結果

問題 No.202 1円玉投げ
ユーザー heno239
提出日時 2020-08-15 10:31:18
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 760 ms / 5,000 ms
コード長 3,079 bytes
コンパイル時間 1,307 ms
コンパイル使用メモリ 116,692 KB
実行使用メモリ 320,640 KB
最終ジャッジ日時 2024-12-22 12:02:06
合計ジャッジ時間 9,845 ms
ジャッジサーバーID
(参考情報)
judge2 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 38
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
using namespace std;
//#define int long long
typedef long long ll;
typedef unsigned long long ul;
typedef unsigned int ui;
constexpr ll mod = 1000000009;
const ll INF = mod * mod;
typedef pair<int, int>P;
#define stop char nyaa;cin>>nyaa;
#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;
typedef double ld;
typedef pair<ld, ld> LDP;
const ld eps = 1e-12;
const ld pi = acos(-1.0);
ll mod_pow(ll x, ll n, ll m = mod) {
ll res = 1;
while (n) {
if (n & 1)res = res * x % m;
x = x * x % m; n >>= 1;
}
return res;
}
struct modint {
ll n;
modint() :n(0) { ; }
modint(ll m) :n(m) {
if (n >= mod)n %= mod;
else if (n < 0)n = (n % mod + mod) % mod;
}
operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }
modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }
modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, ll n) {
if (n == 0)return modint(1);
modint res = (a * a) ^ (n / 2);
if (n % 2)res = res * a;
return res;
}
ll inv(ll a, ll p) {
return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }
ll gcd(ll a, ll b) {
if (a < b)swap(a, b);
while (b) {
ll r = a % b; a = b; b = r;
}
return a;
}
bool great(string a, string b) {
if (a.size() != b.size())return a.size() < b.size();
else return a < b;
}
bool exi[20001][20001];
void solve() {
int n; cin >> n;
vector<P> v;
for (int x = -20; x <= 20; x++) {
for (int y = -20; y <= 20; y++) {
if (x * x + y * y < 400)v.push_back({ x,y });
}
}
int ans = 0;
vector<int> x(n), y(n);
rep(i, n)cin >> x[i] >> y[i];
rep(i, n) {
bool valid= true;
for (P p : v) {
int cx = p.first + x[i];
int cy = p.second + y[i];
if (cx >= 0 && cy >= 0 && cx <= 20000 && cy <= 20000) {
if (exi[cx][cy]) {
valid = false; break;
}
}
}
if (valid) {
ans++; exi[x[i]][y[i]] = true;
}
}
cout << ans << "\n";
}
signed main() {
ios::sync_with_stdio(false);
cin.tie(0);
//cout << fixed << setprecision(10);
//init_f();
//init();
//expr();
//int t; cin >> t; rep(i, t)
solve();
return 0;
}
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