結果
問題 | No.1142 XOR と XOR |
ユーザー | xllend3 |
提出日時 | 2020-07-31 21:51:47 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 5,036 bytes |
コンパイル時間 | 1,484 ms |
コンパイル使用メモリ | 168,096 KB |
実行使用メモリ | 14,028 KB |
最終ジャッジ日時 | 2024-07-06 17:43:34 |
合計ジャッジ時間 | 8,814 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 3 ms
9,932 KB |
testcase_01 | AC | 3 ms
9,808 KB |
testcase_02 | AC | 3 ms
9,804 KB |
testcase_03 | WA | - |
testcase_04 | AC | 321 ms
9,932 KB |
testcase_05 | AC | 265 ms
9,804 KB |
testcase_06 | AC | 335 ms
9,808 KB |
testcase_07 | WA | - |
testcase_08 | AC | 406 ms
14,028 KB |
testcase_09 | AC | 407 ms
9,804 KB |
testcase_10 | AC | 417 ms
11,852 KB |
testcase_11 | AC | 3 ms
9,804 KB |
testcase_12 | AC | 3 ms
9,804 KB |
testcase_13 | AC | 3 ms
9,932 KB |
testcase_14 | AC | 238 ms
9,804 KB |
testcase_15 | AC | 222 ms
9,808 KB |
testcase_16 | AC | 19 ms
9,928 KB |
testcase_17 | WA | - |
testcase_18 | AC | 78 ms
9,800 KB |
testcase_19 | AC | 350 ms
9,928 KB |
testcase_20 | AC | 210 ms
9,804 KB |
testcase_21 | AC | 142 ms
9,804 KB |
testcase_22 | AC | 75 ms
9,808 KB |
testcase_23 | AC | 321 ms
11,980 KB |
testcase_24 | AC | 362 ms
13,900 KB |
testcase_25 | AC | 212 ms
9,804 KB |
testcase_26 | WA | - |
testcase_27 | WA | - |
ソースコード
#include<bits/stdc++.h> using namespace std; #define X first #define Y second #define mp make_pair #define pb push_back #define rep(i,a,n) for(int i=(a);i<=(n);++i) #define dep(i,a,n) for(int i=(a);i>=(n);--i) #define eps 1e-8 #define pi 3.1415926535897 #define sqr(x) ((x)*(x)) #define SZ(x) ((int)(x).size()) #define CPY(a,b) memcpy(a,b,sizeof(a)) #define CLR(a) memset(a,0,sizeof(a)) #define POSIN(x,y) (1<=(x)&&(x)<=m&&1<=(y)&&(y)<=n) #define ALL(x) (x).begin(),(x).end() #define COUT(S,x) cout<<fixed<<setprecision(x)<<S<<endl #define buli(x) (__builtin_popcountll(x)) #define bur0(x) (__builtin_ctzll(x)) #define bul2(x) (63-__builtin_clzll(x)) #define pw(x) ((ll(1))<<(x)) #define upmo(a,b) (((a)=((a)+(b))%mo)<0?(a)+=mo:(a)) #define mmo(a,b) (((a)=1ll*(a)*(b)%mo)<0?(a)+=mo:(a)) #define y0 y0z #define y1 y1z #define yn ynz #define j0 j0z #define j1 j1z #define jn jnz #define tm tmz #ifdef LOCAL #define debug(...) fprintf(stderr, __VA_ARGS__) #define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl; #else #define debug(...) #define dbg(x) #endif template<typename T> bool MAX(T &m, const T q) { if (m < q) {m = q; return true;} else return false; } template<typename T> bool MIN(T &m, const T q) { if (m > q) {m = q; return true;} else return false; } template<typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); } template<typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); } template<typename T> ostream &operator<<(ostream &os, const vector<T> &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; } template<typename T> ostream &operator<<(ostream &os, const deque<T> &vec){ os << "deq["; for (auto v : vec) os << v << ","; os << "]"; return os; } template<typename T> ostream &operator<<(ostream &os, const set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; } template<typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; } template<typename T> ostream &operator<<(ostream &os, const multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; } template<typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; } template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa){ os << "(" << pa.first << "," << pa.second << ")"; return os; } template<typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; } template<typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; } typedef long long ll; typedef double lf; typedef pair<int,int> pii; typedef pair<ll,ll> pll; typedef pair<lf,lf> pff; typedef complex<double> CD; typedef vector<int> VI; typedef vector<ll> VL; const int inf=0x3f3f3f3f; const int mo=1000000007; inline void gn(long long&x){ int sg=1;char c;while(((c=getchar())<'0'||c>'9')&&c!='-');c=='-'?(sg=-1,x=0):(x=c-'0'); while((c=getchar())>='0'&&c<='9')x=x*10+c-'0';x*=sg; } inline void gn(int&x){long long t;gn(t);x=t;} inline void gn(unsigned long long&x){long long t;gn(t);x=t;} inline void gn(double&x){double t;scanf("%lf",&t);x=t;} inline void gn(long double&x){double t;scanf("%lf",&t);x=t;} template<class T1,class T2>inline void gn(T1&r,T2&s){gn(r),gn(s);} template<class T1,class T2,class T3>inline void gn(T1&r,T2&s,T3&t){gn(r),gn(s),gn(t);} template<class T1,class T2,class T3,class T4>inline void gn(T1&r,T2&s,T3&t,T4&u){gn(r),gn(s),gn(t),gn(u);} inline void gs(char *s){scanf("%s",s);} inline void gc(char &c){while((c=getchar())>126 || c<33);} inline void pc(char c){putchar(c);} const int DX[]={1,0,-1,0},DY[]={0,1,0,-1}; ll powmod(ll a,ll b) {ll res=1;a%=mo;for(;b;b>>=1){if(b&1)res=res*a%mo;a=a*a%mo;}return res;} ll powmod(ll a,ll b,ll mo) {ll res=1;a%=mo;for(;b;b>>=1){if(b&1)res=res*a%mo;a=a*a%mo;}return res;} ll gcd(ll a,ll b) { return b?gcd(b,a%b):a;} //******************************************* const int N=1111111,M=111111; int l,m,n,t,C; int a[N],b[N],aa[N],bb[N]; int main(){ #ifdef LOCAL freopen("D.in","r",stdin);//freopen("D.out","w",stdout); #endif scanf("%d%d%d",&n,&m,&t); rep(i,1,n)scanf("%d",&a[i]); rep(i,1,m)scanf("%d",&b[i]); rep(i,2,n)a[i]^=a[i-1]; rep(i,2,m)b[i]^=b[i-1]; rep(i,0,n)aa[a[i]]++; rep(i,0,m)bb[b[i]]++; ll ans=0; rep(p,0,1023){ ll res=1; ll cnt=0; rep(i,0,n){cnt+=aa[a[i]^p];if(p==0)--cnt;} res*=cnt/2; cnt=0; rep(i,0,m){cnt+=bb[b[i]^(p^t)];if((p^t)==0)--cnt;} res*=cnt/2; ans+=res; ans%=mo; } printf("%d\n",int(ans)); return 0; }