結果

問題 No.1113 二つの整数 / Two Integers
ユーザー siro53
提出日時 2020-07-17 22:10:46
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 5 ms / 1,000 ms
コード長 2,950 bytes
コンパイル時間 3,404 ms
コンパイル使用メモリ 207,388 KB
最終ジャッジ日時 2025-01-11 22:45:52
ジャッジサーバーID
(参考情報)
judge3 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 15
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
template <class T> inline bool chmax(T &a, T b) {
if(a < b) {
a = b;
return 1;
}
return 0;
}
template <class T> inline bool chmin(T &a, T b) {
if(a > b) {
a = b;
return 1;
}
return 0;
}
void debug() { cerr << "\n"; }
template <class T> void debug(const T &x) { cerr << x << "\n"; }
template <class T, class... Args> void debug(const T &x, const Args &... args) {
cerr << x << " ";
debug(args...);
}
template <class T> void debugVector(const vector<T> &v) {
for(const T &x : v) {
cerr << x << " ";
}
cerr << "\n";
}
using ll = long long;
#define ALL(v) (v).begin(), (v).end()
#define RALL(v) (v).rbegin(), (v).rend()
const double EPS = 1e-7;
const int INF = 1 << 30;
const ll LLINF = 1LL << 60;
const double PI = acos(-1);
constexpr int MOD = 1000000007;
const int dx[4] = {1, 0, -1, 0};
const int dy[4] = {0, 1, 0, -1};
//-------------------------------------
struct factorise {
ll mul(ll a, ll b, ll c) { return (__int128)a * b % c; }
ll pow(ll a, ll b, ll m) {
ll res = 1;
while(b) {
if(b & 1) {
res = mul(res, a, m);
}
a = mul(a, a, m);
b >>= 1;
}
return res;
}
bool isprime(ll n) {
if(!(n & 1) && n != 2)
return false;
ll d = n - 1;
int s = __builtin_ctzll(d);
d >>= s;
vector<int> A;
if(n <= 1e9)
A = {2, 3, 5, 7};
else
A = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37};
for(int a : A) {
ll p = pow(a, d, n);
int i = s;
while(p != 1 && p != n - 1 && a % n && --i) {
p = mul(p, p, n);
}
if(p != n - 1 && i != s)
return false;
}
return true;
}
ll pollard(ll n) {
auto f = [&](ll a) { return mul(a, a, n) + 1; };
ll x = 0, y = 0, p = 2, q;
int i = 1, t = 0;
while(t++ % 40 || gcd(p, n) == 1) {
if(x == y)
x = ++i, y = f(x);
if(q = mul(p, abs(y - x), n))
p = q;
x = f(x);
y = f(f(y));
}
return gcd(p, n);
}
vector<ll> factor(ll n) {
if(n == 1)
return {};
if(isprime(n))
return {n};
ll a = pollard(n);
assert(a != n && a != 1);
auto l = factor(a), r = factor(n / a);
l.insert(l.end(), r.begin(), r.end());
return l;
}
};
int main() {
cin.tie(0);
ios::sync_with_stdio(false);
ll A, B;
cin >> A >> B;
ll g = gcd(A, B);
factorise f;
auto v = f.factor(g);
map<ll, ll> cnt;
for(auto i : v) {
cnt[i]++;
}
ll n = 1;
for(auto p : cnt) {
n *= (p.second + 1);
}
cout << (n % 2 ? "Odd" : "Even") << endl;
}
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