結果
問題 | No.1153 ねこちゃんゲーム |
ユーザー |
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提出日時 | 2020-08-07 22:39:53 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 536 ms / 2,500 ms |
コード長 | 4,793 bytes |
コンパイル時間 | 1,396 ms |
コンパイル使用メモリ | 123,336 KB |
実行使用メモリ | 88,140 KB |
最終ジャッジ日時 | 2024-09-24 22:54:25 |
合計ジャッジ時間 | 25,831 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 40 |
ソースコード
#include<iostream>#include<string>#include<cstdio>#include<vector>#include<cmath>#include<algorithm>#include<functional>#include<iomanip>#include<queue>#include<ciso646>#include<random>#include<map>#include<set>#include<bitset>#include<stack>#include<unordered_map>#include<utility>#include<cassert>#include<complex>#include<numeric>using namespace std;//#define int long longtypedef long long ll;typedef unsigned long long ul;typedef unsigned int ui;constexpr ll mod = 1000000007;const ll INF = mod * mod;typedef pair<int, int>P;#define stop char nyaa;cin>>nyaa;#define rep(i,n) for(int i=0;i<n;i++)#define per(i,n) for(int i=n-1;i>=0;i--)#define Rep(i,sta,n) for(int i=sta;i<n;i++)#define rep1(i,n) for(int i=1;i<=n;i++)#define per1(i,n) for(int i=n;i>=1;i--)#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)#define all(v) (v).begin(),(v).end()typedef pair<ll, ll> LP;typedef long double ld;typedef pair<ld, ld> LDP;const ld eps = 1e-12;const ld pi = acos(-1.0);ll mod_pow(ll x, ll n, ll m) {ll res = 1;while (n) {if (n & 1)res = res * x % m;x = x * x % m; n >>= 1;}return res;}struct modint {ll n;modint() :n(0) { ; }modint(ll m) :n(m) {if (n >= mod)n %= mod;else if (n < 0)n = (n % mod + mod) % mod;}operator int() { return n; }};bool operator==(modint a, modint b) { return a.n == b.n; }modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }modint operator+(modint a, modint b) { return a += b; }modint operator-(modint a, modint b) { return a -= b; }modint operator*(modint a, modint b) { return a *= b; }modint operator^(modint a, ll n) {if (n == 0)return modint(1);modint res = (a * a) ^ (n / 2);if (n % 2)res = res * a;return res;}ll inv(ll a, ll p) {return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);}modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }const int max_n = 1 << 17;modint fact[max_n], factinv[max_n];void init_f() {fact[0] = modint(1);for (int i = 0; i < max_n - 1; i++) {fact[i + 1] = fact[i] * modint(i + 1);}factinv[max_n - 1] = modint(1) / fact[max_n - 1];for (int i = max_n - 2; i >= 0; i--) {factinv[i] = factinv[i + 1] * modint(i + 1);}}modint comb(int a, int b) {if (a < 0 || b < 0 || a < b)return 0;return fact[a] * factinv[b] * factinv[a - b];}const int mn = 1 << 18;struct edge {int to;};using Data = int;vector<edge> G[mn];vector<int> ids[mn];vector<Data> memo[mn];int root;int mex(vector<int> v) {sort(all(v));v.erase(unique(all(v)), v.end());rep(i, v.size())if (i != v[i])return i;return v.size();}int pars[mn];Data dfs(int id, int fr) {pars[id] = fr;Data res;vector<int> v;////initialize//for (edge e : G[id]) {if (e.to == fr)continue;Data nex = dfs(e.to, id);////update with edge//v.push_back(nex);ids[id].push_back(e.to);memo[id].push_back(nex);}////update for returnres = mex(v);//return res;}int grandy[mn];int pargrandy[mn];void invdfs(int id, int fr, Data pre) {vector<Data> v;for (Data d : memo[id])v.push_back(d);if (fr >= 0)v.push_back(pre);int len = v.size();////calcurate id's ansgrandy[id] = mex(v);////Data init_c = 0;//vector<int> cnt(len + 1);rep(i, len) {if (v[i] <= len)cnt[v[i]]++;}int ag = 0;rep(i, len+1)if (cnt[i] == 0) {ag = i; break;}rep(i, ids[id].size()) {int to = ids[id][i];int val = ag;if (v[i] <= len && cnt[v[i]] == 1) {val = min(val, v[i]);}////update for return//pargrandy[to] = val;invdfs(to, id, val);}}void yaru() {dfs(root, -1);invdfs(root, -1, 0);}void solve() {int n; cin >> n;int m; cin >> m;vector<int> a(m);rep(i, m) {cin >> a[i]; a[i]--;}rep(i, n - 1) {int a, b; cin >> a >> b; a--; b--;G[a].push_back({ b }); G[b].push_back({ a });}yaru();int x = 0;rep(i, m) {x ^= grandy[a[i]];}if (x == 0) {cout << -1 << " " << -1 << "\n";}else {int chk = 0;rep(i, m) {int y = x ^ grandy[a[i]];if (y < grandy[a[i]]) {chk = i; break;}}int y = x ^ grandy[a[chk]];if (pars[a[chk]]>=0&&pargrandy[a[chk]] == y) {cout << chk + 1 << " " << pars[a[chk]] + 1 << "\n";}else {rep(j, ids[a[chk]].size()) {if (memo[a[chk]][j] == y) {cout << chk + 1 << " " << ids[a[chk]][j] + 1 << "\n";return;}}assert(false);}}}signed main() {//ios::sync_with_stdio(false);//cin.tie(0);cout << fixed << setprecision(10);//init_f();//expr();//int t; cin >> t; rep(i, t)solve();return 0;}