結果
| 問題 |
No.1172 Add Recursive Sequence
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2020-08-14 23:01:42 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
TLE
(最新)
AC
(最初)
|
| 実行時間 | - |
| コード長 | 893 bytes |
| コンパイル時間 | 3,326 ms |
| コンパイル使用メモリ | 216,596 KB |
| 最終ジャッジ日時 | 2025-01-13 00:34:36 |
|
ジャッジサーバーID (参考情報) |
judge2 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 14 TLE * 2 |
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:32:42: warning: format ‘%d’ expects argument of type ‘int’, but argument 2 has type ‘ll’ {aka ‘long long int’} [-Wformat=]
32 | for (int i = 0; i < N; ++i) printf("%d\n", res[i] % MOD);
| ~^ ~~~~~~~~~~~~
| | |
| int ll {aka long long int}
| %lld
main.cpp:17:10: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
17 | scanf("%d%d%d", &K, &N, &M);
| ~~~~~^~~~~~~~~~~~~~~~~~~~~~
main.cpp:18:38: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
18 | for (int i = 0; i < K; ++i) scanf("%d", A + i);
| ~~~~~^~~~~~~~~~~~~
main.cpp:19:38: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
19 | for (int i = 0; i < K; ++i) scanf("%d", C + i);
| ~~~~~^~~~~~~~~~~~~
main.cpp:29:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
29 | scanf("%d%d", &L, &R);
| ~~~~~^~~~~~~~~~~~~~~~
ソースコード
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
constexpr int MOD = (int)1e9 + 7;
constexpr int MX = 100000;
constexpr int MX_K = 200;
int K, N, M, L, R;
int A[MX + 1], C[MX_K + 1];
ll tmp, res[MX + 1];
int main() {
scanf("%d%d%d", &K, &N, &M);
for (int i = 0; i < K; ++i) scanf("%d", A + i);
for (int i = 0; i < K; ++i) scanf("%d", C + i);
for (int i = K; i < N; ++i) {
tmp = 0;
for (int j = 0; j < K; ++j) {
tmp += ll(C[j]) * A[i - 1 - j];
tmp %= MOD;
}
A[i] = tmp;
}
for (int i = 0; i < M; ++i) {
scanf("%d%d", &L, &R);
for (int j = L; j < R; ++j) res[j] += A[j - L];
}
for (int i = 0; i < N; ++i) printf("%d\n", res[i] % MOD);
}