結果

問題 No.255 Splarrraaay ｽﾌﾟﾗｰﾚｪｰｰｲ
コンテスト
ユーザー heno239
提出日時 2020-08-20 13:32:31
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 5,379 bytes
コンパイル時間 1,976 ms
コンパイル使用メモリ 139,844 KB
実行使用メモリ 90,584 KB
最終ジャッジ日時 2024-10-13 08:12:53
合計ジャッジ時間 14,744 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 2 WA * 8
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp:29:20: warning: integer overflow in expression of type 'long long int' results in '-5973893300308410287' [-Woverflow]
   29 | const ll INF = mod * mod;
      |                ~~~~^~~~~

ソースコード

diff # 

#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
using namespace std;

//#define int long long
typedef long long ll;

typedef unsigned long long ul;
typedef unsigned int ui;
constexpr ll mod = 1000000000000000009;
const ll INF = mod * mod;
typedef pair<int, int>P;
#define stop char nyaa;cin>>nyaa;
#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;
typedef double ld;
typedef pair<ld, ld> LDP;
const ld eps = 1e-12;
const ld pi = acos(-1.0);

ll mod_pow(ll x, ll n, ll m) {
	ll res = 1;
	while (n) {
		if (n & 1)res = res * x % m;
		x = x * x % m; n >>= 1;
	}
	return res;
}
struct modint {
	ll n;
	modint() :n(0) { ; }
	modint(ll m) :n(m) {
		if (n >= mod)n %= mod;
		else if (n < 0)n = (n % mod + mod) % mod;
	}
	operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }
modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }
modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, ll n) {
	if (n == 0)return modint(1);
	modint res = (a * a) ^ (n / 2);
	if (n % 2)res = res * a;
	return res;
}

ll inv(ll a, ll p) {
	return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }

const int max_n = 1 << 2;
modint fact[max_n], factinv[max_n];
void init_f() {
	fact[0] = modint(1);
	for (int i = 0; i < max_n - 1; i++) {
		fact[i + 1] = fact[i] * modint(i + 1);
	}
	factinv[max_n - 1] = modint(1) / fact[max_n - 1];
	for (int i = max_n - 2; i >= 0; i--) {
		factinv[i] = factinv[i + 1] * modint(i + 1);
	}
}
modint comb(int a, int b) {
	if (a < 0 || b < 0 || a < b)return 0;
	return fact[a] * factinv[b] * factinv[a - b];
}

ll gcd(ll a, ll b) {
	if (a < b)swap(a, b);
	while (b) {
		ll r = a % b; a = b; b = r;
	}
	return a;
}

int dx[9] = { -2,-2,-1,-1,1,1,2,2,0 };
int dy[9] = { -1,1,-2,2,-2,2,-1,1,0 };

void modadd(ll& a, ll b) {
	a += b; while (a >= mod)a -= mod;
}
vector<ll> vx;
struct SegT {
private:
	int n; vector<vector<ll>> node;vector<P> lazy;
	const vector<ll> init_c = { 0,0,0,0,0 };
public:
	SegT(int sz) {
		n = 1;
		while (n < sz)n <<= 1;
		node.resize(2 * n - 1, init_c);
		lazy.resize(2 * n - 1, { -1,0 });
	}
	vector<ll> f(vector<ll> a, vector<ll> b) {
		rep(i, 5)a[i]+=b[i]; return a;
	}
	P h(P a, P b) {
		if (a.first != b.first)return a;
		else {
			a.second += b.second; return a;
		}
	}
	void eval(int k, int l, int r) {
		if (lazy[k].first < 0)return;
		rep(i, 5)if (lazy[k].first != i)node[k][i] = 0;
		node[k][lazy[k].first]+=(vx[r] - vx[l])*lazy[k].second;
		if (r - l > 1) {
			lazy[2 * k + 1] = h(lazy[k],lazy[2*k+1]);
			lazy[2 * k + 2] = h(lazy[k],lazy[2*k+2]);
		}
		lazy[k] = P{ -1,0 };
	}
	void add(int x, int a, int b, int k = 0, int l = 0, int r = -1) {
		if (r < 0)r = n;
		eval(k, l, r);
		if (r <= a || b <= l)return;
		if (a <= l && r <= b) {
			lazy[k] = h(P{ x,1 }, lazy[k]);
			eval(k, l, r);
		}
		else {
			add(x, a, b, k * 2 + 1, l, (l + r) / 2);
			add(x, a, b, k * 2 + 2, (l + r) / 2, r);
			node[k] = f(node[k * 2 + 1], node[k * 2 + 2]);
		}
	}
	vector<ll> query(int a, int b, int k = 0, int l = 0, int r = -1) {
		if (r < 0)r = n;
		eval(k, l, r);
		if (r <= a || b <= l)return init_c;
		if (a <= l && r <= b)return node[k];
		else {
			vector<ll> vl = query(a, b, k * 2 + 1, l, (l + r) / 2);
			vector<ll> vr = query(a, b, k * 2 + 2, (l + r) / 2, r);
			return f(vl, vr);
		}
	}
};
void solve() {
	ll n; int q; cin >> n >> q;
	vector<int> t(q);
	vector<ll> l(q), r(q);
	rep(i, q) {
		cin >> t[i] >> l[i] >> r[i];
		r[i]++;
		vx.push_back(l[i]);
		vx.push_back(r[i]);
	}
	vx.push_back(0);
	vx.push_back(n);
	sort(all(vx));
	vx.erase(unique(all(vx)), vx.end());
	rep(i, q) {
		l[i] = lower_bound(all(vx), l[i]) - vx.begin();
		r[i] = lower_bound(all(vx), r[i]) - vx.begin();
	}
	SegT st(vx.size()); vx.push_back(n);
	vector<ll> score(5, 0);
	rep(i, q) {
		if (t[i] == 0) {
			vector<ll> v = st.query(l[i], r[i]);
			ll ma = -1;
			vector<LP> vs;
			rep(j, 5)vs.push_back({ v[j],j });
			sort(all(vs));
			if (vs[3].first != vs[4].first) {
				modadd(score[vs[4].second],vs[4].first);
			}
		}
		else {
			st.add(t[i] - 1, l[i], r[i]);
		}
	}
	vector<ll> v = st.query(0, vx.size());
	rep(i, 5) {
		modadd(score[i],v[i]);
	}
	rep(i, 5) {
		if (i > 0)cout << " ";
		cout << score[i];
	}
	cout << "\n";
}


signed main() {
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout << fixed << setprecision(10);
	//init_f();
	//expr();
	//int t; cin >> t; rep(i, t)
	//while (cin >> n >> m>>s1>>s2>>t, n)
	solve();
	return 0;
}
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