結果

問題 No.1192 半部分列
ユーザー hitonanodehitonanode
提出日時 2020-08-22 15:05:00
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 5,009 bytes
コンパイル時間 2,287 ms
コンパイル使用メモリ 207,856 KB
実行使用メモリ 24,936 KB
最終ジャッジ日時 2024-10-15 09:22:26
合計ジャッジ時間 3,538 ms
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,816 KB
testcase_01 AC 2 ms
6,816 KB
testcase_02 AC 2 ms
6,816 KB
testcase_03 AC 2 ms
6,816 KB
testcase_04 AC 2 ms
6,816 KB
testcase_05 AC 2 ms
6,820 KB
testcase_06 AC 38 ms
24,808 KB
testcase_07 WA -
testcase_08 WA -
testcase_09 WA -
testcase_10 AC 2 ms
6,820 KB
testcase_11 WA -
testcase_12 WA -
testcase_13 WA -
testcase_14 AC 30 ms
17,152 KB
testcase_15 WA -
testcase_16 WA -
testcase_17 WA -
testcase_18 WA -
testcase_19 WA -
testcase_20 WA -
testcase_21 AC 23 ms
13,952 KB
testcase_22 AC 2 ms
6,816 KB
testcase_23 WA -
testcase_24 AC 10 ms
7,040 KB
testcase_25 AC 20 ms
12,288 KB
testcase_26 AC 21 ms
12,416 KB
testcase_27 AC 18 ms
13,688 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;
using lint = long long;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
#define ALL(x) (x).begin(), (x).end()
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
template <typename T> void ndarray(vector<T> &vec, int len) { vec.resize(len); }
template <typename T, typename... Args> void ndarray(vector<T> &vec, int len, Args... args) { vec.resize(len); for (auto &v : vec) ndarray(v, args...); }
template <typename V, typename T> void ndfill(V &x, const T &val) { x = val; }
template <typename V, typename T> void ndfill(vector<V> &vec, const T &val) { for (auto &v : vec) ndfill(v, val); }
template <typename T> bool chmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; }
template <typename T> bool chmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; }
template <typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); }
template <typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); }
template <typename T> vector<T> srtunq(vector<T> vec) { sort(vec.begin(), vec.end()), vec.erase(unique(vec.begin(), vec.end()), vec.end()); return vec; }
template <typename T> istream &operator>>(istream &is, vector<T> &vec) { for (auto &v : vec) is >> v; return is; }
template <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) { os << '['; for (auto v : vec) os << v << ','; os << ']'; return os; }
#if __cplusplus >= 201703L
template <typename... T> istream &operator>>(istream &is, tuple<T...> &tpl) { std::apply([&is](auto &&... args) { ((is >> args), ...);}, tpl); return is; }
template <typename... T> ostream &operator<<(ostream &os, const tuple<T...> &tpl) { std::apply([&os](auto &&... args) { ((os << args << ','), ...);}, tpl); return os; }
#endif
template <typename T> ostream &operator<<(ostream &os, const deque<T> &vec) { os << "deq["; for (auto v : vec) os << v << ','; os << ']'; return os; }
template <typename T> ostream &operator<<(ostream &os, const set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa) { os << '(' << pa.first << ',' << pa.second << ')'; return os; }
template <typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; }
template <typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; }
#ifdef HITONANODE_LOCAL
#define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl
#else
#define dbg(x)
#endif

vector<int> Solve(string S, string T)
{
    vector<int> reqlen(S.length());
    int tmp = 0;
    REP(i, S.length())
    {
        while (tmp < T.length() and S[i] != T[tmp]) tmp++;
        reqlen[i] = ++tmp;
    }
    return reqlen;
}

vector<vector<int>> buildNext(string T)
{
    vector<vector<int>> nxt(26, vector<int>(T.length() + 1, T.length() + 1));
    IREP(i, T.length())
    {
        REP(d, 26)
        nxt[d][i] = nxt[d][i + 1];
        nxt[T[i] - 'a'][i] = i;
    }
    return nxt;
}
int main()
{
    string S, T;
    cin >> S >> T;

    auto Srev = S, Trev = T;
    reverse(ALL(Srev));
    reverse(ALL(Trev));
    auto vb = Solve(Srev, Trev);
    dbg(vb);
    reverse(vb.begin(), vb.end());

    auto Snxt = buildNext(S), Tnxt = buildNext(T);
    int Scur = 0, Tcur = 0;
    string ret;
    while (Scur < S.length())
    {
        int nxtc = -1;
        REP(d, 26) if (Snxt[d][Scur] < S.length())
        {
            if (vb[Snxt[d][Scur]] + Tcur > T.length())
            {
                nxtc = d;
                break;
            }
        }
        if (nxtc < 0)
        {
            puts("-1");
            return 0;
        }
        ret += 'a' + nxtc;
        Scur = Snxt[nxtc][Scur] + 1;
        Tcur = Tnxt[nxtc][Tcur] + 1;
    }
    cout << ret << '\n';
}
0