結果

問題 No.186 中華風 (Easy)
ユーザー Suu0313Suu0313
提出日時 2020-09-14 22:30:46
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 2 ms / 2,000 ms
コード長 5,358 bytes
コンパイル時間 1,601 ms
コンパイル使用メモリ 172,156 KB
実行使用メモリ 4,380 KB
最終ジャッジ日時 2023-09-27 01:01:47
合計ジャッジ時間 2,485 ms
ジャッジサーバーID
（参考情報） 		judge13 / judge14
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
4,380 KB
testcase_01 AC 1 ms
4,376 KB
testcase_02 AC 1 ms
4,376 KB
testcase_03 AC 1 ms
4,380 KB
testcase_04 AC 2 ms
4,376 KB
testcase_05 AC 2 ms
4,376 KB
testcase_06 AC 2 ms
4,380 KB
testcase_07 AC 1 ms
4,376 KB
testcase_08 AC 2 ms
4,376 KB
testcase_09 AC 2 ms
4,380 KB
testcase_10 AC 2 ms
4,380 KB
testcase_11 AC 2 ms
4,376 KB
testcase_12 AC 2 ms
4,376 KB
testcase_13 AC 2 ms
4,376 KB
testcase_14 AC 1 ms
4,380 KB
testcase_15 AC 2 ms
4,380 KB
testcase_16 AC 2 ms
4,380 KB
testcase_17 AC 1 ms
4,380 KB
testcase_18 AC 2 ms
4,376 KB
testcase_19 AC 1 ms
4,380 KB
testcase_20 AC 1 ms
4,376 KB
testcase_21 AC 1 ms
4,376 KB
testcase_22 AC 1 ms
4,376 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <bits/stdc++.h>
using namespace std;

//conversion
//------------------------------------------
inline int toInt(string s) {int v; istringstream sin(s);sin>>v;return v;}
template<class T> inline string toString(T x) {ostringstream sout;sout<<x;return sout.str();}

//math
//-------------------------------------------
template<class T> inline T sqr(T x) {return x*x;}

//typedef
//------------------------------------------
typedef long long LL;
typedef pair<int, int> PII;
typedef pair<LL,LL> PLL;
typedef vector<int> VI;
typedef vector<VI> VVI;
typedef vector<LL> VLL;
typedef vector<VLL> VVLL;
typedef vector<bool> VB;
typedef vector<VB> VVB;
typedef vector<double> VD;
typedef vector<VD> VVD;
typedef vector<string> VS;
typedef vector<VS> VVS;
typedef vector<char> VC;
typedef vector<VC> VVC;
typedef vector<PII> VPII;
typedef vector<PLL> VPLL;
typedef priority_queue<int> PQGI; //大きい順
typedef priority_queue<int, VI, greater<int>> PQLI;
typedef priority_queue<PII> PQGP;
typedef priority_queue<PII, VPII, greater<PII>> PQLP;
//priority_queue<T,vector<T>,decltype(f)> pq{f};

//container util
//------------------------------------------
#define ALL(a)  (a).begin(),(a).end()
#define RALL(a) (a).rbegin(),(a).rend()
#define EB emplace_back
#define EF emplace_front
#define PB push_back
#define PF push_front
#define POB pop_back
#define POF pop_front
#define MP make_pair
#define SZ(a) int((a).size())
#define SQ(a) ((a)*(a))
#define EACH(i,c) for(typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)
#define EXIST(s,e) ((s).find(e)!=(s).end())
#define SORT(c) sort((c).begin(),(c).end())
#define SORTR(c) sort((c).rbegin(), (c).rend())
#define LB lower_bound
#define UB upper_bound
#define NEXP next_permutation
#define FI first
#define SE second
#define Vmin(a) *min_element((a).begin(),(a).end())
#define Vmax(a) *max_element((a).begin(),(a).end())

//repetition
//------------------------------------------
#define FOR(i,a,b) for(int i=(a);i<(b);++i)
#define REP(i,n)  FOR(i,0,n)
#define FORR(i,a,b) for(int i = (b-1);i>=(a);i--)
#define REPR(i,n) FORR(i,0,n)
#define CFOR(i,a,b) for(int i=(a);i<=(b);++i)
#define CREP(i,n)  CFOR(i,0,n)
#define CFORR(i,a,b) for(int i = (b);i>=(a);i--)
#define CREPR(i,n) CFORR(i,0,n)
#define BFOR(bit,a,b) for(int bit = (a); bit < (1<<(b)); ++bit)
#define BREP(bit,n) BFOR(bit,0,n)

//constant
//--------------------------------------------
const double EPS = 1e-10;
const double PI  = acos(-1.0);
const int INF = INT_MAX/2;
const LL LINF = LLONG_MAX/3;
const int RINF = INT_MIN/2;
const LL RLINF = LLONG_MIN/3;
const LL MOD = 1e9+7;
const LL MODD = 998244353;
const int MAX = 510000;

inline bool Eq(double a, double b) { return fabs(b - a) < EPS; }

//other
//-------------------------------------------
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }

#define COUT(x) cout << (x) << endl
#define COUT2(x,y) cout << (x) << " " << (y) << endl
#define COUT3(x,y,z) cout << (x) << " " << (y) << " " << (z) << endl
#define PR(x) cout << (x)
#define ENDL cout << endl
#define SPACE cout << " "
#define BC(x) __builtin_popcountll(x)

VI dx = {1,0,-1,0,1,1,-1,-1};
VI dy = {0,1,0,-1,1,-1,1,-1};

LL Gcd(LL a, LL b) {return __gcd(a,b);}
LL Lcm(LL a, LL b) {return a/Gcd(a,b)*b;}

LL ModPow(LL A, LL N, LL M=MOD){
  LL res = 1;
  while(N>0){
    if(N&1) res = res * A % M;
    A = A * A % M;
    N >>= 1;
  }
  return res;
}

template< typename T1, typename T2 >
istream &operator>>(istream &is, pair< T1, T2 > &p) {
  is >> p.first >> p.second;
  return is;
}

template< typename T1, typename T2 >
ostream &operator<<(ostream &os, const pair< T1, T2 >& p) {
  os << p.first << " " << p.second;
  return os;
}

template< typename T >
istream &operator>>(istream &is, vector< T > &v) {
  for(T &in : v) is >> in;
  return is;
}

template< typename T >
ostream &operator<<(ostream &os, const vector< T > &v) {
  for(int i = 0; i < SZ(v); i++) {
    os << v[i] << (i + 1 != SZ(v) ? " " : "");
  }
  return os;
}

template<typename T>
vector<T> make_v(size_t a,T b){return vector<T>(a,b);}
template<typename... Ts>
auto make_v(size_t a,Ts... ts){
  return vector<decltype(make_v(ts...))>(a,make_v(ts...));
}


PLL InvGcd(LL a, LL b){
  if(a==0) return {b, 0};
  LL s = b, t = a;
  LL m0 = 0, m1 = 1;
  while(t){
    LL u = s/t; s -= t*u; m0 -= m1*u;
    LL tmp = s; s = t; t = tmp; tmp = m0; m0 = m1; m1 = tmp;
  }
  if(m0<0) m0 += b/s;
  return {s, m0};
}
PLL ChineseRem(VLL &r, VLL &m){
  int n = SZ(r);
  LL r0 = 0, m0 = 1;
  REP(i,n){
    LL r1 = r.at(i), m1 = m.at(i);
    r1 %= m1;
    if(r1<0) r1 += m1;
    if(m0<m1){
      swap(r0,r1);
      swap(m0,m1);
    }
    if(m0%m1 == 0){
      if(r0%m1 != r1) return {0,0};
      continue;
    }
    LL g, im;
    tie(g,im) = InvGcd(m0, m1);
    LL u1 = m1 / g;
    if((r1-r0) % g) return {0,0};
    LL x = (r1-r0) / g % u1 * im % u1;
    r0 += x * m0;
    m0 *= u1;
    if(r0 < 0) r0 += m0;
  }
  return {r0, m0};
}

int main() {

  // cin.tie(0);
  // ios::sync_with_stdio(false);
  cout << fixed << setprecision(12);

  VLL X(3), Y(3);
  REP(i,3) cin >> X.at(i) >> Y.at(i);

  PLL res = ChineseRem(X,Y);

  if(res.SE == 0){
    COUT(-1);
  }else if(res.FI == 0){
    COUT(res.SE);
  }else{
    COUT(res.FI);
  }

  return 0;
}
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