結果

問題 No.295 hel__world
ユーザー anta
提出日時 2015-10-23 23:50:08
言語 C++11(廃止可能性あり)
(gcc 13.3.0)
結果
AC  
実行時間 55 ms / 5,000 ms
コード長 5,923 bytes
コンパイル時間 1,565 ms
コンパイル使用メモリ 113,160 KB
実行使用メモリ 49,028 KB
最終ジャッジ日時 2024-09-13 04:03:42
合計ジャッジ時間 4,036 ms
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 53
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:163:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
  163 |                 scanf("%lld", &S[i]);
      |                 ~~~~~^~~~~~~~~~~~~~~
main.cpp:164:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
  164 |         scanf("%s", T);
      |         ~~~~~^~~~~~~~~

ソースコード

diff #
プレゼンテーションモードにする

#include <string>
#include <vector>
#include <algorithm>
#include <numeric>
#include <set>
#include <map>
#include <queue>
#include <iostream>
#include <sstream>
#include <cstdio>
#include <cmath>
#include <ctime>
#include <cstring>
#include <cctype>
#include <cassert>
#include <limits>
#include <functional>
#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))
#define rer(i,l,u) for(int (i)=(int)(l);(i)<=(int)(u);++(i))
#define reu(i,l,u) for(int (i)=(int)(l);(i)<(int)(u);++(i))
#if defined(_MSC_VER) || __cplusplus > 199711L
#define aut(r,v) auto r = (v)
#else
#define aut(r,v) __typeof(v) r = (v)
#endif
#define each(it,o) for(aut(it, (o).begin()); it != (o).end(); ++ it)
#define all(o) (o).begin(), (o).end()
#define pb(x) push_back(x)
#define mp(x,y) make_pair((x),(y))
#define mset(m,v) memset(m,v,sizeof(m))
#define INF 0x3f3f3f3f
#define INFL 0x3f3f3f3f3f3f3f3fLL
using namespace std;
typedef vector<int> vi; typedef pair<int,int> pii; typedef vector<pair<int,int> > vpii; typedef long long ll;
template<typename T, typename U> inline void amin(T &x, U y) { if(y < x) x = y; }
template<typename T, typename U> inline void amax(T &x, U y) { if(x < y) x = y; }
struct SaturationInt {
typedef unsigned long long T; typedef double Float;
static T Max;
T x;
static inline T sat(T x) { return x > Max ? Max : x; }
SaturationInt(): x(0) { }
SaturationInt(T x_): x(sat(x_)) { }
T get() const { return x; }
SaturationInt operator+(const SaturationInt &that) const {
return SaturationInt(x + that.x);
}
SaturationInt operator*(const SaturationInt &that) const {
return SaturationInt((Float)x * that.x > Max ? Max : x * that.x);
}
SaturationInt &operator+=(const SaturationInt &that) { return *this = *this + that; }
SaturationInt &operator*=(const SaturationInt &that) { return *this = *this * that; }
SaturationInt operator^(long long k) const {
T r = 1, a = x;
while(k) {
if(k & 1) r *= a;
if(k >>= 1) {
if((Float)a * a * r > Max) return SaturationInt(Max);
a *= a;
}
}
return SaturationInt(r);
}
bool operator<(const SaturationInt &that) const {
return x < that.x;
}
};
SaturationInt::T SaturationInt::Max = (1ULL << 63) - 1;
typedef SaturationInt sint;
const int NCR_TABLE_N = 2000;
sint nCrTable[NCR_TABLE_N+1][NCR_TABLE_N+1];
sint nCr(long long x, long long y) {
if(nCrTable[0][0].x == 0) {
for(int i = 0; i <= NCR_TABLE_N; i ++) {
nCrTable[i][0] = 1;
for(int j = 1; j <= i; j ++)
nCrTable[i][j] = nCrTable[i-1][j-1] + nCrTable[i-1][j];
}
}
if(x < y) return sint();
if(y > x / 2) y = x - y;
if(y == 0) return sint(1);
if(y == 1) return sint(x);
if(y == 2) {
long long a[2] = {x, x - 1};
a[x % 2] /= 2;
return sint(a[0]) * sint(a[1]);
}
if(y == 3) {
long long a[3] = {x, x - 1, x - 2};
a[x % 2] /= 2;
a[x % 3] /= 3;
return sint(a[0]) * sint(a[1]) * sint(a[2]);
}
if(y == 4) {
long long a[4] = {x, x - 1, x - 2, x - 3};
a[(x % 2 == x % 4 ? 2 : 0) + x % 2] /= 2;
a[x % 3] /= 3;
a[x % 4] /= 4;
return sint(a[0]) * sint(a[1]) * sint(a[2]) * sint(a[3]);
}
if(y == 5) {
long long a[5] = {x, x - 1, x - 2, x - 3, x - 4};
a[(x % 2 == x % 4 ? 2 : 0) + x % 2] /= 2;
a[x % 3] /= 3;
a[x % 4] /= 4;
a[x % 5] /= 5;
return sint(a[0]) * sint(a[1]) * sint(a[2]) * sint(a[3]) * sint(a[4]);
}
if(y == 6) {
long long a[6] = {x, x - 1, x - 2, x - 3, x - 4, x - 5};
a[x % 5] /= 5;
rep(k, 6) { if(a[k] % 2 == 0) a[k] /= 2; break; }
rep(k, 6) { if(a[k] % 2 == 0) a[k] /= 2; break; }
rep(k, 6) { if(a[k] % 2 == 0) a[k] /= 2; break; }
rep(k, 6) { if(a[k] % 2 == 0) a[k] /= 2; break; }
rep(k, 6) { if(a[k] % 3 == 0) a[k] /= 3; break; }
rep(k, 6) { if(a[k] % 3 == 0) a[k] /= 3; break; }
return sint(a[0]) * sint(a[1]) * sint(a[2]) * sint(a[3]) * sint(a[4]) * sint(a[5]);
}
if(x > NCR_TABLE_N) {
return sint(sint::Max);
} else {
return nCrTable[(int)x][(int)y];
}
}
template<typename T>
vector<pair<T,int> > runLength(const T a[], int n) {
vector<pair<T,int> > r;
if(n <= 0) return r;
int cnt = 0;
for(int i = 0; i <= n; i ++) {
if(i == n || (i != 0 && a[i] != a[i-1])) {
r.push_back(make_pair(a[i-1], cnt));
cnt = 0;
}
cnt ++;
}
return r;
}
sint solve(long long x, int y, int n) {
sint ans = 1;
ans *= nCr(y + x / n, y) ^ (n - x % n);
ans *= nCr(y + x / n + 1, y) ^ (x % n);
return ans;
}
int main() {
const int Alphas = 26;
char *T = new char[1000001];
vector<long long> S(Alphas);
for(int i = 0; i < Alphas; ++ i)
scanf("%lld", &S[i]);
scanf("%s", T);
auto runs = runLength(T, strlen(T));
vector<vi> lengths(Alphas);
for(auto p : runs) {
int a = p.first - 'a';
S[a] -= p.second;
lengths[a].push_back(p.second);
}
sint ans = 1;
rep(a, Alphas) {
long long x = S[a];
if(x < 0) {
ans *= 0;
continue;
}
vi &v = lengths[a];
sort(all(v), greater<int>());
if(v.empty())
continue;
auto w = runLength(&v[0], v.size());
if(w.size() == 1) {
ans *= solve(x, w[0].first, w[0].second);
continue;
}
vector<int> sum(w.size() + 1, 0);
for(int i = (int)w.size() - 1; i >= 0; -- i)
sum[i] = sum[i+1] + w[i].first * w[i].second;
map<long long, sint> dp, ndp;
dp[x] = 1;
rep(k, w.size()) {
int y = w[k].first, n = w[k].second;
double ratio = y * n * 1. / sum[k];
ndp.clear();
for(auto p : dp) {
long long remx = p.first;
sint t = p.second;
long long a = (long long)(remx * ratio);
for(long long b = max(0LL, a - 10); b <= min(remx, a + 10); ++ b) {
amax(ndp[remx - b], t * solve(b, y, n));
}
}
sint maxi;
dp.clear();
for(auto it = ndp.rbegin(); it != ndp.rend(); ++ it) {
if(maxi < it->second) {
maxi = it->second;
dp.insert(*it);
}
}
if(maxi.get() >= 1ULL << 62)
break;
}
sint maxi;
for(auto p : dp)
amax(maxi, p.second);
ans *= maxi;
}
if(ans.get() >= 1ULL << 62) {
puts("hel");
} else {
cout << ans.get() << endl;
}
return 0;
}
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