結果
問題 |
No.1102 Remnants
|
ユーザー |
![]() |
提出日時 | 2020-08-19 13:53:03 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 83 ms / 2,000 ms |
コード長 | 2,235 bytes |
コンパイル時間 | 1,321 ms |
コンパイル使用メモリ | 116,852 KB |
最終ジャッジ日時 | 2025-01-13 03:47:16 |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 25 |
コンパイルメッセージ
main.cpp: In function ‘void get(std::vector<long long int>&)’: main.cpp:25:38: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 25 | void get(vll &a){re(i,a.size()) scanf("%lld",&a[i]);} | ~~~~~^~~~~~~~~~~~~~ main.cpp: In function ‘void get(std::vector<std::vector<long long int> >&)’: main.cpp:26:56: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 26 | void get(vvl &a){re(i,a.size()) re(j,a[0].size()) scanf("%lld",&a[i][j]);} | ~~~~~^~~~~~~~~~~~~~~~~
ソースコード
#include <iostream> #include <string> #include <vector> #include <queue> #include <deque> #include <algorithm> #include <set> #include <map> #include <bitset> #include <cmath> #include <functional> #include <iomanip> #define vll vector<ll> #define vvvl vector<vvl> #define vvl vector<vector<ll>> #define VV(a, b, c, d) vector<vector<d>>(a, vector<d>(b, c)) #define VVV(a, b, c, d) vector<vvl>(a, vvl(b, vll (c, d))); #define re(c, b) for(ll c=0;c<b;c++) #define rep(a,b,c) for(ll a=b;a<c;a++) #define all(obj) (obj).begin(), (obj).end() typedef long long int ll; typedef long double ld; using namespace std; void get(vll &a){re(i,a.size()) scanf("%lld",&a[i]);} void get(vvl &a){re(i,a.size()) re(j,a[0].size()) scanf("%lld",&a[i][j]);} void print(vll &a){re(i,a.size()) cout<<a[i]<<(i==a.size()-1?"\n":" ");} void print(vvl &a){re(i,a.size()) re(j,a[0].size())cout<<a[i][j]<<(j==a[0].size()-1?"\n":" ");} #define P 1000000007 #define N_MAX 1000000 vector<ll> fac(N_MAX+1); vector<ll> finv(N_MAX+1); vector<ll> inv(N_MAX+1); ll comb(ll n, ll k){ if(n<0||k<0||n<k) return 0; return (((fac[n]*finv[n-k])%P)*finv[k])%P; } ll perm(ll n, ll k){ if(n<0||k<0||n<k) return 0; return (fac[n]*finv[n-k])%P; } void init(){ fac[0] = finv[0] = fac[1] = finv[1] = inv[1] = 1; for(int i = 2; i <= N_MAX; i++){ fac[i] = (fac[i-1]*i)%P; inv[i] = ((-(P/i)*inv[P%i])%P+P)%P; finv[i] = (finv[i-1]*inv[i])%P; } } ll pp(ll a, ll b){ return (a * b)%P;} ll mpow(ll a, ll b, ll p = -1){ ll ret = 1, num = a; if(p==-1){ while(b>0){ if(b%2) ret *= num; num = num * num; b /= 2; } }else{ while(b>0){ if(b%2) ret = (ret*num)%p; num = (num*num)%p; b /= 2; } } return ret; } int main() { init(); ll n, k;std::cin >> n >> k; vll a(n);get(a); ll ans = 0; vll lc(n, 0), rc(n, 0); lc[0] = 1; rc[n-1] = 1; for(ll i=1;i<n;i++){ ll pre = lc[i-1]; pre = pp(pre, i+k); pre = pp(pre, inv[i]); lc[i] = pre; } for(int i=n-2;i>=0;i--){ ll pre = rc[i+1]; pre = pp(pre, n-1-i + k); pre = pp(pre, inv[n-1-i]); rc[i] = pre; } for(int i=0;i<n;i++) { ans = (ans + ((a[i] * pp(lc[i], rc[i]))%P))%P; } std::cout << ans << '\n'; }