結果

問題 No.1231 Make a Multiple of Ten
ユーザー satashun
提出日時 2020-09-18 21:24:38
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 90 ms / 2,000 ms
コード長 2,018 bytes
コンパイル時間 1,717 ms
コンパイル使用メモリ 194,012 KB
最終ジャッジ日時 2025-01-14 16:22:37
ジャッジサーバーID
(参考情報)
judge1 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 13
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pii = pair<int, int>;
template <class T>
using V = vector<T>;
template <class T>
using VV = V<V<T>>;
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define fi first
#define se second
#define rep(i, n) rep2(i, 0, n)
#define rep2(i, m, n) for (int i = m; i < (n); i++)
#define per(i, b) per2(i, 0, b)
#define per2(i, a, b) for (int i = int(b) - 1; i >= int(a); i--)
#define ALL(c) (c).begin(), (c).end()
#define SZ(x) ((int)(x).size())
constexpr ll TEN(int n) { return (n == 0) ? 1 : 10 * TEN(n - 1); }
template <class T, class U>
void chmin(T& t, const U& u) {
if (t > u) t = u;
}
template <class T, class U>
void chmax(T& t, const U& u) {
if (t < u) t = u;
}
template <class T, class U>
ostream& operator<<(ostream& os, const pair<T, U>& p) {
os << "(" << p.first << "," << p.second << ")";
return os;
}
template <class T>
ostream& operator<<(ostream& os, const vector<T>& v) {
os << "{";
rep(i, v.size()) {
if (i) os << ",";
os << v[i];
}
os << "}";
return os;
}
#ifdef LOCAL
void debug_out() { cerr << endl; }
template <typename Head, typename... Tail>
void debug_out(Head H, Tail... T) {
cerr << " " << H;
debug_out(T...);
}
#define debug(...) \
cerr << __LINE__ << " [" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#define dump(x) cerr << __LINE__ << " " << #x << " = " << (x) << endl
#else
#define debug(...) (void(0))
#define dump(x) (void(0))
#endif
int dp[11][10];
int main() {
int N;
cin >> N;
V<int> cnt(10);
rep(i, N) {
int x;
cin >> x;
cnt[x % 10]++;
}
memset(dp, -1, sizeof(dp));
dp[0][0] = 0;
rep(i, 10) {
rep(j, 10) {
if (dp[i][j] == -1) continue;
rep(k, cnt[i] + 1) {
int d = k * i % 10;
chmax(dp[i + 1][(j + d) % 10], dp[i][j] + k);
}
}
}
cout << dp[10][0] << endl;
return 0;
}
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