結果
| 問題 |
No.1209 XOR Into You
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2020-08-30 14:25:27 |
| 言語 | Rust (1.83.0 + proconio) |
| 結果 |
AC
|
| 実行時間 | 102 ms / 2,000 ms |
| コード長 | 5,053 bytes |
| コンパイル時間 | 18,771 ms |
| コンパイル使用メモリ | 378,460 KB |
| 実行使用メモリ | 16,324 KB |
| 最終ジャッジ日時 | 2024-11-15 07:37:48 |
| 合計ジャッジ時間 | 19,929 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 37 |
ソースコード
#[allow(unused_imports)]
use std::cmp::*;
#[allow(unused_imports)]
use std::collections::*;
use std::io::{Write, BufWriter};
// https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8
macro_rules! input {
($($r:tt)*) => {
let stdin = std::io::stdin();
let mut bytes = std::io::Read::bytes(std::io::BufReader::new(stdin.lock()));
let mut next = move || -> String{
bytes
.by_ref()
.map(|r|r.unwrap() as char)
.skip_while(|c|c.is_whitespace())
.take_while(|c|!c.is_whitespace())
.collect()
};
input_inner!{next, $($r)*}
};
}
macro_rules! input_inner {
($next:expr) => {};
($next:expr, ) => {};
($next:expr, $var:ident : $t:tt $($r:tt)*) => {
let $var = read_value!($next, $t);
input_inner!{$next $($r)*}
};
}
macro_rules! read_value {
($next:expr, [graph1; $len:expr]) => {{
let mut g = vec![vec![]; $len];
let ab = read_value!($next, [(usize1, usize1)]);
for (a, b) in ab {
g[a].push(b);
g[b].push(a);
}
g
}};
($next:expr, ( $($t:tt),* )) => {
( $(read_value!($next, $t)),* )
};
($next:expr, [ $t:tt ; $len:expr ]) => {
(0..$len).map(|_| read_value!($next, $t)).collect::<Vec<_>>()
};
($next:expr, chars) => {
read_value!($next, String).chars().collect::<Vec<char>>()
};
($next:expr, usize1) => (read_value!($next, usize) - 1);
($next:expr, [ $t:tt ]) => {{
let len = read_value!($next, usize);
read_value!($next, [$t; len])
}};
($next:expr, $t:ty) => ($next().parse::<$t>().expect("Parse error"));
}
#[allow(unused)]
macro_rules! debug {
($($format:tt)*) => (write!(std::io::stderr(), $($format)*).unwrap());
}
#[allow(unused)]
macro_rules! debugln {
($($format:tt)*) => (writeln!(std::io::stderr(), $($format)*).unwrap());
}
/**
* Segment Tree. This data structure is useful for fast folding on intervals of an array
* whose elements are elements of monoid I. Note that constructing this tree requires the identity
* element of I and the operation of I.
* Verified by: yukicoder No. 259 (http://yukicoder.me/submissions/100581)
* AGC015-E (http://agc015.contest.atcoder.jp/submissions/1461001)
*/
struct SegTree<I, BiOp> {
n: usize,
dat: Vec<I>,
op: BiOp,
e: I,
}
impl<I, BiOp> SegTree<I, BiOp>
where BiOp: Fn(I, I) -> I,
I: Copy {
pub fn new(n_: usize, op: BiOp, e: I) -> Self {
let mut n = 1;
while n < n_ { n *= 2; } // n is a power of 2
SegTree {n: n, dat: vec![e; 2 * n - 1], op: op, e: e}
}
/* ary[k] <- v */
pub fn update(&mut self, idx: usize, v: I) {
let mut k = idx + self.n - 1;
self.dat[k] = v;
while k > 0 {
k = (k - 1) / 2;
self.dat[k] = (self.op)(self.dat[2 * k + 1], self.dat[2 * k + 2]);
}
}
/* [a, b) (note: half-inclusive)
* http://proc-cpuinfo.fixstars.com/2017/07/optimize-segment-tree/ */
pub fn query(&self, mut a: usize, mut b: usize) -> I {
let mut left = self.e;
let mut right = self.e;
a += self.n - 1;
b += self.n - 1;
while a < b {
if (a & 1) == 0 {
left = (self.op)(left, self.dat[a]);
}
if (b & 1) == 0 {
right = (self.op)(self.dat[b - 1], right);
}
a = a / 2;
b = (b - 1) / 2;
}
(self.op)(left, right)
}
}
fn solve() {
let out = std::io::stdout();
let mut out = BufWriter::new(out.lock());
macro_rules! puts {
($($format:tt)*) => (let _ = write!(out,$($format)*););
}
input! {
n: usize,
a: [i64; n],
b: [i64; n],
}
macro_rules! fail {
() => {
puts!("-1\n");
return;
}
}
if a[0] != b[0] {
fail!();
}
let mut hm = HashMap::new();
for i in 1..n {
*hm.entry(a[i] ^ a[i - 1]).or_insert(0) += 1;
*hm.entry(b[i] ^ b[i - 1]).or_insert(0) -= 1;
}
for (_, &v) in &hm {
if v != 0 {
fail!();
}
}
let mut inv = HashMap::new();
let mut count = 0;
for i in 0..n - 1 {
let val = a[i] ^ a[i + 1];
inv.entry(val).or_insert(vec![]).push(count);
count += 1;
}
let mut st = SegTree::new(n, |x, y| x + y, 0i64);
let mut ans = 0;
for i in (0..n - 1).rev() {
let val = b[i] ^ b[i + 1];
let ent = inv.entry(val).or_insert(vec![]);
let idx = ent.pop().unwrap();
ans += st.query(0, idx);
st.update(idx, st.query(idx, idx + 1) + 1);
}
puts!("{}\n", ans);
}
fn main() {
// In order to avoid potential stack overflow, spawn a new thread.
let stack_size = 104_857_600; // 100 MB
let thd = std::thread::Builder::new().stack_size(stack_size);
thd.spawn(|| solve()).unwrap().join().unwrap();
}