結果
問題 | No.1144 Triangles |
ユーザー | xyz2606 |
提出日時 | 2020-07-31 23:32:15 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 3,936 bytes |
コンパイル時間 | 1,242 ms |
コンパイル使用メモリ | 117,508 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-07-06 21:46:24 |
合計ジャッジ時間 | 7,526 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,812 KB |
testcase_01 | AC | 2 ms
6,940 KB |
testcase_02 | AC | 2 ms
6,940 KB |
testcase_03 | AC | 2 ms
6,944 KB |
testcase_04 | AC | 467 ms
6,940 KB |
testcase_05 | AC | 458 ms
6,944 KB |
testcase_06 | AC | 468 ms
6,940 KB |
testcase_07 | WA | - |
testcase_08 | AC | 445 ms
6,940 KB |
testcase_09 | AC | 2 ms
6,940 KB |
testcase_10 | AC | 2 ms
6,944 KB |
testcase_11 | AC | 1 ms
6,944 KB |
testcase_12 | AC | 2 ms
6,944 KB |
testcase_13 | AC | 2 ms
6,944 KB |
testcase_14 | AC | 421 ms
6,940 KB |
testcase_15 | AC | 412 ms
6,940 KB |
testcase_16 | AC | 441 ms
6,940 KB |
testcase_17 | AC | 442 ms
6,940 KB |
testcase_18 | AC | 440 ms
6,944 KB |
testcase_19 | AC | 24 ms
6,940 KB |
testcase_20 | AC | 3 ms
6,940 KB |
testcase_21 | AC | 3 ms
6,940 KB |
testcase_22 | AC | 425 ms
6,944 KB |
testcase_23 | AC | 26 ms
6,940 KB |
testcase_24 | AC | 417 ms
6,944 KB |
testcase_25 | AC | 137 ms
6,940 KB |
testcase_26 | AC | 15 ms
6,940 KB |
testcase_27 | AC | 9 ms
6,940 KB |
testcase_28 | WA | - |
ソースコード
#include<vector> #include<set> #include<map> #include<queue> #include<string> #include<algorithm> #include<iostream> #include<bitset> #include<functional> #include<numeric> #include<cstdio> #include<cstring> #include<cstdlib> #include<cassert> #include<cmath> #include<iomanip> #include<random> #include<ctime> #include<complex> using namespace std; typedef long long LL; typedef double D; #define all(v) (v).begin(), (v).end() mt19937 gene(233); typedef complex<double> Complex; #define fi first #define se second #define ins insert #define pb push_back inline char GET_CHAR(){ const int maxn = 131072; static char buf[maxn],*p1=buf,*p2=buf; return p1==p2&&(p2=(p1=buf)+fread(buf,1,maxn,stdin),p1==p2)?EOF:*p1++; } inline int getInt() { int res(0); char c = getchar(); while(c < '0') c = getchar(); while(c >= '0') { res = res * 10 + (c - '0'); c = getchar(); } return res; } inline LL fastpo(LL x, LL n, LL mod) { LL res(1); while(n) { if(n & 1) { res = res * (LL)x % mod; } x = x * (LL) x % mod; n /= 2; } return res; } LL gcd(LL a, LL b) { return b ? gcd(b, a % b) : a; } inline string itoa(int x, int width = 0) { string res; if(x == 0) res.push_back('0'); while(x) { res.push_back('0' + x % 10); x /= 10; } while((int)res.size() < width) res.push_back('0'); reverse(res.begin(), res.end()); return res; } const int _B = 131072; char buf[_B]; int _bl = 0; inline void flush() { fwrite(buf, 1, _bl, stdout); _bl = 0; } __inline void _putchar(char c) { if(_bl == _B) flush(); buf[_bl++] = c; } inline void print(LL x, char c) { static char tmp[20]; int l = 0; if(!x) tmp[l++] = '0'; else { while(x) { tmp[l++] = x % 10 + '0'; x /= 10; } } for(int i = l - 1; i >= 0; i--) _putchar(tmp[i]); _putchar(c); } const int N = 2222; const int LOG = 20; const int mod = 1e9 + 7; const int inf = 1e9 + 7; int n, m; int dx[4] = {1, 0, -1, 0}; int dy[4] = {0, 1, 0, -1}; struct P { LL x, y; int cnt; void scan() { cin >> x >> y; cnt = 1; } P operator + (const P & b) const { return P{x + b.x, y + b.y};} P operator - (const P & b) const { return P{x - b.x, y - b.y};} LL operator * (const P & b) const { return x * b.y - y * b.x;} LL operator % (const P & b) const { return x * b.x + y * b.y;} bool operator < (const P & b) const { int d = x > 0 || x == 0 && y > 0; int db = b.x > 0 || b.x == 0 && b.y > 0; if(d != db) return d < db; else return *this * b > 0; } void print() const { cout << x << ' ' << y << endl; } }; P a[N]; int main() { int n; scanf("%d", &n); for(int i = 0; i < n; i++) { a[i].scan(); } LL ans = 0; for(int i = 0; i < n; i++) { P tot{0, 0}; vector<P> v; int cc = 1; for(int j = 0; j < n; j++) { if(j == i) continue; if((a[j] - a[i]).x == 0 && (a[j] - a[i]).y == 0) { cc++; continue; } v.pb(a[j] - a[i]); tot = tot + v.back(); } sort(v.begin(), v.end()); int sz = v.size(); if(sz <= 1) continue; int p = 0; P sum = v[0]; LL tmp = 0; //printf("%d %d\n", i, cc); for(int j = 0, k; j < sz; j = k) { /*if(p < j || v[j] * v[p] == 0) { while(p + 1 != j + sz && (p + 1 <= j || v[j] * v[(p + 1) % (sz)] == 0)) { p = p + 1; sum = sum + v[p % (sz)]; } }*/ P vv{0, 0}; for(k = j; k < sz && v[j] * v[k] == 0 && v[j] % v[k] > 0; k++) { vv = vv + v[k]; } //if(k - j != 1) printf("%d\n", k - j); while(j != k - 1) { sum = sum - v[j]; j++; } while(p + 1 != j + sz && (p < j || v[j] * v[(p + 1) % (sz)] > 0)) { p = p + 1; sum = sum + v[p % (sz)]; } //cout << '?' << j << ' ' << p << endl; //sum.print(); //v[j].print(); tmp = tmp + vv * sum % mod - vv * (tot - sum) % mod; tmp = (tmp % mod + mod) % mod; sum = sum - v[j]; //cout << "?" << ans << endl; } //cout << tmp << endl; ans = (ans + tmp * (LL)cc) %mod; } ans = ans * fastpo(6, mod - 2, mod) % mod; cout << ans << endl; }