結果

問題 No.314 ケンケンパ
ユーザー pione
提出日時 2020-08-11 04:19:09
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 44 ms / 1,000 ms
コード長 1,942 bytes
コンパイル時間 1,569 ms
コンパイル使用メモリ 166,316 KB
実行使用メモリ 34,560 KB
最終ジャッジ日時 2024-10-09 11:08:10
合計ジャッジ時間 2,436 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 17
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
// #define int long long
#define rep(i, n) for (long long i = (long long)(0); i < (long long)(n); ++i)
#define reps(i, n) for (long long i = (long long)(1); i <= (long long)(n); ++i)
#define rrep(i, n) for (long long i = ((long long)(n)-1); i >= 0; i--)
#define rreps(i, n) for (long long i = ((long long)(n)); i > 0; i--)
#define irep(i, m, n) for (long long i = (long long)(m); i < (long long)(n); ++i)
#define ireps(i, m, n) for (long long i = (long long)(m); i <= (long long)(n); ++i)
#define SORT(v, n) sort(v, v + n);
#define REVERSE(v, n) reverse(v, v+n);
#define vsort(v) sort(v.begin(), v.end());
#define all(v) v.begin(), v.end()
#define mp(n, m) make_pair(n, m);
#define cout(d) cout<<d<<endl;
#define coutd(d) cout<<std::setprecision(10)<<d<<endl;
#define cinline(n) getline(cin,n);
#define replace_all(s, b, a) replace(s.begin(),s.end(), b, a);
#define PI (acos(-1))
#define FILL(v, n, x) fill(v, v + n, x);
#define sz(x) long long(x.size())
using ll = long long;
using vi = vector<int>;
using vvi = vector<vi>;
using vll = vector<ll>;
using vvll = vector<vll>;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using vs = vector<string>;
using vpll = vector<pair<ll, ll>>;
using vtp = vector<tuple<ll,ll,ll>>;
using vb = vector<bool>;
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
const ll INF = 1e9+10;
const ll MOD = 1e9+7;
const ll LINF = 1e18;
ll dp[1001001][4];
signed main()
{
  cin.tie( 0 ); ios::sync_with_stdio( false );
  
  ll n; cin>>n;
  
  dp[0][0]=1;
  rep(i,n){
    (dp[i+1][1]+=dp[i][0])%=MOD;
    (dp[i+1][2]+=dp[i][1])%=MOD;
    (dp[i+1][3]+=dp[i][1])%=MOD;
    (dp[i+1][3]+=dp[i][2])%=MOD;
    (dp[i+1][1]+=dp[i][3])%=MOD;
  }
  
  ll ans=0;
  
  for(ll i=1; i<=3; i++) (ans+=dp[n][i])%=MOD;
  cout<<ans<<endl;
}
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