#516667 (C++17) No.1125 Without Parallelogram

• 問題: No.1125 Without Parallelogram
• ユーザー: snuke
• 提出日時: 2020-07-22 23:15:12
• 言語: C++17 (gcc 12.3.0 + boost 1.83.0)
• 結果: AC
• 実行時間: 14 ms / 1,000 ms
• コード長: 3,001 bytes
• コンパイル時間: 2,381 ms
• コンパイル使用メモリ: 214,832 KB
• 実行使用メモリ: 5,376 KB
• 最終ジャッジ日時: 2024-06-23 00:54:11
• 合計ジャッジ時間: 6,730 ms
• ジャッジサーバーID （参考情報）: judge2 / judge5

入力	結果	実行時間; 実行使用メモリ
testcase_00	AC	4 ms; 5,248 KB
testcase_01	AC	3 ms; 5,376 KB
testcase_02	AC	4 ms; 5,376 KB
testcase_03	AC	4 ms; 5,376 KB
testcase_04	AC	3 ms; 5,376 KB
testcase_05	AC	4 ms; 5,376 KB
testcase_06	AC	4 ms; 5,376 KB
testcase_07	AC	4 ms; 5,376 KB
testcase_08	AC	4 ms; 5,376 KB
testcase_09	AC	3 ms; 5,376 KB
testcase_10	AC	4 ms; 5,376 KB
testcase_11	AC	4 ms; 5,376 KB
testcase_12	AC	4 ms; 5,376 KB
testcase_13	AC	4 ms; 5,376 KB
testcase_14	AC	4 ms; 5,376 KB
testcase_15	AC	4 ms; 5,376 KB
testcase_16	AC	5 ms; 5,376 KB
testcase_17	AC	6 ms; 5,376 KB
testcase_18	AC	6 ms; 5,376 KB
testcase_19	AC	6 ms; 5,376 KB
testcase_20	AC	7 ms; 5,376 KB
testcase_21	AC	8 ms; 5,376 KB
testcase_22	AC	8 ms; 5,376 KB
testcase_23	AC	8 ms; 5,376 KB
testcase_24	AC	14 ms; 5,376 KB
testcase_25	AC	14 ms; 5,376 KB
testcase_26	AC	11 ms; 5,376 KB
testcase_27	AC	8 ms; 5,376 KB
testcase_28	AC	4 ms; 5,376 KB
testcase_29	AC	3 ms; 5,376 KB
testcase_30	AC	3 ms; 5,376 KB

ソースコード

#include <bits/stdc++.h>
#define fi first
#define se second
#define rep(i,n) for(int i = 0; i < (n); ++i)
#define rrep(i,n) for(int i = 1; i <= (n); ++i)
#define drep(i,n) for(int i = (n)-1; i >= 0; --i)
#define srep(i,s,t) for (int i = s; i < t; ++i)
#define rng(a) a.begin(),a.end()
#define rrng(a) a.rbegin(),a.rend()
#define maxs(x,y) (x = max(x,y))
#define mins(x,y) (x = min(x,y))
#define isin(x,l,r) ((l) <= (x) && (x) < (r))
#define pb push_back
#define eb emplace_back
#define sz(x) (int)(x).size()
#define pcnt __builtin_popcountll
#define uni(x) x.erase(unique(rng(x)),x.end())
#define snuke srand((unsigned)clock()+(unsigned)time(NULL));
#define show(x) cout<<#x<<" = "<<x<<endl;
#define PQ(T) priority_queue<T,v(T),greater<T> >
#define bn(x) ((1<<x)-1)
#define dup(x,y) (((x)+(y)-1)/(y))
#define newline puts("")
#define v(T) vector<T>
#define vv(T) v(v(T))
using namespace std;
typedef long long int ll;
typedef unsigned uint;
typedef unsigned long long ull;
typedef pair<int,int> P;
typedef tuple<int,int,int> T;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef vector<ll> vl;
typedef vector<P> vp;
typedef vector<T> vt;
inline int getInt() { int x; scanf("%d",&x); return x;}
template<typename T>inline istream& operator>>(istream&i,v(T)&v)
{rep(j,sz(v))i>>v[j];return i;}
template<typename T>string join(const v(T)&v)
{stringstream s;rep(i,sz(v))s<<' '<<v[i];return s.str().substr(1);}
template<typename T>inline ostream& operator<<(ostream&o,const v(T)&v)
{if(sz(v))o<<join(v);return o;}
template<typename T1,typename T2>inline istream& operator>>(istream&i,pair<T1,T2>&v)
{return i>>v.fi>>v.se;}
template<typename T1,typename T2>inline ostream& operator<<(ostream&o,const pair<T1,T2>&v)
{return o<<v.fi<<","<<v.se;}
template<typename T>inline ll suma(const v(T)& a) { ll res(0); for (auto&& x : a) res += x; return res;}
const double eps = 1e-10;
const ll LINF = 1001002003004005006ll;
const int INF = 1001001001;
#define dame { puts("-1"); return 0;}
#define yn {puts("Yes");}else{puts("No");}
const int MX = 200005;

// linear sieve
vi ps, pf;
void sieve(int mx) {
  pf = vi(mx+1);
  rep(i,mx+1) pf[i] = i;
  for (int i = 2; i <= mx; ++i) {
    if (pf[i] == i) ps.pb(i);
    for (int j = 0; j < sz(ps) && ps[j] <= pf[i]; ++j) {
      int x = ps[j]*i;
      if (x > mx) break;
      pf[x] = ps[j];
    }
  }
}
inline bool isp(int x) { return pf[x] == x && x >= 2;}
vp factor(int x) { // asc
  if (x == 1) return {};
  vp res(1, P(pf[x], 0));
  while (x != 1) {
    if (res.back().fi == pf[x]) res.back().se++;
    else res.pb(P(pf[x],1));
    x /= pf[x];
  }
  return res;
}
//



int main() {
  sieve(MX);
  int n;
  scanf("%d",&n);
  int p = *lower_bound(rng(ps), max(40,n+2));
  srep(x,2,p) {
    set<int> st;
    vi ans(1,1);
    st.insert(1);
    while (sz(ans) < n) {
      ans.pb(ans.back()*x%p);
      st.insert(ans.back());
    }
    if (sz(st) != n) continue;
    rep(i,n) {
      cout<<i<<" "<<ans[i]<<endl;
    }
    break;
  }
  return 0;
}