結果

問題 No.1270 Range Arrange Query
ユーザー stoq
提出日時 2020-09-18 05:17:14
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
RE  
(最新)
AC  
(最初)
実行時間 -
コード長 8,150 bytes
コンパイル時間 3,969 ms
コンパイル使用メモリ 233,224 KB
最終ジャッジ日時 2025-01-14 15:59:45
ジャッジサーバーID
（参考情報） 		judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 13 RE * 2
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘void solve()’:
main.cpp:382:18: warning: ‘len’ may be used uninitialized [-Wmaybe-uninitialized]
  382 |     ans[i] = inv + sg.query(0, n) * len;
      |              ~~~~^~~~~~~~~~~~~~~~~~~~~~
main.cpp:378:8: note: ‘len’ was declared here
  378 |     ll len;
      |        ^~~

ソースコード

diff #
プレゼンテーションモードにする

#define MOD_TYPE 1
#pragma region Macros
#include <bits/stdc++.h>
using namespace std;
#if 0
#include <boost/multiprecision/cpp_int.hpp>
#include <boost/multiprecision/cpp_dec_float.hpp>
using Int = boost::multiprecision::cpp_int;
using lld = boost::multiprecision::cpp_dec_float_100;
#endif
#if 1
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#endif
using ll = long long int;
using ld = long double;
using ull = unsigned long long;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using pld = pair<ld, ld>;
template <typename Q_type>
using smaller_queue = priority_queue<Q_type, vector<Q_type>, greater<Q_type>>;
constexpr ll MOD = (MOD_TYPE == 1 ? (ll)(1e9 + 7) : 998244353);
//constexpr ll MOD = 1;
constexpr int INF = (int)1e9 + 10;
constexpr ll LINF = (ll)4e18;
constexpr double PI = acos(-1.0);
constexpr double EPS = 1e-9;
constexpr int Dx[] = {0, 0, -1, 1, -1, 1, -1, 1, 0};
constexpr int Dy[] = {1, -1, 0, 0, -1, -1, 1, 1, 0};
#define REP(i, m, n) for (ll i = m; i < (ll)(n); ++i)
#define rep(i, n) REP(i, 0, n)
#define REPI(i, m, n) for (int i = m; i < (int)(n); ++i)
#define repi(i, n) REPI(i, 0, n)
#define MP make_pair
#define MT make_tuple
#define YES(n) cout << ((n) ? "YES" : "NO") << "\n"
#define Yes(n) cout << ((n) ? "Yes" : "No") << "\n"
#define possible(n) cout << ((n) ? "possible" : "impossible") << "\n"
#define Possible(n) cout << ((n) ? "Possible" : "Impossible") << "\n"
#define Yay(n) cout << ((n) ? "Yay!" : ":(") << "\n"
#define all(v) v.begin(), v.end()
#define NP(v) next_permutation(all(v))
#define dbg(x) cerr << #x << ":" << x << "\n";
struct io_init
{
  io_init()
  {
    cin.tie(0);
    ios::sync_with_stdio(false);
    cout << setprecision(30) << setiosflags(ios::fixed);
  };
} io_init;
template <typename T>
inline bool chmin(T &a, T b)
{
  if (a > b)
  {
    a = b;
    return true;
  }
  return false;
}
template <typename T>
inline bool chmax(T &a, T b)
{
  if (a < b)
  {
    a = b;
    return true;
  }
  return false;
}
inline ll CEIL(ll a, ll b)
{
  return (a + b - 1) / b;
}
template <typename A, size_t N, typename T>
inline void Fill(A (&array)[N], const T &val)
{
  fill((T *)array, (T *)(array + N), val);
}
template <typename T, typename U>
constexpr istream &operator>>(istream &is, pair<T, U> &p) noexcept
{
  is >> p.first >> p.second;
  return is;
}
template <typename T, typename U>
constexpr ostream &operator<<(ostream &os, pair<T, U> &p) noexcept
{
  os << p.first << " " << p.second;
  return os;
}
#pragma endregion
template <typename T>
struct BIT
{
  int n;
  vector<T> dat;
  BIT() {}
  BIT(int n_) : n(n_), dat(n_, 0) {}
  // 0-indexed
  void add(int i, T x)
  {
    i++;
    while (i <= n)
    {
      dat[i - 1] += x;
      i += i & -i;
    }
  }
  // [0, i)
  T sum(int i)
  {
    T res = 0;
    while (i > 0)
    {
      res += dat[i - 1];
      i -= i & -i;
    }
    return res;
  }
  // 0-indexed
  T get(int i) { return sum(i + 1) - sum(i); }
  // [l, r)
  T sum(int l, int r) { return sum(r) - sum(l); }
  void display()
  {
    for (int i = 0; i < n; i++)
      cerr << get(i) << " ";
    cerr << "\n";
  }
};
template <typename T, typename E>
struct SegmentTree
{
  using F = function<T(T, T)>;
  using G = function<T(T, E)>;
  using H = function<E(E, E)>;
  using P = function<E(E, int)>;
  int n;
  F f;
  G g;
  H h;
  P p;
  T ti;
  E ei;
  vector<T> dat;
  vector<E> laz;
  SegmentTree() {}
  SegmentTree(
      int n_, F f, G g, H h, T ti, E ei, P p = [](E a, int b) { return a; })
      : f(f), g(g), h(h), ti(ti), ei(ei), p(p)
  {
    init(n_);
  }
  SegmentTree(
      vector<T> &v, F f, G g, H h, T ti, E ei, P p = [](E a, int b) { return a; })
      : f(f), g(g), h(h), ti(ti), ei(ei), p(p)
  {
    init(v.size());
    build(v);
  }
  void init(int n_)
  {
    n = 1;
    while (n < n_)
      n *= 2;
    dat.clear();
    dat.resize(2 * n - 1, ti);
    laz.clear();
    laz.resize(2 * n - 1, ei);
  }
  void build(const vector<T> v)
  {
    for (int i = 0; i < v.size(); i++)
      dat[i + n - 1] = v[i];
    for (int i = n - 2; i >= 0; i--)
      dat[i] = f(dat[i * 2 + 1], dat[i * 2 + 2]);
  }
  void eval(int len, int k)
  {
    if (laz[k] == ei)
      return;
    if (k * 2 + 1 < n * 2 - 1)
    {
      laz[k * 2 + 1] = h(laz[k * 2 + 1], laz[k]);
      laz[k * 2 + 2] = h(laz[k * 2 + 2], laz[k]);
    }
    dat[k] = g(dat[k], p(laz[k], len));
    laz[k] = ei;
  }
  T update(int a, int b, E x, int k, int l, int r)
  {
    eval(r - l, k);
    if (r <= a || b <= l)
      return dat[k];
    if (a <= l && r <= b)
    {
      laz[k] = h(laz[k], x);
      return g(dat[k], p(laz[k], r - l));
    }
    return dat[k] = f(update(a, b, x, k * 2 + 1, l, (l + r) / 2),
                      update(a, b, x, k * 2 + 2, (l + r) / 2, r));
  }
  T update(int a, int b, E x) { return update(a, b, x, 0, 0, n); }
  T query(int a, int b, int k, int l, int r)
  {
    eval(r - l, k);
    if (r <= a || b <= l)
      return ti;
    if (a <= l && r <= b)
      return dat[k];
    T vl = query(a, b, k * 2 + 1, l, (l + r) / 2);
    T vr = query(a, b, k * 2 + 2, (l + r) / 2, r);
    return f(vl, vr);
  }
  T query(int a, int b) { return query(a, b, 0, 0, n); }
  void disp()
  {
    rep(i, n) cerr << query(i, i + 1) << " ";
    cerr << "\n";
  }
};
auto my_min = [](ll a, ll b) { return min(a, b); };
int n;
vector<int> a;
BIT<ll> bit_l, bit_r;
SegmentTree<ll, ll> sg;
ll inv = 0;
struct Mo
{
  vector<int> left, right, order;
  vector<vector<bool>> v;
  int width;
  int nl, nr, ptr;
  Mo(int n) : width((int)sqrt(n)), nl(0), nr(0), ptr(0), v(vector<vector<bool>>(n, vector<bool>(2, 0))) {}
  void insert(int l, int r) /* [l, r) */
  {
    left.push_back(l);
    right.push_back(r);
  }
  /* ソート */
  void build()
  {
    order.resize(left.size());
    iota(begin(order), end(order), 0);
    sort(begin(order), end(order), [&](int a, int b) {
      if (left[a] / width != left[b] / width)
        return left[a] < left[b];
      return right[a] < right[b];
    });
  }
  /* クエリを 1 つぶんすすめて, クエリのidを返す */
  void process(int &query_id, ll &len)
  {
    if (ptr == order.size())
    {
      query_id = -1;
      return;
    }
    const auto id = order[ptr];
    while (nl > left[id])
      distribute(--nl, 0);
    while (nr < right[id])
      distribute(nr++, 1);
    while (nl < left[id])
      distribute(nl++, 0);
    while (nr > right[id])
      distribute(--nr, 1);
    query_id = order[ptr++], len = right[id] - left[id];
  }
  inline void distribute(int idx, bool R)
  {
    v[idx][R].flip();
    if (v[idx][R] ^ !R)
      add(idx, R);
    else
      del(idx, R);
  }
  void add(int idx, bool R)
  {
    //cerr << "add\n";
    //dbg(idx);
    //dbg(R);
    if (!R) // left
    {
      sg.update(0, a[idx], -1);
      bit_l.add(a[idx], -1);
    }
    else // right
    {
      sg.update(a[idx] + 1, n, -1);
      bit_r.add(a[idx], -1);
    }
    inv -= bit_l.sum(a[idx] + 1, n) + bit_r.sum(0, a[idx]);
    //sg.disp();
  }
  void del(int idx, bool R)
  {
    //cerr << "del\n";
    //dbg(idx);
    //dbg(R);
    if (!R) // left
    {
      sg.update(0, a[idx], 1);
      bit_l.add(a[idx], 1);
    }
    else // right
    {
      sg.update(a[idx] + 1, n, 1);
      bit_r.add(a[idx], 1);
    }
    inv += bit_l.sum(a[idx] + 1, n) + bit_r.sum(0, a[idx]);
    //sg.disp();
  }
};
void solve()
{
  int q;
  cin >> n >> q;
  bit_l = BIT<ll>(n), bit_r = BIT<ll>(n);
  vector<ll> sg_init(n, 0);
  sg = SegmentTree<ll, ll>(sg_init, my_min, plus<ll>(), plus<ll>(), (ll)1e18, 0LL);
  a.resize(n);
  rep(i, n)
  {
    cin >> a[i];
    a[i]--;
  }
  for (int i = n - 1; i >= 0; i--)
  {
    inv += bit_r.sum(0, a[i]);
    bit_r.add(a[i], 1);
  }
  //dbg(inv);
  Mo mo(n);
  rep(qi, q)
  {
    int l, r;
    cin >> l >> r;
    l--;
    mo.insert(l, r);
  }
  mo.build();
  rep(i, n) sg.update(a[i] + 1, n, 1);
  //sg.disp();
  vector<int> ans(n);
  rep(qi, q)
  {
    int i;
    ll len;
    mo.process(i, len);
    //dbg(i);
    //dbg(inv);
    ans[i] = inv + sg.query(0, n) * len;
    //sg.disp();
  }
  rep(i, q) cout << ans[i] << "\n";
}
int main()
{
  solve();
}
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