結果

問題 No.1115 二つの数列 / Two Sequences
ユーザー onsen_manjuuu
提出日時 2020-07-21 11:53:20
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 97 ms / 2,000 ms
コード長 4,163 bytes
コンパイル時間 2,900 ms
コンパイル使用メモリ 175,440 KB
実行使用メモリ 5,760 KB
最終ジャッジ日時 2024-12-27 12:15:47
合計ジャッジ時間 5,804 ms
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 5
other AC * 35
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
using namespace std;
using ll = long long;
template<class T>
class SegTree{
private:
int n;
int m;
int depth;
T def;
vector<T> data;
function<T(T,T)> calculate;
function<T(T,T)> update;
T rec(int l, int r, int node, int node_l, int node_r) {
if (node_r <= l || node_l >= r) return def;
if (node_l >= l && node_r <= r) return data[node];
int mid = (node_l + node_r) / 2;
return calculate(
rec(l, r, node * 2, node_l, mid),
rec(l, r, node * 2 + 1, mid, node_r));
}
void _assign(int index, T val){
index += n;
data[index] = update(data[index], val);
for(;index /= 2;)
data[index] = calculate(data[index * 2],data[index * 2 + 1]);
}
void _print() {
cerr << "[";
for(int i = 0; i < m; i++) {
cerr << data[i + n] << (i != m - 1 ? "," : "]\n");
}
}
void _show() {
vector<string> res(depth + 1);
vector<int> width(depth + 1);
width[depth-1] = 3;
for(int i = depth-2; i >= 0; i--)width[i] = width[i + 1] * 2 + 2;
for(int i = 0; i < depth; i++) {
int start = 1<<i, end = 1<<(i + 1);
for(int j = start; j < end; j++) {
int d = 0, cur = (data[j] == 0 ? 1 : data[j]);
while(cur){cur/=10,d++;}
int wid = width[i] - d;
cerr << '[' << right << string(wid/2,' ') << data[j] << string(wid - wid/2, ' ') << ']';
}
cerr << endl;
}
}
int _lower_right(int index, T val) {
int lef = index, rig = n; //ooooxx
while(rig - lef > 1) {
int mid = (rig + lef) / 2;
(get(index, mid) < val ? lef : rig) = mid;
}
return rig;
}
int _upper_right(int index, T val) {
int lef = index, rig = n; //ooooxx
while(rig - lef > 1) {
int mid = (rig + lef) / 2;
(get(index, mid) <= val ? lef : rig) = mid;
}
return rig;
}
public:
SegTree(vector<T> a, T _def, function<T(T,T)> _calculate, function<T(T,T)> _update):
def(_def), calculate(_calculate), update(_update) {
m = a.size();
for (n = 1; n < (int) a.size(); n *= 2, depth++);
data.resize(n * 2, def);
for (int i = 0; i < (int) a.size(); i++) data[i + n] = a[i];
for (int i = n - 1; i >= 1; i--)
data[i] = calculate(data[i * 2], data[i * 2 + 1]);
}
//
T get(int l,int r){
if(l == r)return def;
return rec(l,r,1,0,n);
}
//
void assign(int index, T val){
_assign(index, val);
}
void print() {
_print();
}
void show() {
_show();
}
T operator[] (int i){
return data[i + n];
}
//get(index, right) >= valright
int lower_right(int index, T val) {
return _lower_right(index, val);
}
//get(index, right) > valright
int upper_right(int index, T val) {
return _upper_right(index, val);
}
};
ll rev(vector<int> a) {
int n = a.size();
SegTree<int> tree(vector<int>(n), 0, [](int a, int b){return a + b;}, [](int a, int b){return a + b;});
ll sum = 0;
for(int i = 0; i < n; i++) {
sum += tree.get(a[i], n + 1);
tree.assign(a[i], 1);
}
return sum;
}
int main()
{
int n; cin >> n;
vector<int> a(n), p(n);
for(int i = 0; i < n; i++)cin >> a[i], a[i]--;
for(int i = 0; i < n; i++) {
int t; cin >> t; t--;
p[t] = i;
}
for(int i = 0; i < n; i++)a[i] = p[a[i]];
cout << rev(a) << endl;
}
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