結果

問題 No.1170 Never Want to Walk
ユーザー hitonanodehitonanode
提出日時 2020-08-14 22:11:55
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 237 ms / 2,000 ms
コード長 5,705 bytes
コンパイル時間 3,002 ms
コンパイル使用メモリ 199,488 KB
最終ジャッジ日時 2025-01-13 00:01:01
ジャッジサーバーID
（参考情報） 		judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 37
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <bits/stdc++.h>
using namespace std;
using lint = long long;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
#define ALL(x) (x).begin(), (x).end()
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
template <typename T> void ndarray(vector<T> &vec, int len) { vec.resize(len); }
template <typename T, typename... Args> void ndarray(vector<T> &vec, int len, Args... args) { vec.resize(len); for (auto &v : vec) ndarray(v, args...); }
template <typename V, typename T> void ndfill(V &x, const T &val) { x = val; }
template <typename V, typename T> void ndfill(vector<V> &vec, const T &val) { for (auto &v : vec) ndfill(v, val); }
template <typename T> bool chmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; }
template <typename T> bool chmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; }
template <typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); }
template <typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); }
template <typename T> vector<T> srtunq(vector<T> vec) { sort(vec.begin(), vec.end()), vec.erase(unique(vec.begin(), vec.end()), vec.end()); return vec; }
template <typename T> istream &operator>>(istream &is, vector<T> &vec) { for (auto &v : vec) is >> v; return is; }
template <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) { os << '['; for (auto v : vec) os << v << ','; os << ']'; return os; }
#if __cplusplus >= 201703L
template <typename... T> istream &operator>>(istream &is, tuple<T...> &tpl) { std::apply([&is](auto &&... args) { ((is >> args), ...);}, tpl); return is; }
template <typename... T> ostream &operator<<(ostream &os, const tuple<T...> &tpl) { std::apply([&os](auto &&... args) { ((os << args << ','), ...);}, tpl); return os; }
#endif
template <typename T> ostream &operator<<(ostream &os, const deque<T> &vec) { os << "deq["; for (auto v : vec) os << v << ','; os << ']'; return os; }
template <typename T> ostream &operator<<(ostream &os, const set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa) { os << '(' << pa.first << ',' << pa.second << ')'; return os; }
template <typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; }
template <typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; }
#ifdef HITONANODE_LOCAL
#define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl
#else
#define dbg(x)
#endif

// UnionFind Tree (0-indexed), based on size of each disjoint set
struct UnionFind
{
    std::vector<int> par, cou;
    UnionFind(int N = 0) : par(N), cou(N) {
        iota(par.begin(), par.end(), 0);
    }
    int find(int x) { return (par[x] == x) ? x : (par[x] = find(par[x])); }
    bool unite(int x, int y) {
        x = find(x), y = find(y);
        if (x == y) return false;
        if (cou[x] < cou[y]) std::swap(x, y);
        par[y] = x, cou[x] += cou[y];
        return true;
    }
    int count(int x) { return cou[find(x)]; }
    bool same(int x, int y) { return find(x) == find(y); }
};


int main()
{
    int N, A, B;
    cin >> N >> A >> B;
    vector<int> X(N);
    cin >> X;
    int sz = 1;
    while (sz <= N) sz *= 2;
    dbg(sz);
    UnionFind uf(sz * 2);
    REP(i, N) uf.cou[sz + i] = 1;

    vector<int> C(sz * 2);
    auto rec = [&](auto &&rec, int i, int lo, int hi, int now, int L, int R) -> void {
        if (R <= L) return;
        if (L >= hi or lo >= R) return;
        dbg(now);
        if (lo <= L and R <= hi)
        {
            C.at(now) = 1;
            uf.unite(i, now);
            return;
        }
        rec(rec, i, lo, hi, now * 2, L, (L + R) / 2);
        rec(rec, i, lo, hi, now * 2 + 1, (L + R) / 2, R);
    };
    REP(i, N)
    {
        int lo = lower_bound(ALL(X), X[i] + A) - X.begin(), hi = upper_bound(ALL(X), X[i] + B) - X.begin();
        dbg((vector<int>{i, lo, hi}));
        rec(rec, sz + i, lo, hi, 1, 0, sz);
        // FOR(j, lo, hi) uf.unite(sz + i, sz + j);
        lo = lower_bound(ALL(X), X[i] - B) - X.begin(), hi = upper_bound(ALL(X), X[i] - A) - X.begin();
        dbg((vector<int>{i, lo, hi}));
        // FOR(j, lo, hi) uf.unite(sz + i, sz + j);
        rec(rec, sz + i, lo, hi, 1, 0, sz);
    }
    REP(i, sz) if (C[i])
    {
        dbg(i);
        uf.unite(i, i * 2);
        uf.unite(i, i * 2 + 1);
        C[i * 2] = 1;
        C[i * 2 + 1] = 1;
    }
    REP(i, N) cout << uf.count(sz + i) << '\n';
}
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