結果
問題 | No.96 圏外です。 |
ユーザー | anta |
提出日時 | 2014-12-07 20:33:30 |
言語 | C++11 (gcc 11.4.0) |
結果 |
TLE
|
実行時間 | - |
コード長 | 7,264 bytes |
コンパイル時間 | 1,204 ms |
コンパイル使用メモリ | 107,560 KB |
実行使用メモリ | 60,516 KB |
最終ジャッジ日時 | 2024-06-11 16:31:59 |
合計ジャッジ時間 | 7,895 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 13 ms
52,352 KB |
testcase_01 | AC | 13 ms
52,412 KB |
testcase_02 | AC | 13 ms
52,400 KB |
testcase_03 | AC | 2 ms
6,940 KB |
testcase_04 | AC | 18 ms
52,512 KB |
testcase_05 | AC | 21 ms
52,692 KB |
testcase_06 | AC | 25 ms
52,780 KB |
testcase_07 | AC | 30 ms
52,928 KB |
testcase_08 | AC | 43 ms
53,164 KB |
testcase_09 | AC | 50 ms
53,456 KB |
testcase_10 | TLE | - |
testcase_11 | -- | - |
testcase_12 | -- | - |
testcase_13 | -- | - |
testcase_14 | -- | - |
testcase_15 | -- | - |
testcase_16 | -- | - |
testcase_17 | -- | - |
testcase_18 | -- | - |
testcase_19 | -- | - |
testcase_20 | -- | - |
testcase_21 | -- | - |
testcase_22 | -- | - |
testcase_23 | -- | - |
testcase_24 | -- | - |
testcase_25 | -- | - |
testcase_26 | -- | - |
testcase_27 | -- | - |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:123:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 123 | scanf("%d%d", &X[i], &Y[i]); | ~~~~~^~~~~~~~~~~~~~~~~~~~~~
ソースコード
#define _CRT_SECURE_NO_WARNINGS #include <string> #include <vector> #include <algorithm> #include <numeric> #include <set> #include <map> #include <queue> #include <iostream> #include <sstream> #include <cstdio> #include <cmath> #include <ctime> #include <cstring> #include <cctype> #include <cassert> #include <limits> #include <functional> #include <unordered_map> #define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i)) #define rer(i,l,u) for(int (i)=(int)(l);(i)<=(int)(u);++(i)) #define reu(i,l,u) for(int (i)=(int)(l);(i)<(int)(u);++(i)) #if defined(_MSC_VER) || __cplusplus > 199711L #define aut(r,v) auto r = (v) #else #define aut(r,v) typeof(v) r = (v) #endif #define each(it,o) for(aut(it, (o).begin()); it != (o).end(); ++ it) #define all(o) (o).begin(), (o).end() #define pb(x) push_back(x) #define mp(x,y) make_pair((x),(y)) #define mset(m,v) memset(m,v,sizeof(m)) #define INF 0x3f3f3f3f #define INFL 0x3f3f3f3f3f3f3f3fLL using namespace std; typedef vector<int> vi; typedef pair<int,int> pii; typedef vector<pair<int,int> > vpii; typedef long long ll; typedef vector<long long> vl; typedef pair<long long,long long> pll; typedef vector<pair<long long,long long> > vpll; typedef vector<string> vs; typedef long double ld; template<typename T, typename U> inline void amin(T &x, U y) { if(y < x) x = y; } template<typename T, typename U> inline void amax(T &x, U y) { if(x < y) x = y; } const int C = 317; const int circle[C] = {-200210,-180193,-180192,-180191,-180190,-180189,-180188,-180187,-180186,-180185,-160174,-160173,-160172,-160171,-160170,-160169,-160168,-160167,-160166,-160165,-160164,-160163,-160162,-140154,-140153,-140152,-140151,-140150,-140149,-140148,-140147,-140146,-140145,-140144,-140143,-140142,-140141,-140140,-120134,-120133,-120132,-120131,-120130,-120129,-120128,-120127,-120126,-120125,-120124,-120123,-120122,-120121,-120120,-120119,-120118,-100113,-100112,-100111,-100110,-100109,-100108,-100107,-100106,-100105,-100104,-100103,-100102,-100101,-100100,-100099,-100098,-100097,-80093,-80092,-80091,-80090,-80089,-80088,-80087,-80086,-80085,-80084,-80083,-80082,-80081,-80080,-80079,-80078,-80077,-80076,-80075,-60072,-60071,-60070,-60069,-60068,-60067,-60066,-60065,-60064,-60063,-60062,-60061,-60060,-60059,-60058,-60057,-60056,-60055,-60054,-40051,-40050,-40049,-40048,-40047,-40046,-40045,-40044,-40043,-40042,-40041,-40040,-40039,-40038,-40037,-40036,-40035,-40034,-40033,-20030,-20029,-20028,-20027,-20026,-20025,-20024,-20023,-20022,-20021,-20020,-20019,-20018,-20017,-20016,-20015,-20014,-20013,-20012,-10,-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8,9,10,20012,20013,20014,20015,20016,20017,20018,20019,20020,20021,20022,20023,20024,20025,20026,20027,20028,20029,20030,40033,40034,40035,40036,40037,40038,40039,40040,40041,40042,40043,40044,40045,40046,40047,40048,40049,40050,40051,60054,60055,60056,60057,60058,60059,60060,60061,60062,60063,60064,60065,60066,60067,60068,60069,60070,60071,60072,80075,80076,80077,80078,80079,80080,80081,80082,80083,80084,80085,80086,80087,80088,80089,80090,80091,80092,80093,100097,100098,100099,100100,100101,100102,100103,100104,100105,100106,100107,100108,100109,100110,100111,100112,100113,120118,120119,120120,120121,120122,120123,120124,120125,120126,120127,120128,120129,120130,120131,120132,120133,120134,140140,140141,140142,140143,140144,140145,140146,140147,140148,140149,140150,140151,140152,140153,140154,160162,160163,160164,160165,160166,160167,160168,160169,160170,160171,160172,160173,160174,180185,180186,180187,180188,180189,180190,180191,180192,180193,200210}; int sq(int x) { return x*x; } int pack(int y, int x) { return (y + 10011) * 20021 + (x + 10011); } struct P { typedef int T; typedef ll T2; //T2は{a*b | a:T, b:T}を含むタイプ T x, y; P(T x_, T y_): x(x_), y(y_) {} P(): x(0), y(0) {} }; inline bool operator==(const P& a, const P& b) { return a.x == b.x && a.y == b.y; } inline bool operator<(const P& a, const P& b) { return a.x < b.x || (a.x == b.x && a.y < b.y); } inline P operator+(const P& a, const P& b) { return P(a.x+b.x, a.y+b.y); } inline P operator-(const P& a, const P& b) { return P(a.x-b.x, a.y-b.y); } inline P operator-=(P& a, const P& b) { a.x -= b.x, a.y -= b.y ; return a; } inline P::T2 cross(const P& a, const P& b) { return (P::T2)a.x*b.y - (P::T2)a.y*b.x; } inline P::T2 dot(const P& a, const P& b) { return (P::T2)a.x*b.x + (P::T2)a.y*b.y; } inline P::T2 norm(const P& a) { return (P::T2)a.x*a.x + (P::T2)a.y*a.y; } ostream& operator<<(ostream& out, const P& x) { out << "(" << x.x << ", " << x.y << ")"; return out; } struct L { P a, b; L(const P &a_, const P &b_): a(a_), b(b_) {} const P& operator[](size_t i) const { return i ? b : a; } }; inline int ccw(const P& a, const P& b, const P& c) { int ax = b.x - a.x, ay = b.y - a.y, bx = c.x - a.x, by = c.y - a.y; P::T2 t = (P::T2)ax*by - (P::T2)ay*bx; if (t > 0) return 1; if (t < 0) return -1; if((P::T2)ax*bx + (P::T2)ay*by < 0) return +2; if((P::T2)ax*ax + (P::T2)ay*ay < (P::T2)bx*bx + (P::T2)by*by) return -2; return 0; } vector<P> convex_hull(vector<P> ps) { int n = ps.size(), k = 0; sort(ps.begin(), ps.end()); vector<P> ch(2*n); for (int i = 0; i < n; ch[k++] = ps[i++]) // lower-hull while (k >= 2 && ccw(ch[k-2], ch[k-1], ps[i]) <= 0) --k; for (int i = n-2, t = k+1; i >= 0; ch[k++] = ps[i--]) // upper-hull while (k >= t && ccw(ch[k-2], ch[k-1], ps[i]) <= 0) --k; ch.resize(k-1); return ch; } ll convex_diameter(const vector<P> &pt) { const int n = pt.size(); int is = 0, js = 0; for (int i = 1; i < n; ++i) { if(pt[i].y > pt[is].y) is = i; if(pt[i].y < pt[js].y) js = i; } ll maxd = norm(pt[is]-pt[js]); int i, maxi, j, maxj; i = maxi = is; j = maxj = js; do { if (cross((pt[(i+1)%pt.size()]-pt[i]), (pt[(j+1)%pt.size()]-pt[j])) >= 0) j = (j+1) % n; else i = (i+1) % n; if (norm(pt[i]-pt[j]) > maxd) { maxd = norm(pt[i]-pt[j]); maxi = i; maxj = j; } }while (i != is || j != js); return maxd; } int main() { int N; cin >> N; vector<int> X(N), Y(N); rep(i, N) scanf("%d%d", &X[i], &Y[i]); if(N == 0) { puts("1"); return 0; } vector<bool> bv(20021*20021); map<int,int> a; rep(i, N) { int p = pack(Y[i],X[i]); a.insert(mp(p, i)); bv[p] = true; } vector<bool> vis(N); ll maxd = 0; vector<P> points; vi stk; rep(s, N) if(!vis[s]) { stk.clear(); points.clear(); stk.push_back(s); vis[s] = true; bv[pack(Y[s], X[s])] = false; // cerr << s << ": " << endl; while(!stk.empty()) { int i = stk.back(); stk.pop_back(); int y0 = Y[i], x0 = X[i]; // cerr << "\t" << i << endl; points.push_back(P(x0, y0)); int p0 = pack(y0, x0); rep(k, C) { int p = p0 + circle[k]; if(bv[p]) { auto it = a.find(p); if(it != a.end()) { int j = it->second; if(!vis[j]) { stk.push_back(j); vis[j] = true; } bv[p] = false; } } } } if(points.size() >= 2) { vector<P> ch = convex_hull(points); ll d = convex_diameter(ch); amax(maxd, d); } } double ans = sqrt(maxd * 1.) + 2; printf("%.10f\n", ans); return 0; }