結果

問題 No.1153 ねこちゃんゲーム
ユーザー heno239
提出日時 2020-08-07 22:39:53
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 536 ms / 2,500 ms
コード長 4,793 bytes
コンパイル時間 1,396 ms
コンパイル使用メモリ 123,336 KB
実行使用メモリ 88,140 KB
最終ジャッジ日時 2024-09-24 22:54:25
合計ジャッジ時間 25,831 ms
ジャッジサーバーID
(参考情報)
judge4 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 40
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
using namespace std;
//#define int long long
typedef long long ll;
typedef unsigned long long ul;
typedef unsigned int ui;
constexpr ll mod = 1000000007;
const ll INF = mod * mod;
typedef pair<int, int>P;
#define stop char nyaa;cin>>nyaa;
#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;
typedef long double ld;
typedef pair<ld, ld> LDP;
const ld eps = 1e-12;
const ld pi = acos(-1.0);
ll mod_pow(ll x, ll n, ll m) {
ll res = 1;
while (n) {
if (n & 1)res = res * x % m;
x = x * x % m; n >>= 1;
}
return res;
}
struct modint {
ll n;
modint() :n(0) { ; }
modint(ll m) :n(m) {
if (n >= mod)n %= mod;
else if (n < 0)n = (n % mod + mod) % mod;
}
operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }
modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }
modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, ll n) {
if (n == 0)return modint(1);
modint res = (a * a) ^ (n / 2);
if (n % 2)res = res * a;
return res;
}
ll inv(ll a, ll p) {
return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }
const int max_n = 1 << 17;
modint fact[max_n], factinv[max_n];
void init_f() {
fact[0] = modint(1);
for (int i = 0; i < max_n - 1; i++) {
fact[i + 1] = fact[i] * modint(i + 1);
}
factinv[max_n - 1] = modint(1) / fact[max_n - 1];
for (int i = max_n - 2; i >= 0; i--) {
factinv[i] = factinv[i + 1] * modint(i + 1);
}
}
modint comb(int a, int b) {
if (a < 0 || b < 0 || a < b)return 0;
return fact[a] * factinv[b] * factinv[a - b];
}
const int mn = 1 << 18;
struct edge {
int to;
};
using Data = int;
vector<edge> G[mn];
vector<int> ids[mn];
vector<Data> memo[mn];
int root;
int mex(vector<int> v) {
sort(all(v));
v.erase(unique(all(v)), v.end());
rep(i, v.size())if (i != v[i])return i;
return v.size();
}
int pars[mn];
Data dfs(int id, int fr) {
pars[id] = fr;
Data res;
vector<int> v;
//
//initialize
//
for (edge e : G[id]) {
if (e.to == fr)continue;
Data nex = dfs(e.to, id);
//
//update with edge
//
v.push_back(nex);
ids[id].push_back(e.to);
memo[id].push_back(nex);
}
//
//update for return
res = mex(v);
//
return res;
}
int grandy[mn];
int pargrandy[mn];
void invdfs(int id, int fr, Data pre) {
vector<Data> v;
for (Data d : memo[id])v.push_back(d);
if (fr >= 0)v.push_back(pre);
int len = v.size();
//
//calcurate id's ans
grandy[id] = mex(v);
//
//
Data init_c = 0;
//
vector<int> cnt(len + 1);
rep(i, len) {
if (v[i] <= len)cnt[v[i]]++;
}
int ag = 0;
rep(i, len+1)if (cnt[i] == 0) {
ag = i; break;
}
rep(i, ids[id].size()) {
int to = ids[id][i];
int val = ag;
if (v[i] <= len && cnt[v[i]] == 1) {
val = min(val, v[i]);
}
//
//update for return
//
pargrandy[to] = val;
invdfs(to, id, val);
}
}
void yaru() {
dfs(root, -1);
invdfs(root, -1, 0);
}
void solve() {
int n; cin >> n;
int m; cin >> m;
vector<int> a(m);
rep(i, m) {
cin >> a[i]; a[i]--;
}
rep(i, n - 1) {
int a, b; cin >> a >> b; a--; b--;
G[a].push_back({ b }); G[b].push_back({ a });
}
yaru();
int x = 0;
rep(i, m) {
x ^= grandy[a[i]];
}
if (x == 0) {
cout << -1 << " " << -1 << "\n";
}
else {
int chk = 0;
rep(i, m) {
int y = x ^ grandy[a[i]];
if (y < grandy[a[i]]) {
chk = i; break;
}
}
int y = x ^ grandy[a[chk]];
if (pars[a[chk]]>=0&&pargrandy[a[chk]] == y) {
cout << chk + 1 << " " << pars[a[chk]] + 1 << "\n";
}
else {
rep(j, ids[a[chk]].size()) {
if (memo[a[chk]][j] == y) {
cout << chk + 1 << " " << ids[a[chk]][j] + 1 << "\n";
return;
}
}
assert(false);
}
}
}
signed main() {
//ios::sync_with_stdio(false);
//cin.tie(0);
cout << fixed << setprecision(10);
//init_f();
//expr();
//int t; cin >> t; rep(i, t)
solve();
return 0;
}
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