結果
問題 | No.1191 数え上げを愛したい(数列編) |
ユーザー | uchiiii |
提出日時 | 2020-09-01 20:06:47 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 9 ms / 2,000 ms |
コード長 | 5,276 bytes |
コンパイル時間 | 2,772 ms |
コンパイル使用メモリ | 223,284 KB |
実行使用メモリ | 8,064 KB |
最終ジャッジ日時 | 2024-04-30 17:35:00 |
合計ジャッジ時間 | 3,831 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
(要ログイン)
テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 8 ms
7,936 KB |
testcase_01 | AC | 8 ms
7,936 KB |
testcase_02 | AC | 7 ms
7,936 KB |
testcase_03 | AC | 8 ms
7,936 KB |
testcase_04 | AC | 8 ms
7,936 KB |
testcase_05 | AC | 7 ms
7,932 KB |
testcase_06 | AC | 8 ms
7,936 KB |
testcase_07 | AC | 7 ms
7,936 KB |
testcase_08 | AC | 8 ms
7,936 KB |
testcase_09 | AC | 8 ms
7,936 KB |
testcase_10 | AC | 7 ms
7,864 KB |
testcase_11 | AC | 7 ms
7,936 KB |
testcase_12 | AC | 8 ms
8,064 KB |
testcase_13 | AC | 7 ms
7,936 KB |
testcase_14 | AC | 7 ms
7,916 KB |
testcase_15 | AC | 9 ms
7,936 KB |
testcase_16 | AC | 7 ms
7,936 KB |
testcase_17 | AC | 7 ms
7,936 KB |
testcase_18 | AC | 7 ms
7,936 KB |
testcase_19 | AC | 7 ms
7,936 KB |
testcase_20 | AC | 8 ms
7,936 KB |
testcase_21 | AC | 7 ms
7,936 KB |
testcase_22 | AC | 8 ms
7,936 KB |
testcase_23 | AC | 6 ms
7,936 KB |
testcase_24 | AC | 8 ms
7,936 KB |
testcase_25 | AC | 7 ms
7,936 KB |
ソースコード
#pragma GCC target("avx2") #pragma GCC optimize("03") #pragma GCC optimize("unroll-loops") #include <bits/stdc++.h> using namespace std; typedef long double ld; typedef long long ll; typedef unsigned long long ull; #define endl "\n" #define FOR(i,a,b) for(ll i=(a);i<=(b);i++) #define rep(i,n) for(int i=0;i<(n);i++) #define PII pair<int, int> #define PLL pair<ll, ll> #define ALL(x) (x).begin(), (x).end() int dx[] = {1, 0, -1, 0}; int dy[] = {0, 1, 0, -1}; constexpr int INF=1<<30; constexpr ll LINF=1LL<<60; constexpr ll mod=998244353; template<class T>vector<T> vec(int len, T elem) { return vector<T>(len, elem); } // auto dp = vec(52, vec(103, vec(103, INF))); template<class T>inline bool chmax(T &a, const T &b) { if (a<b) { a = b; return 1; } return 0; } template<class T>inline bool chmin(T &a, const T &b) { if (b<a) { a = b; return 1; } return 0; } template<class T>inline int popcount(T a) {return __builtin_popcount(a);} template<class T>inline T emod(T a, T p) { return (a%p + p) % p;} template <typename T> istream &operator>>(istream &is, vector<T> &vec) { for (auto &v : vec) is >> v; return is; } template <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {os << '\n'; for (auto v : vec) os << v << ' '; os << '\n'; return os;} template <typename T> ostream &operator<<(ostream &os, const deque<T> &vec) { os << "deq["; for (auto v : vec) os << v << ','; os << ']'; return os; } template <typename T> ostream &operator<<(ostream &os, const set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; } template <typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; } template <typename T> ostream &operator<<(ostream &os, const multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; } template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; } template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa) { os << '(' << pa.first << ',' << pa.second << ')'; return os; } template <typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; } template <typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; } struct MyIO { MyIO(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(15); } } IO_OI; #ifdef LOCAL void debug_out() { cerr << endl; } template <typename Head, typename... Tail> void debug_out(Head H, Tail... T) { cerr << " " << H; debug_out(T...); } #define debug(...) \ cerr << __LINE__ << " [" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__) #define dump(x) cerr << __LINE__ << " " << #x << " = " << (x) << endl #else #define debug(...) (void(0)) #define dump(x) (void(0)) #endif //------------------- struct mint { ll x; mint(ll x=0):x(x%mod){} bool operator==(const mint a)const{return x==a.x;} bool operator!=(const mint a)const{return x!=a.x;} bool operator>=(const mint a){return (x >= a.x)? 1: 0;} bool operator<(const mint a){return !(*this>=a);} bool operator>(const mint a){return (x > a.x)? 1:0;} bool operator<=(const mint a){return !(*this>a);} mint& operator+=(const mint a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this; } mint& operator/=(const mint a) { return (*this) *= a.inv(); } mint operator+(const mint a) const { mint res(*this); return res+=a; } mint operator-(const mint a) const { mint res(*this); return res-=a; } mint operator*(const mint a) const { mint res(*this); return res*=a; } mint operator/(const mint a) const { mint res(*this); return res/=a; } mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; //2 square if (t&1) a *= *this; return a; } // for prime mod mint inv() const { return pow(mod-2); } friend ostream& operator<<(ostream& os, const mint& m){ os << m.x; return os; } }; struct combination { vector<mint> fact, ifact; combination(int n):fact(n+1),ifact(n+1) { fact[0] = 1; for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i; ifact[n] = fact[n].inv(); for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i; } mint operator()(int n, int k) { if (k < 0 || k > n) return 0; return fact[n]*ifact[k]*ifact[n-k]; } } comb(300005); mint f(int n, int k) { if (n < 0) return 0; // nPk = nCk * k! mint res = comb(n,k); res *= comb.fact[k]; return res; } int main() { ll n,m,a,b; cin>>n>>m>>a>>b; mint ans = 0; // if(a*(n-1)>b) { // cout << 0 << endl; // return 0; // } FOR(i,1,m) { ll k = min(i+b,m) - i - (n-1)*a; if(k<0) continue; ans += comb(k+n-1, n-1); } cout << ans*f(n, n) << endl; return 0; }