結果

問題 No.1172 Add Recursive Sequence
ユーザー fastmathfastmath
提出日時 2020-08-16 22:52:30
言語 C++17(clang)
(17.0.6 + boost 1.83.0)
結果
AC  
実行時間 633 ms / 4,000 ms
コード長 3,762 bytes
コンパイル時間 1,916 ms
コンパイル使用メモリ 164,976 KB
実行使用メモリ 168,920 KB
最終ジャッジ日時 2024-04-19 18:34:39
合計ジャッジ時間 5,014 ms
ジャッジサーバーID
(参考情報)
judge5 / judge1
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 46 ms
166,660 KB
testcase_01 AC 44 ms
166,768 KB
testcase_02 AC 44 ms
166,588 KB
testcase_03 AC 45 ms
166,672 KB
testcase_04 AC 43 ms
166,656 KB
testcase_05 AC 43 ms
166,664 KB
testcase_06 AC 44 ms
166,664 KB
testcase_07 AC 44 ms
166,712 KB
testcase_08 AC 46 ms
166,656 KB
testcase_09 AC 45 ms
166,828 KB
testcase_10 AC 55 ms
166,944 KB
testcase_11 AC 55 ms
167,040 KB
testcase_12 AC 53 ms
166,980 KB
testcase_13 AC 53 ms
166,852 KB
testcase_14 AC 133 ms
168,900 KB
testcase_15 AC 108 ms
168,896 KB
testcase_16 AC 633 ms
168,920 KB
testcase_17 AC 586 ms
168,916 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include<bits/stdc++.h>
using namespace std;
#define int long long
#define ii pair <int, int>
#define app push_back
#define all(a) a.begin(), a.end()
#define bp __builtin_popcountll
#define ll long long
#define mp make_pair
#define f first
#define s second
#define Time (double)clock()/CLOCKS_PER_SEC
#define debug(x) std::cout << #x << ": " << x << '\n';

const int N = 1e5+7, MOD = 1e9+7;
//need define int long long
int mod(int n) {
    n %= MOD;
    if (n < 0) return n + MOD;
    else return n;
}   
int fp(int a, int p) {
    int ans = 1, c = a;
    for (int i = 0; (1ll << i) <= p; ++i) {
        if ((p >> i) & 1) ans = mod(ans * c);
        c = mod(c * c);
    }   
    return ans;
}   
int dv(int a, int b) { return mod(a * fp(b, MOD - 2)); }

struct M {
ll x;
M (int x_) {
    x = mod(x_);
}   
M () {
    x = 0;
}
M operator + (M y) {
    int ans = x + y.x;
    if (ans >= MOD)
        ans -= MOD;
    return M(ans);
}
M operator - (M y) {
    int ans = x - y.x;
    if (ans < 0)
        ans += MOD;
    return M(ans);            
}   
M operator * (M y) {
    return M(x * y.x % MOD);   
}   
M operator / (M y) {
    return M(x * fp(y.x, MOD - 2) % MOD);
}   
M operator + (int y) {
    return (*this) + M(y);
}
M operator - (int y) {
    return (*this) - M(y);
}   
M operator * (int y) {
    return (*this) * M(y);
}   
M operator / (int y) {
    return (*this) / M(y);
}   
M operator ^ (int p) {
    return M(fp(x, p));
}   
void operator += (M y) {
    *this = *this + y;
}   
void operator -= (M y) {
    *this = *this - y;
}   
void operator *= (M y) {
    *this = *this * y;
}
void operator /= (M y) {
    *this = *this / y;
}   
void operator += (int y) {
    *this = *this + y;
}   
void operator -= (int y) {
    *this = *this - y;
}   
void operator *= (int y) {
    *this = *this * y;
}
void operator /= (int y) {
    *this = *this / y;
}   
void operator ^= (int p) {
    *this = *this ^ p;
}
};  

M f[N], inv[N];
void prec() {
    f[0] = M(1);
    for (int i = 1; i < N; ++i)
        f[i] = f[i - 1] * M(i);
    inv[N - 1] = f[N - 1] ^ (MOD - 2);
    for (int i = N - 2; i >= 0; --i)
        inv[i] = inv[i + 1] * M(i + 1);
}
M C(int n, int k) {
    if (n < k)
        return M(0);
    else
        return f[n] * inv[k] * inv[n - k];
}   

const int K = 207;
M up[N][K];

signed main() {
    #ifdef HOME
    freopen("input.txt", "r", stdin);
    #else
    #define endl '\n'
    ios_base::sync_with_stdio(0); cin.tie(0);
    #endif
    int k, n, m;
    cin >> k >> n >> m;
    vector <M> a(k);
    for (int i = 0; i < k; ++i)
        cin >> a[i].x;
    vector <M> c(k);
    for (int i = 0; i < k; ++i)
        cin >> c[i].x;

    while (a.size() <= n) {
        M x(0);
        int sz = a.size();
        for (int i = 0; i < k; ++i)
            x += c[i] * a[sz - i - 1];
        a.app(x);                
    }   

    #ifdef HOME
    for (auto e : a)
        cout << e.x << endl;
    cout << endl;
    #endif    

    vector <M> add(n);
    for (int i = 0; i < m; ++i) {
        int l, r;
        cin >> l >> r;
        r--;
        int len = r - l + 1;
        for (int j = 0; j < min(len, k); ++j) {
            add[l + j] += a[j];
        }   
        if (len >= k) {            
            for (int i = 0; i < k; ++i)
                up[l + k][i] += a[i];
            for (int i = 0; i < k; ++i) 
                up[r + 1][i] -= a[r + 1 - l - k + i];
        }   
    }   

    vector <M> lf(n);
    for (int i = 0; i < n; ++i) {
        if (i >= k) {
            for (int j = 0; j < k; ++j) 
                lf[i - k + j] += up[i][j];                
            for (int j = 0; j < k; ++j)
                lf[i] += lf[i - 1 - j] * c[j];                    
        }   
        cout << (lf[i] + add[i]).x << endl;
    }   
}
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