結果

問題 No.1195 数え上げを愛したい（文字列編）
ユーザー heno239heno239
提出日時 2020-08-22 14:32:16
言語 C++14
(gcc 13.2.0 + boost 1.83.0)
結果
AC  
実行時間 2,705 ms / 3,000 ms
コード長 4,944 bytes
コンパイル時間 1,471 ms
コンパイル使用メモリ 123,860 KB
実行使用メモリ 57,080 KB
最終ジャッジ日時 2024-04-23 08:54:48
合計ジャッジ時間 38,728 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge3
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2,696 ms
57,044 KB
testcase_01 AC 2,696 ms
56,904 KB
testcase_02 AC 2,705 ms
57,080 KB
testcase_03 AC 249 ms
29,536 KB
testcase_04 AC 311 ms
29,296 KB
testcase_05 AC 225 ms
46,892 KB
testcase_06 AC 16 ms
19,780 KB
testcase_07 AC 16 ms
20,164 KB
testcase_08 AC 421 ms
23,888 KB
testcase_09 AC 2,532 ms
57,024 KB
testcase_10 AC 1,421 ms
38,424 KB
testcase_11 AC 2,295 ms
55,096 KB
testcase_12 AC 2,110 ms
55,124 KB
testcase_13 AC 1,790 ms
38,516 KB
testcase_14 AC 1,111 ms
37,360 KB
testcase_15 AC 1,339 ms
38,540 KB
testcase_16 AC 1,211 ms
38,384 KB
testcase_17 AC 451 ms
24,432 KB
testcase_18 AC 2,212 ms
54,884 KB
testcase_19 AC 2,127 ms
54,892 KB
testcase_20 AC 1,824 ms
38,520 KB
testcase_21 AC 2,323 ms
52,856 KB
testcase_22 AC 1,774 ms
38,360 KB
testcase_23 AC 18 ms
20,036 KB
testcase_24 AC 17 ms
19,912 KB
testcase_25 AC 16 ms
19,912 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
#include<array>
using namespace std;

//#define int long long
typedef long long ll;

typedef unsigned long long ul;
typedef unsigned int ui;
constexpr ll mod = 998244353;
const ll INF = mod * mod;
typedef pair<int, int>P;
#define stop char nyaa;cin>>nyaa;
#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;
typedef double ld;
typedef pair<ld, ld> LDP;
const ld eps = 1e-12;
const ld pi = acosl(-1.0);

ll mod_pow(ll x, ll n, ll m) {
	ll res = 1;
	while (n) {
		if (n & 1)res = res * x % m;
		x = x * x % m; n >>= 1;
	}
	return res;
}
struct modint {
	ll n;
	modint() :n(0) { ; }
	modint(ll m) :n(m) {
		if (n >= mod)n %= mod;
		else if (n < 0)n = (n % mod + mod) % mod;
	}
	operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }
modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }
modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, ll n) {
	if (n == 0)return modint(1);
	modint res = (a * a) ^ (n / 2);
	if (n % 2)res = res * a;
	return res;
}

ll inv(ll a, ll p) {
	return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }

const int max_n = 1 << 20;
modint fact[max_n], factinv[max_n];
void init_f() {
	fact[0] = modint(1);
	for (int i = 0; i < max_n - 1; i++) {
		fact[i + 1] = fact[i] * modint(i + 1);
	}
	factinv[max_n - 1] = modint(1) / fact[max_n - 1];
	for (int i = max_n - 2; i >= 0; i--) {
		factinv[i] = factinv[i + 1] * modint(i + 1);
	}
}
modint comb(int a, int b) {
	if (a < 0 || b < 0 || a < b)return 0;
	return fact[a] * factinv[b] * factinv[a - b];
}

ul gcd(ul a, ul b) {
	if (a < b)swap(a, b);
	while (b) {
		ul r = a % b; a = b; b = r;
	}
	return a;
}
ll mod_pow(ll a, ll n) {
	ll res = 1;
	while (n) {
		if (n & 1)res = res * a % mod;
		a = a * a % mod; n >>= 1;
	}
	return res;
}
ll mod_inverse(ll a) {
	return mod_pow(a, mod - 2);
}
ll root[24], invroot[24];
void init() {
	rep(i, 24) {
		int n = (1 << i);
		root[i] = mod_pow(3, (mod - 1) / n);
		invroot[i] = mod_inverse(root[i]);
	}
}
typedef vector <ll> poly;
poly dft(poly f, bool inverse = false) {
	int n = f.size(); int i, j, k;
	//bit左右反転
	for (i = 0, j = 1; j < n - 1; j++) {
		for (k = n >> 1; k > (i ^= k); k >>= 1);
		if (i > j)swap(f[i], f[j]);
	}
	for (int j = 1; (1 << j) <= n; j++) {
		int m = 1 << j;
		ll zeta = root[j];
		if (inverse)zeta = invroot[j];
		for (i = 0; i < n; i += m) {
			ll powzeta = 1;
			for (k = i; k < i + m / 2; k++) {
				ll t1 = f[k], t2 = powzeta * f[k + m / 2] % mod;
				f[k] = t1 + t2; while (f[k] >= mod)f[k] -= mod;
				f[k + m / 2] = t1 - t2 + mod; while (f[k + m / 2] >= mod)f[k + m / 2] -= mod;
				(powzeta *= zeta) %= mod;
			}
		}
	}
	if (inverse) {
		ll rv = mod_inverse(n);
		for (i = 0; i < n; i++) {
			(f[i] *= rv) %= mod;
		}
	}
	return f;
}
poly multiply(poly g, poly h) {
	int n = 1;
	int pi = 0, qi = 0;
	rep(i, g.size())if (g[i])pi = i;
	rep(i, h.size())if (h[i])qi = i;
	int sz = pi + qi + 2;
	while (n < sz)n *= 2;
	g.resize(n); h.resize(n);
	/*while (g.size() < n) {
	g.push_back(0);
	}
	while (h.size() < n) {
	h.push_back(0);
	}*/
	poly gg = dft(g);
	poly hh = dft(h);
	poly ff; ff.resize(n);
	rep(i, n) {
		ff[i] = gg[i] * hh[i] % mod;
	}
	return dft(ff, true);
}

void solve() {
	init();
	int alf[26] = {};
	string s; cin >> s;
	rep(i, s.size())alf[s[i] - 'a']++;
	sort(alf,alf+26);
	vector<ll>dp = { 1 };
	rep(i, 26) {
		int c = alf[i];
		if (c == 0)continue;
		poly p(c + 1);
		rep(j, c + 1) {
			p[j] = factinv[j];
		}
		poly q = dp;
		rep(j, dp.size()) {
			q[j] = q[j] * (ll)factinv[j] % mod;
		}
		poly r = multiply(p, q);
		rep(j, r.size()) {
			r[j] = r[j] * (ll)fact[j] % mod;
		}
		swap(dp, r);
	}
	modint ans = 0;
	for (int i = 1; i < dp.size(); i++)ans += dp[i];
	cout << ans << "\n";

}

signed main() {
    ios::sync_with_stdio(false);
	cin.tie(0);
	//cout << fixed << setprecision(10);
	init_f();
	//expr();
	//int t; cin >> t; rep(i, t)
	//while (cin >> n >> m>>s1>>s2>>t, n)
	solve();
	return 0;
}
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