結果

問題 No.1140 EXPotentiaLLL!
ユーザー kimiyuki
提出日時 2020-07-31 21:38:23
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 3,739 bytes
コンパイル時間 1,799 ms
コンパイル使用メモリ 91,276 KB
最終ジャッジ日時 2025-01-12 09:29:29
ジャッジサーバーID
（参考情報） 		judge5 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 5 WA * 7
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ソースコード

diff #
プレゼンテーションモードにする

#line 1 "main.cpp"
#define PROBLEM "https://yukicoder.me/problems/no/1140"
#include <cstdio>
#line 2 "/home/user/Library/utils/macros.hpp"
#define REP(i, n) for (int i = 0; (i) < (int)(n); ++ (i))
#define REP3(i, m, n) for (int i = (m); (i) < (int)(n); ++ (i))
#define REP_R(i, n) for (int i = (int)(n) - 1; (i) >= 0; -- (i))
#define REP3R(i, m, n) for (int i = (int)(n) - 1; (i) >= (int)(m); -- (i))
#define ALL(x) std::begin(x), std::end(x)
#line 2 "/home/user/Library/number/primes.hpp"
#include <algorithm>
#include <cassert>
#include <cstdint>
#include <map>
#include <vector>
#line 8 "/home/user/Library/number/primes.hpp"
/**
 * @note O(\sqrt{n})
 */
struct prepared_primes {
    int size;
    std::vector<int> sieve;
    std::vector<int> primes;
    prepared_primes(int size_)
        : size(size_) {
        sieve.resize(size);
        REP3 (p, 2, size) if (sieve[p] == 0) {
            primes.push_back(p);
            for (int k = p; k < size; k += p) {
                if (sieve[k] == 0) {
                    sieve[k] = p;
                }
            }
        }
    }
    std::vector<int64_t> list_prime_factors(int64_t n) {
        assert (1 <= n and n < (int64_t)size * size);
        std::vector<int64_t> result;
        // trial division for large part
        for (int p : primes) {
            if (n < size or n < (int64_t)p * p) {
                break;
            }
            while (n % p == 0) {
                n /= p;
                result.push_back(p);
            }
        }
        // small part
        if (n == 1) {
            // nop
        } else if (n < size) {
            while (n != 1) {
                result.push_back(sieve[n]);
                n /= sieve[n];
            }
        } else {
            result.push_back(n);
        }
        assert (std::is_sorted(ALL(result)));
        return result;
    }
    /**
     * @note O(1) if n < size; O(sqrt n) if size <= n < size^2
     */
    bool is_prime(int64_t n) {
        assert (1 <= n and n < (int64_t)size * size);
        if (n < size) {
            return sieve[n] == n;
        }
        for (int p : primes) {
            if (n < (int64_t)p * p) {
                break;
            }
            if (n % p == 0) {
                return false;
            }
        }
        return true;
    }
    std::vector<int64_t> list_all_factors(int64_t n) {
        auto p = list_prime_factors(n);
        std::vector<int64_t> d;
        d.push_back(1);
        for (int l = 0; l < p.size(); ) {
            int r = l + 1;
            while (r < p.size() and p[r] == p[l]) ++ r;
            int n = d.size();
            REP (k1, r - l) {
                REP (k2, n) {
                    d.push_back(d[d.size() - n] * p[l]);
                }
            }
            l = r;
        }
        return d;
    }
    std::map<int64_t, int> list_prime_factors_as_map(int64_t n) {
        std::map<int64_t, int> cnt;
        for (int64_t p : list_prime_factors(n)) {
            ++ cnt[p];
        }
        return cnt;
    }
    int64_t euler_totient(int64_t n) {
        int64_t phi = 1;
        int64_t last = -1;
        for (int64_t p : list_prime_factors(n)) {
            if (last != p) {
                last = p;
                phi *= p - 1;
            } else {
                phi *= p;
            }
        }
        return phi;
    }
};
#line 5 "main.cpp"
using namespace std;
prepared_primes primes(1e6 + 100);
int solve(long long a, int p) {
    if (a % p == 0) return 0;
    return primes.is_prime(p) ? 1 : -1;
}
int main() {
    int t; scanf("%d", &t);
    while (t --) {
        long long a; int p; scanf("%lld%d", &a, &p);
        auto ans = solve(a, p);
        printf("%d\n", ans);
    }
    return 0;
}
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