結果
問題 | No.1140 EXPotentiaLLL! |
ユーザー |
|
提出日時 | 2020-07-31 21:39:23 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
TLE
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 3,756 bytes |
コンパイル時間 | 919 ms |
コンパイル使用メモリ | 64,896 KB |
最終ジャッジ日時 | 2025-01-12 09:31:00 |
ジャッジサーバーID (参考情報) |
judge1 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 10 TLE * 2 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:16:17: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 16 | #line 8 "/home/user/Library/number/primes.hpp" | ~~~~~^~~~~~~~~~ main.cpp:18:34: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 18 | /** | ^
ソースコード
#line 1 "main.cpp"#define PROBLEM "https://yukicoder.me/problems/no/1140"#include <cstdio>#line 2 "/home/user/Library/utils/macros.hpp"#define REP(i, n) for (int i = 0; (i) < (int)(n); ++ (i))#define REP3(i, m, n) for (int i = (m); (i) < (int)(n); ++ (i))#define REP_R(i, n) for (int i = (int)(n) - 1; (i) >= 0; -- (i))#define REP3R(i, m, n) for (int i = (int)(n) - 1; (i) >= (int)(m); -- (i))#define ALL(x) std::begin(x), std::end(x)#line 2 "/home/user/Library/number/primes.hpp"#include <algorithm>#include <cassert>#include <cstdint>#include <map>#include <vector>#line 8 "/home/user/Library/number/primes.hpp"/*** @note O(\sqrt{n})*/struct prepared_primes {int size;std::vector<int> sieve;std::vector<int> primes;prepared_primes(int size_): size(size_) {sieve.resize(size);REP3 (p, 2, size) if (sieve[p] == 0) {primes.push_back(p);for (int k = p; k < size; k += p) {if (sieve[k] == 0) {sieve[k] = p;}}}}std::vector<int64_t> list_prime_factors(int64_t n) {assert (1 <= n and n < (int64_t)size * size);std::vector<int64_t> result;// trial division for large partfor (int p : primes) {if (n < size or n < (int64_t)p * p) {break;}while (n % p == 0) {n /= p;result.push_back(p);}}// small partif (n == 1) {// nop} else if (n < size) {while (n != 1) {result.push_back(sieve[n]);n /= sieve[n];}} else {result.push_back(n);}assert (std::is_sorted(ALL(result)));return result;}/*** @note O(1) if n < size; O(sqrt n) if size <= n < size^2*/bool is_prime(int64_t n) {assert (1 <= n and n < (int64_t)size * size);if (n < size) {return sieve[n] == n;}for (int p : primes) {if (n < (int64_t)p * p) {break;}if (n % p == 0) {return false;}}return true;}std::vector<int64_t> list_all_factors(int64_t n) {auto p = list_prime_factors(n);std::vector<int64_t> d;d.push_back(1);for (int l = 0; l < p.size(); ) {int r = l + 1;while (r < p.size() and p[r] == p[l]) ++ r;int n = d.size();REP (k1, r - l) {REP (k2, n) {d.push_back(d[d.size() - n] * p[l]);}}l = r;}return d;}std::map<int64_t, int> list_prime_factors_as_map(int64_t n) {std::map<int64_t, int> cnt;for (int64_t p : list_prime_factors(n)) {++ cnt[p];}return cnt;}int64_t euler_totient(int64_t n) {int64_t phi = 1;int64_t last = -1;for (int64_t p : list_prime_factors(n)) {if (last != p) {last = p;phi *= p - 1;} else {phi *= p;}}return phi;}};#line 5 "main.cpp"using namespace std;prepared_primes primes(1e6 + 100);int solve(long long a, int p) {if (not primes.is_prime(p)) return -1;if (a % p == 0) return 0;return 1;}int main() {int t; scanf("%d", &t);while (t --) {long long a; int p; scanf("%lld%d", &a, &p);auto ans = solve(a, p);printf("%d\n", ans);}return 0;}