que;vector<int> indegree(V);for (int i = 0; i < V; i++) {for (int j = 0; j < G[i].size(); j++) {indegree[G[i][j]]++;}}for (int i = 0; i < V; i++) {if (indegree[i] == 0) {que.push(i);}}while (que.empty() == false) {int v = que.front();que.pop();for (int i = 0; i < G[v].size(); i++) {int u = G[v][i];indegree[u] -= 1;if (indegree[u] == 0) que.push(u);}sorted_vertices.push_back(v);}return sorted_vertices;}struct Point{double x;double y;};struct LineSegment{Point start;Point end;};double tenkyori(const LineSegment& line, const Point& point){double x0 = point.x, y0 = point.y;double x1 = line.start.x, y1 = line.start.y;double x2 = line.end.x, y2 = line.end.y;double a = x2 - x1;double b = y2 - y1;double a2 = a * a;double b2 = b * b;double r2 = a2 + b2;double tt = -(a * (x1 - x0) + b * (y1 - y0));if (tt < 0)return sqrt((x1 - x0) * (x1 - x0) + (y1 - y0) * (y1 - y0));else if (tt > r2)return sqrt((x2 - x0) * (x2 - x0) + (y2 - y0) * (y2 - y0));double f1 = a * (y1 - y0) - b * (x1 - x0);return sqrt((f1 * f1) / r2);}void dfs1(vector<vector<ll>>& z,ll k,ll oya,ll &ans,vector<ll>&b) {for (auto m : z[k]) {if (m != oya)dfs1(z, m, k,ans,b);}vector<ll> s;for (auto m : z[k]) {if (m != oya)s.push_back(b[m]);}ll m = b.size() - 1;for (auto d : s) {m -= d;}b[k] = b.size() - m;if(m!=0)s.push_back(m);ll a = modinv(2, 1000000007);for (auto d : s) {a += 1000000007-modinv(modpow(2, b.size() - d, 1000000007),1000000007);}a += modinv(modpow(2, b.size(), 1000000007), 1000000007)*(z[k].size()-1);ans += a;ans %= 1000000007;return;}ll merge_cnt(vector<int>& a) {int n = a.size();if (n <= 1) { return 0; }ll cnt = 0;vector<int> b(a.begin(), a.begin() + n / 2);vector<int> c(a.begin() + n / 2, a.end());cnt += merge_cnt(b);cnt += merge_cnt(c);int ai = 0, bi = 0, ci = 0;while (ai < n) {if (bi < b.size() && (ci == c.size() || b[bi] <= c[ci])) {a[ai++] = b[bi++];}else {cnt += n / 2 - bi;a[ai++] = c[ci++];}}return cnt;}int main() {ll n;cin >> n;vector<ll> z(n);vector<ll> x(n);for (int i = 0; i < n; i++) {cin >> z[i];z[i]--;}for (int i = 0; i < n; i++) {ll a;cin >> a;a--;x[a] = i;}vector<int> s(n);for (int i = 0; i < n; i++) {s[i] = x[z[i]];}ll ans = merge_cnt(s);cout << ans << endl;}