結果

問題 No.1234 典型RMQ
ユーザー hamamu
提出日時 2020-09-18 22:24:57
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 124 ms / 2,000 ms
コード長 6,495 bytes
コンパイル時間 2,206 ms
コンパイル使用メモリ 208,636 KB
最終ジャッジ日時 2025-01-14 17:25:18
ジャッジサーバーID
(参考情報)
judge5 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 27
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

·#include "bits/stdc++.h"
using namespace std;
using ll=long long;
using vll=vector< ll>;
using vvll=vector< vll>;
using vvvll=vector< vvll>;
using vvvvll=vector<vvvll>;
constexpr ll INF = 1LL << 60;
struct Fast{ Fast(){ cin.tie(0); ios::sync_with_stdio(false); cout<<fixed<<setprecision(numeric_limits<double>::max_digits10); } } fast;
#define REPS(i, S, E) for (ll i = (S); i <= (E); i++)
#define REP(i, N) REPS(i, 0, (N)-1)
#define DEPS(i, S, E) for (ll i = (E); i >= (S); i--)
#define DEP(i, N) DEPS(i, 0, (N)-1)
#define rep(i, S, E) for (ll i = (S); i <= (E); i++)
#define dep(i, E, S) for (ll i = (E); i >= (S); i--)
#define each(e, v) for (auto&& e : v)
#define ALL(v) (v).begin(), (v).end()
#define RALL(v) (v).rbegin(), (v).rend()
template<class T> inline bool chmax(T &a, T b) { if (a < b) { a = b; return true; }return false; }
template<class T> inline bool chmin(T &a, T b) { if (a > b) { a = b; return true; }return false; }
template<class T> inline T MaxE(vector<T>&v,ll S,ll E){ T m=v[S]; rep(i,S,E)chmax(m,v[i]); return m; }
template<class T> inline T MinE(vector<T>&v,ll S,ll E){ T m=v[S]; rep(i,S,E)chmin(m,v[i]); return m; }
template<class T> inline T MaxE(vector<T> &v) { return MaxE(v,0,(ll)v.size()-1); }
template<class T> inline T MinE(vector<T> &v) { return MinE(v,0,(ll)v.size()-1); }
template<class T> inline T Sum(vector<T> &v,ll S,ll E){ T s=T(); rep(i,S,E)s+=v[i]; return s; }
template<class T> inline T Sum(vector<T> &v) { return Sum(v,0,v.size()-1); }
template<class T> inline ll sz(T &v){ return (ll)v.size(); }
inline ll CEIL(ll a,ll b){ return (a<0) ? -(-a/b) : (a+b-1)/b; }
inline ll FLOOR(ll a,ll b){ return -CEIL(-a,b); }
#if 0
#include <atcoder/all>
using namespace atcoder;
#endif
template <class T, class E> struct LazySegmentTree{
using F = function<T(T, T)>;
using G = function<T(T, E)>;
using H = function<E(E, E)>;
F f; //!<
G g; //!<
H h; //!<
T ti; //!<
E ei; //!< 使OK
ll n=1; //!< 2
vector<T> dat;
vector<E> laz;
LazySegmentTree() {}
LazySegmentTree(vector<T> &v, F f, G g, H h, T ti, E ei) { Init(v, f, g, h, ti, ei); }
void Init(vector<T> &v, F f, G g, H h, T ti, E ei){
this->f=f; this->g=g; this->h=h; this->ti=ti; this->ei=ei;
while (n<(ll)v.size()) n<<=1;
dat.resize(2*n-1, ti);
laz.resize(2*n-1, ei);
for (ll i=0; i<(ll)v.size(); i++) dat[n-1+i] = v[i];
for (ll i=n-2; i>=0; i--) dat[i] = f(dat[2*i+1], dat[2*i+2]);
}
void Update(ll a, ll b, E x){ update(a, b+1, x, 0, 0, n); } //[a,b]x
void update(ll a, ll b, E x, ll k, ll l, ll r){ //k=[l,r)
if (r<=a || b<=l) eval(k); //[l,r)[a,b)
else if (a<=l && r<=b){ //[l,r)[a,b)
laz[k] = h(laz[k], x);
eval(k); //dat[k]
}
else { //[l,r)[a,b)
eval(k); //
update(a, b, x, k*2+1, l, (l+r)/2);
update(a, b, x, k*2+2, (l+r)/2, r);
dat[k] = f(dat[k*2+1], dat[k*2+2]);
}
}
T Range(ll a, ll b) { return range(a, b+1, 0, 0, n); }//[a,b]
T range(ll a, ll b, ll k, ll l, ll r){ //k=[l,r)
if (r<=a || b<=l) return ti; //[l,r)[a,b)
eval(k); //
if (a<=l && r<=b) return dat[k];//[l,r)[a,b)
return f(range(a, b, k*2+1, l, (l+r)/2), range(a, b, k*2+2, (l+r)/2, r));
//[l,r)[a,b)
}
ll FindL(ll a, ll b, T x) { return findL(a, b+1, x, 0, 0, n); }
ll findL(ll a, ll b, T x, ll k, ll l, ll r){ //[l,r) b
if (r<=a || b<=l) return b; //
eval(k);
if (f(dat[k], x) != dat[k]) return b; //
if (n-1 <= k) return k-(n-1); //return
ll i = findL(a, b, x, 2*k+1, l, (l+r)/2); //
if (i==b) i = findL(a, b, x, 2*k+2, (l+r)/2, r); //
return i;
}
ll FindR(ll a, ll b, T x) { return findR(a, b+1, x, 0, 0, n); }
ll findR(ll a, ll b, T x, ll k, ll l, ll r){ //[l,r) a-1
if (r<=a || b<=l) return a-1; //
eval(k);
if (f(dat[k], x) != dat[k]) return a-1; //
if (n-1 <= k) return k-(n-1); //return
ll i = findR(a, b, x, 2*k+2, (l+r)/2, r); //
if (i==a-1) i = findR(a, b, x, 2*k+1, l, (l+r)/2); //
return i;
}
void eval(ll k){
if (laz[k] == ei) return;
if (k<=n-2){ //
laz[k*2+1] = h(laz[k*2+1], laz[k]);
laz[k*2+2] = h(laz[k*2+2], laz[k]);
}
//
dat[k] = g(dat[k], laz[k]);
laz[k] = ei;
}
void Dump(ll w=5){
auto disp=[&](ll x){
if (x==-INF) cerr << setw(w) << "-INF";
else if (x== INF) cerr << setw(w) << "INF";
else cerr << setw(w) << x;
};
REP(i, n) for (ll k=i+n-1, m=1, p=1; k>=0; p=m, m*=k%2, k=(k==0)?-1:(k-1)/2){
if (m){
cerr << ((k<n-1)?"":""); disp(dat[k]); cerr<<" /"; disp(laz[k]);
}
else{
cerr << ((p&~m) ?"":"");
}
if (k==0) cerr << '\n';
} cerr << '\n';
}
};
void solve()
{
ll n; cin >> n;
vector<ll> a(n); rep(i,0,n-1){ ll a_; cin>>a_; a[i]=a_; }
LazySegmentTree<ll, ll> sgt(
a,
[](ll x, ll y){ return min(x, y); },//
[](ll x, ll y){ return x + y; },//xy
[](ll x, ll y){ return x + y; },//
INF, //
0); // 使OK
ll q; cin >> q;
rep(qq,0,q-1){
ll k,l,r,c; cin >> k >> l >> r >> c;
l--;r--;
if (k==1){
sgt.Update(l, r, c);
}
else{//k=2
ll ans=sgt.Range(l, r);
cout << ans << '\n';
}
}
}
int main(){
#if 1
solve();
#else
ll t; cin >> t;
rep(i, 0, t-1){
solve();
}
#endif
return 0;
}
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