結果

問題 No.1238 選抜クラス
ユーザー piddypiddy
提出日時 2020-09-06 05:33:20
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
(最新)
AC  
(最初)
実行時間 -
コード長 5,190 bytes
コンパイル時間 676 ms
コンパイル使用メモリ 77,172 KB
実行使用メモリ 8,760 KB
最終ジャッジ日時 2023-08-19 13:31:47
合計ジャッジ時間 4,689 ms
ジャッジサーバーID
(参考情報)
judge13 / judge14
このコードへのチャレンジ(β)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 1 ms
7,568 KB
testcase_01 AC 2 ms
4,376 KB
testcase_02 AC 2 ms
4,376 KB
testcase_03 AC 2 ms
4,380 KB
testcase_04 AC 2 ms
4,380 KB
testcase_05 AC 1 ms
4,376 KB
testcase_06 AC 2 ms
4,380 KB
testcase_07 AC 1 ms
4,376 KB
testcase_08 AC 2 ms
4,380 KB
testcase_09 AC 3 ms
4,380 KB
testcase_10 AC 2 ms
4,376 KB
testcase_11 AC 2 ms
4,384 KB
testcase_12 AC 1 ms
4,376 KB
testcase_13 AC 1 ms
4,376 KB
testcase_14 AC 1 ms
4,380 KB
testcase_15 AC 2 ms
4,380 KB
testcase_16 AC 2 ms
4,376 KB
testcase_17 WA -
testcase_18 WA -
testcase_19 WA -
testcase_20 WA -
testcase_21 TLE -
testcase_22 -- -
testcase_23 -- -
testcase_24 -- -
testcase_25 -- -
testcase_26 -- -
testcase_27 -- -
testcase_28 -- -
testcase_29 -- -
testcase_30 -- -
testcase_31 -- -
testcase_32 -- -
testcase_33 -- -
testcase_34 -- -
testcase_35 -- -
testcase_36 -- -
testcase_37 -- -
testcase_38 -- -
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <iostream>
#include <vector>
#include <bitset>
using namespace std;
using ll = long long;

template<long long P>
long long modinv(long long n) {
	long long a = P, u = 1, v = 0;
	while (a) {
		long long t = n / a;
		n -= t * a;
		std::swap(n, a);
		u -= t * v;
		std::swap(u, v);
	}
	u %= P;
	if (u < 0) u += P;
	return u;
}

template<long long M>
struct modint {
	long long val;

	modint<M>(long long right) : val(right) {sub(val);}
	modint<M>() {val = 0;}

	void sub(long long &n) {
		if (n < 0) {
			long long m = (-n) % M;
			n = M - m;
		}
		else n %= M;
	}

	modint<M> operator+ (modint<M> right) {return (this -> val) + right.val;}
	modint<M> operator+ (long long right) {sub(right); return (this -> val) + right;}
	modint<M> operator- (modint<M> right) {return (this -> val) - right.val;}
	modint<M> operator- (long long right) {sub(right); return (this -> val) - right;}
	modint<M> operator* (modint<M> right) {return (this -> val) * right.val;}
	modint<M> operator* (long long right) {sub(right); return (this -> val) * right;}

	bool operator== (modint<M> right) {return ((this -> val) == right.val);}
	bool operator== (long long right) {sub(right); return ((this -> val) == right);}
	bool operator!= (modint<M> right) {return ((this -> val) != right.val);}
	bool operator!= (long long right) {sub(right); return ((this -> val) != right);}
	bool operator<= (modint<M> right) {return ((this -> val) <= right.val);}
	bool operator<= (long long right) {sub(right); return ((this -> val) <= right);}
	bool operator>= (modint<M> right) {return ((this -> val) >= right.val);}
	bool operator>= (long long right) {sub(right); return ((this -> val) >= right);}
	bool operator< (modint<M> right) {return ((this -> val) < right.val);}
	bool operator< (long long right) {sub(right); return ((this -> val) < right);}
	bool operator> (modint<M> right) {return ((this -> val) > right.val);}
	bool operator> (long long right) {sub(right); return ((this -> val) > right);}

	void operator+= (modint<M> right) {*this = *this + right;}
	void operator+= (long long right) {*this = *this + right;}
	void operator-= (modint<M> right) {*this = *this - right;}
	void operator-= (long long right) {*this = *this - right;}
	void operator*= (modint<M> right) {*this = *this * right;}
	void operator*= (long long right) {*this = *this * right;}

	modint<M>& operator++ () {*this += 1; return *this;}
	modint<M> operator++ (int) {*this += 1; return *this - 1;}
	modint<M>& operator-- () {*this -= 1; return *this;}
	modint<M> operator-- (int) {*this -= 1; return *this + 1;}

	modint<M> operator/ (modint<M> right) {return *this * modinv<M>(right.val);}
	modint<M> operator/ (long long right) {sub(right); return *this * modinv<M>(right);}

	void operator/= (modint<M> right) {*this = *this / right;}
	void operator/= (long long right) {*this = *this / right;}
};

std::vector<long long> factorial;
std::vector<long long> factorial_inv;

template<long long P>
void make_table(long long n) {
	factorial.resize(n + 1, 1); factorial_inv.resize(n + 1, 1);
	for (long long i = 2; i <= n; i++) {
		factorial[i] = factorial[i - 1] * i % P;
	}
	factorial_inv[n] = modinv<P>(factorial[n]);
	for (long long i = n - 1; i >= 0; i--) {
		factorial_inv[i] = factorial_inv[i + 1] * (i + 1) % P;
	}
}

template<long long P>
modint<P> permutation(long long n, long long r) {
	if (n <= factorial.size()) {
		modint<P> a = factorial[n], b = factorial_inv[n - r];
		return a * b;
	}
	else {
		std::cerr << "attention : factorial table is not constructed" << '\n';
		modint<P> ret = 1;
		for (long long i = 0; i < r; i++) ret *= n - i;
		return ret;
	}
}

template<long long P>
modint<P> combination(long long n, long long r) {
	r = std::min(r, n - r);
	if (n <= factorial.size()) {
		return permutation<P>(n, r) * factorial_inv[r];
	}
	else {
		std::cerr << "attention : factorial table is not constructed" << '\n';
		modint<P> ret = 1;
		for (long long i = 0; i < r; i++) {
			ret *= n - i;
			ret /= i + 1;
		}
		return ret;
	}
}

template<long long M>
modint<M> modpow(long long a, long long n) {
	a %= M;
	if (n == 0) return 1;
	if (a == 0) return 0;
	if (a == 1) return 1;
	long long b = 1, cnt = 0;
	while (b < M && cnt < n) {
		b *= a;
		cnt++;
	}
	modint<M> ret;
	if (b < M) ret = b;
	else {
		b %= M;
		ret = modpow<M>(b, n / cnt) * modpow<M>(a, n % cnt);
	}
	return ret;
}

template<long long M>
modint<M> modpow(modint<M> m, long long n) {
	long long a = m.val;
	if (n == 0) return 1;
	if (a == 0) return 0;
	if (a == 1) return 1;
	long long b = 1, cnt = 0;
	while (b < M && cnt < n) {
		b *= a;
		cnt++;
	}
	modint<M> ret;
	if (b < M) ret = b;
	else {
		b %= M;
		ret = modpow<M>(b, n / cnt) * modpow<M>(a, n % cnt);
	}
	return ret;
}

template<long long M>
std::ostream &operator<< (std::ostream &out, modint<M> tgt) {out << tgt.val; return out;}

int main() {
	int N, K;
	cin >> N >> K;
	vector<int> A(N);
	for (int i = 0; i < N; i++) cin >> A[i];

	const int P = 1000000007;
	modint<P> ans = 0;
	for (int i = 1; i < (1 << N); i++) {
		bitset<32> bs = i;
		int sum = 0;
		for (int j = 0; j < N; j++) {
			if (bs[j]) sum += A[j];
		}
		if (sum >= K * __builtin_popcount(i)) ans++;
	}
	cout << ans << endl;
}
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