結果
| 問題 |
No.195 フィボナッチ数列の理解(2)
|
| コンテスト | |
| ユーザー |
heno239
|
| 提出日時 | 2020-08-09 17:24:58 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 4,463 bytes |
| コンパイル時間 | 1,229 ms |
| コンパイル使用メモリ | 127,848 KB |
| 実行使用メモリ | 11,944 KB |
| 最終ジャッジ日時 | 2024-10-05 02:52:40 |
| 合計ジャッジ時間 | 7,638 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | -- * 3 |
| other | AC * 1 TLE * 1 -- * 20 |
ソースコード
#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
using namespace std;
//#define int long long
typedef long long ll;
typedef unsigned long long ul;
typedef unsigned int ui;
constexpr ll mod = 1000000007;
const ll INF = mod * mod;
typedef pair<int, int>P;
#define stop char nyaa;cin>>nyaa;
#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;
typedef double ld;
typedef pair<ld, ld> LDP;
const ld eps = 1e-12;
const ld pi = acos(-1.0);
ll mod_pow(ll x, ll n, ll m) {
ll res = 1;
while (n) {
if (n & 1)res = res * x % m;
x = x * x % m; n >>= 1;
}
return res;
}
struct modint {
ll n;
modint() :n(0) { ; }
modint(ll m) :n(m) {
if (n >= mod)n %= mod;
else if (n < 0)n = (n % mod + mod) % mod;
}
operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }
modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }
modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, ll n) {
if (n == 0)return modint(1);
modint res = (a * a) ^ (n / 2);
if (n % 2)res = res * a;
return res;
}
ll inv(ll a, ll p) {
return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }
const int max_n = 1 << 17;
modint fact[max_n], factinv[max_n];
void init_f() {
fact[0] = modint(1);
for (int i = 0; i < max_n - 1; i++) {
fact[i + 1] = fact[i] * modint(i + 1);
}
factinv[max_n - 1] = modint(1) / fact[max_n - 1];
for (int i = max_n - 2; i >= 0; i--) {
factinv[i] = factinv[i + 1] * modint(i + 1);
}
}
modint comb(int a, int b) {
if (a < 0 || b < 0 || a < b)return 0;
return fact[a] * factinv[b] * factinv[a - b];
}
typedef vector<vector<ll>> mat;
typedef vector<ll> vec;
mat mtmul(mat& A, mat& B) {
mat C(A.size(), vec(B[0].size()));
rep(i, (int)A.size()) {
rep(k, (int)B.size()) {
rep(j, (int)B[0].size()) {
C[i][j] = (C[i][j] + (A[i][k] * B[k][j]) % mod) % mod;
}
}
}
return C;
}
P normalize(P p) {
while (p.first < p.second&&p.second-p.first<=p.first) {
p = { p.second - p.first,p.first };
}
return p;
}
vector<P> calc(int le, int ri) {
vector<P> res;
mat A = { {1,1},{1,0} };
mat X = { {1,0},{0,1} };
while (true) {
if (X[0][1] * le >= ri)break;
ll dif = ri - X[0][1] * le;
if (dif % X[0][0] == 0) {
P p = { le,dif / X[0][0] };
p=normalize(p); res.push_back(p);
}
X = mtmul(A,X);
}
return res;
}
void solve() {
vector<ll> v(3);
rep(i, 3)cin >> v[i];
sort(all(v));
v.erase(unique(all(v)), v.end());
if (v.size() == 1) {
vector<P> c = calc(1, v[0]);
P mi = c[0];
rep(i, c.size()) {
//cout << c[i].first << " " << c[i].second << "\n";
mi = min(mi, c[i]);
}
cout << mi.first << " " << mi.second << "\n";
}
else if (v.size() == 2) {
vector<P> c = calc(v[0], v[1]);
P mi = c[0];
rep(i, c.size()) {
mi = min(mi, c[i]);
}
cout << mi.first << " " << mi.second << "\n";
}
else {
vector<P> c1 = calc(v[0], v[1]);
vector<P> c2 = calc(v[1], v[0]);
vector<P> c;
for (P p : c1)c.push_back(p);
for (P p : c2)c.push_back(p);
P ans = { mod,mod };
for (P p : c) {
bool valid = false;
int x = p.first, y = p.second;
while (y < v[2]) {
int s = x + y;
if (s == v[2])valid = true;
x = y; y = s;
}
if (valid) {
ans = min(ans, p);
}
}
if (ans.first == mod) {
cout << -1 << "\n";
}
else {
cout << ans.first << " " << ans.second << "\n";
}
}
}
signed main() {
ios::sync_with_stdio(false);
cin.tie(0);
//cout << fixed << setprecision(10);
//init_f();
//expr();
//int t; cin >> t; rep(i, t)
solve();
return 0;
}
heno239