結果
問題 | No.1200 お菓子配り-3 |
ユーザー |
|
提出日時 | 2020-08-28 22:02:44 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 2,403 bytes |
コンパイル時間 | 4,320 ms |
コンパイル使用メモリ | 197,772 KB |
最終ジャッジ日時 | 2025-01-13 17:36:17 |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 29 WA * 2 |
ソースコード
#include <bits/stdc++.h>#ifdef DEBUG#include <Mylib/Debug/debug.cpp>#else#define dump(...) ((void)0)#endiftemplate <typename T, typename U>bool chmin(T &a, const U &b){return (a > b ? a = b, true : false);}template <typename T, typename U>bool chmax(T &a, const U &b){return (a < b ? a = b, true : false);}template <typename T, size_t N, typename U>void fill_array(T (&a)[N], const U &v){std::fill((U*)a, (U*)(a + N), v);}template <typename T>auto make_vector(int n, int m, const T &value){return std::vector<std::vector<T>>(n, std::vector<T>(m, value));}template <typename T>std::ostream& operator<<(std::ostream &s, const std::vector<T> &a){for(auto it = a.begin(); it != a.end(); ++it){if(it != a.begin()) s << " ";s << *it;}return s;}template <typename T>std::istream& operator>>(std::istream &s, std::vector<T> &a){for(auto &x : a) s >> x;return s;}/*** @title Enumerate divisors* @docs enumerate_divisors.md*/std::vector<int64_t> enumerate_divisors(int64_t n){std::vector<int64_t> temp, ret;{int64_t i;for(i = 1LL; i * i < n; ++i){if(n%i == 0){temp.push_back(n / i);ret.push_back(i);}}if(i * i == n) ret.push_back(i);}std::reverse(temp.begin(), temp.end());ret.insert(ret.end(), temp.begin(), temp.end());return ret;}namespace solver{void init(){std::cin.tie(0);std::ios::sync_with_stdio(false);std::cout << std::fixed << std::setprecision(12);std::cerr << std::fixed << std::setprecision(12);std::cin.exceptions(std::ios_base::failbit);}void solve(){int S; std::cin >> S;while(S--){int X, Y; std::cin >> X >> Y;if(X < Y) std::swap(X, Y);int diff = X - Y;int64_t ans = 0;for(auto div : enumerate_divisors(diff)){int A = div + 1;if((X + Y) % (A + 1)) continue;int d1 = diff / div;int d2 = (X + Y) / (A + 1);int B = (d1 + d2) / 2;int C = d2 - B;//dump(std::make_tuple(A, B, C));if(B > 0 and C > 0){if(X == A * B + C and Y == A * C + B) ++ans;}}std::cout << ans << "\n";}}}int main(){solver::init();while(true){try{solver::solve();}catch(const std::istream::failure &e){break;}}return 0;}