結果

問題 No.1200 お菓子配り-3
ユーザー hitonanode
提出日時 2020-08-28 21:32:45
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
(最新)
AC  
(最初)
実行時間 -
コード長 6,559 bytes
コンパイル時間 2,710 ms
コンパイル使用メモリ 207,292 KB
最終ジャッジ日時 2025-01-13 16:41:15
ジャッジサーバーID
(参考情報)
judge4 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 29 WA * 2
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
using lint = long long;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
#define ALL(x) (x).begin(), (x).end()
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
template <typename T> void ndarray(vector<T> &vec, int len) { vec.resize(len); }
template <typename T, typename... Args> void ndarray(vector<T> &vec, int len, Args... args) { vec.resize(len); for (auto &v : vec) ndarray(v, args
    ...); }
template <typename V, typename T> void ndfill(V &x, const T &val) { x = val; }
template <typename V, typename T> void ndfill(vector<V> &vec, const T &val) { for (auto &v : vec) ndfill(v, val); }
template <typename T> bool chmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; }
template <typename T> bool chmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; }
template <typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l
    .second + r.second); }
template <typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l
    .second - r.second); }
template <typename T> vector<T> srtunq(vector<T> vec) { sort(vec.begin(), vec.end()), vec.erase(unique(vec.begin(), vec.end()), vec.end()); return
    vec; }
template <typename T> istream &operator>>(istream &is, vector<T> &vec) { for (auto &v : vec) is >> v; return is; }
template <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) { os << '['; for (auto v : vec) os << v << ','; os << ']'; return os; }
#if __cplusplus >= 201703L
template <typename... T> istream &operator>>(istream &is, tuple<T...> &tpl) { std::apply([&is](auto &&... args) { ((is >> args), ...);}, tpl); return
    is; }
template <typename... T> ostream &operator<<(ostream &os, const tuple<T...> &tpl) { std::apply([&os](auto &&... args) { ((os << args << ','), ...);},
    tpl); return os; }
#endif
template <typename T> ostream &operator<<(ostream &os, const deque<T> &vec) { os << "deq["; for (auto v : vec) os << v << ','; os << ']'; return os;
    }
template <typename T> ostream &operator<<(ostream &os, const set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return
    os; }
template <typename T> ostream &operator<<(ostream &os, const multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os;
    }
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}';
    return os; }
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa) { os << '(' << pa.first << ',' << pa.second << ')';
    return os; }
template <typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v
    .second << ','; os << '}'; return os; }
template <typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first <<
    "=>" << v.second << ','; os << '}'; return os; }
#ifdef HITONANODE_LOCAL
#define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl
#else
#define dbg(x)
#endif
// Sieve of Eratosthenes
// (*this)[i] = (divisor of i, greater than 1)
// Example: [0, 1, 2, 3, 2, 5, 3, 7, 2, 3, 2, 11, ...]
// Complexity: Space O(MAXN), Time (construction) O(MAXNloglogMAXN)
struct SieveOfEratosthenes : std::vector<int>
{
std::vector<int> primes;
SieveOfEratosthenes(int MAXN) : std::vector<int>(MAXN + 1) {
std::iota(begin(), end(), 0);
for (int i = 2; i <= MAXN; i++) {
if ((*this)[i] == i) {
primes.push_back(i);
for (int j = i; j <= MAXN; j += i) (*this)[j] = i;
}
}
}
using T = long long int;
// Prime factorization for x <= MAXN^2
// Complexity: O(log x) (x <= MAXN)
// O(MAXN / logMAXN) (MAXN < x <= MAXN^2)
std::map<T, int> Factorize(T x) {
assert(x <= 1LL * (int(size()) - 1) * (int(size()) - 1));
std::map<T, int> ret;
if (x < int(size())) {
while (x > 1) {
ret[(*this)[x]]++;
x /= (*this)[x];
}
}
else {
for (auto p : primes) {
while (!(x % p)) x /= p, ret[p]++;
if (x == 1) break;
}
if (x > 1) ret[x]++;
}
return ret;
}
std::vector<T> Divisors(T x) {
std::vector<T> ret{1};
for (auto p : Factorize(x)) {
int n = ret.size();
for (int i = 0; i < n; i++) {
for (T a = 1, d = 1; d <= p.second; d++) {
a *= p.first;
ret.push_back(ret[i] * a);
}
}
}
return ret; // Not sorted
}
// Moebius function Table
// return: [0=>0, 1=>1, 2=>-1, 3=>-1, 4=>0, 5=>-1, 6=>1, 7=>-1, 8=>0, ...]
std::vector<int> GenerateMoebiusFunctionTable() {
std::vector<int> ret(size());
for (int i = 1; i < int(size()); i++) {
if (i == 1) ret[i] = 1;
else if ((i / (*this)[i]) % (*this)[i] == 0) ret[i] = 0;
else ret[i] = -ret[i / (*this)[i]];
}
return ret;
}
};
SieveOfEratosthenes sieve(40000);
long long solve()
{
int X, Y;
cin >> X >> Y;
if (X == Y)
{
auto f = sieve.Factorize(X);
int cnt = 1;
for (auto p : f)
{
cnt *= p.second + 1;
}
return X - 1 + cnt - 1;
}
auto f = sieve.Divisors(abs(X - Y));
int ret = 0;
for (auto aa : f)
{
int a = aa + 1;
if ((X + Y) % (a + 1) == 0)
{
int bplusc = (X + Y) / (a + 1);
int bminusc = abs(X - Y) / (a - 1);
if ((bplusc + bminusc) % 2 == 0 and bplusc > bminusc) ret++;
}
}
return ret;
}
int main()
{
int S;
cin >> S;
while (S--) cout << solve() << ('\n');
}
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