結果

問題 No.1231 Make a Multiple of Ten
ユーザー marurunn11
提出日時 2020-09-19 10:55:21
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 182 ms / 2,000 ms
コード長 13,835 bytes
コンパイル時間 4,127 ms
コンパイル使用メモリ 221,880 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-06-23 13:55:56
合計ジャッジ時間 5,428 ms
ジャッジサーバーID
(参考情報)
judge3 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 13
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ソースコード

diff #
プレゼンテーションモードにする

#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include "bits/stdc++.h"
#ifdef _MSC_VER
#include <intrin.h> //gcc__popcnt, umul128 include
#define __builtin_popcount __popcnt
#define __builtin_popcountll __popcnt64
//#pragma intrinsic(_umul128)
#endif
//#include <atcoder/all>
//using namespace atcoder;
//#include <boost/multiprecision/cpp_int.hpp>
//#include <boost/multiprecision/cpp_dec_float.hpp>
using namespace std;
typedef long long ll;
typedef long double ld;
#define int long long
#define LL128 boost::multiprecision::int128_t
#define LL boost::multiprecision::cpp_int
#define LD100 boost::multiprecision::cpp_dec_float_100
#define rep(i, n) for(long long i = 0; i < (n); i++)
#define sqrt(d) pow((long double) (d), 0.50)
#define PII pair<int, int>
#define MP make_pair
#define PB push_back
#define ALL(v) v.begin(), v.end()
const int INF = std::numeric_limits<int>::max() / 2 - 100000000;
const long long INF2 = std::numeric_limits<long long>::max() / 2 - 100000000;
const long double pi = acos(-1);
constexpr int MOD = 1000000007; //1e9 + 7
//constexpr int MOD = 1000000009; //1e9 + 9
//constexpr int MOD = 998244353;
long long my_gcd(long long a, long long b) {
if (b == 0) return a;
return my_gcd(b, a % b);
}
// ax + by = gcd(a, b) gcd(a, b)
long long my_gcd_ext(long long a, long long b, long long& x, long long& y) {
if (b == 0) {
x = 1; y = 0;
return a;
}
long long tempo = my_gcd_ext(b, a % b, y, x);
//bx' + ry' = gcd(a, b) → (qb + r)x + by = gcd(a, b) // (r = a % b)
//b(x' - qy') + (bq + r)y' = gcd(a, b)
// x = y', y = x' - qy'
y -= (a / b) * x;
return tempo;
}
//M a gcd(a, M) = 1
long long my_invmod(long long a, long long M) {
long long x = 0, y = 0;
long long memo = my_gcd_ext(a, M, x, y);
assert(memo == 1LL);
x %= M;
if (x < 0) x += M;
return x;
}
//2
//N^aM
ll my_pow(ll N, ll a, ll M) {
ll tempo;
if (a == 0) {
return 1;
}
else {
if (a % 2 == 0) {
tempo = my_pow(N, a / 2, M);
return (tempo * tempo) % M;
}
else {
tempo = my_pow(N, a - 1, M);
return (tempo * N) % M;
}
}
}
ll my_pow(ll N, ll a) {
ll tempo;
if (a == 0) {
return 1;
}
else {
if (a % 2 == 0) {
tempo = my_pow(N, a / 2);
return (tempo * tempo);
}
else {
tempo = my_pow(N, a - 1);
return (tempo * N);
}
}
}
//N_C_a M
ll my_combination(ll N, ll a, ll M) {
if (N < a) return 0;
ll answer = 1;
rep(i, a) {
answer *= (N - i);
answer %= M;
}
rep(i, a) {
answer *= my_pow(i + 1, M - 2, M);
answer %= M;
}
return answer;
}
//N_C_i M v.at(i)
void my_combination_table(ll N, ll M, vector<ll>& v) {
v.assign(N + 1, 1);
for (ll i = 1; i <= N; i++) {
v.at(i) = v.at(i - 1) * (N - (i - 1LL));
v.at(i) %= M;
v.at(i) *= my_pow(i, M - 2, M);
v.at(i) %= M;
}
}
//(N + i)_C_N M v.at(i) (v )
void my_combination_table2(ll N, ll M, vector<ll>& v) {
v.at(0) = 1;
for (ll i = 1; i < (ll)v.size(); i++) {
v.at(i) = v.at(i - 1) * (N + i);
v.at(i) %= M;
v.at(i) *= my_pow(i, M - 2, M);
v.at(i) %= M;
}
}
//x ! dp 20 ! = 2.43e18 long long
ll factorial(ll x, vector<ll>& dp) {
if ((ll)dp.size() <= x) {
int n = dp.size();
rep(i, x + 1 - n) {
dp.push_back(0);
}
}
if (x == 0) return dp.at(x) = 1;
if (dp.at(x) != -1 && dp.at(x) != 0) return dp.at(x);
return dp.at(x) = x * factorial(x - 1, dp);
}
// M x ! dp
ll factorial2(ll x, ll M, vector<ll>& dp) {
if ((ll)dp.size() <= x) {
int n = dp.size();
rep(i, x + 1 - n) {
dp.push_back(0);
}
}
if (x == 0) return dp.at(x) = 1;
if (dp.at(x) != -1 && dp.at(x) != 0) return dp.at(x);
ll tempo = (x * factorial2(x - 1, M, dp));
tempo %= M;
return dp.at(x) = tempo;
}
// mod M (M: prime)x ! dp
ll factorial_inverse(ll x, ll M, vector<ll>& dp) {
if ((ll)dp.size() <= x) {
int n = dp.size();
rep(i, x + 1 - n) {
dp.push_back(0);
}
}
if (x == 0) return dp.at(x) = 1;
if (dp.at(x) != -1 && dp.at(x) != 0) return dp.at(x);
return dp.at(x) = (my_pow(x, M - 2, M) * factorial_inverse(x - 1, M, dp)) % M;
}
//N_C_a M
ll my_combination2(ll N, ll a, ll M, vector<ll>& dp_factorial, vector<ll>& dp_factorial_inverse) {
if ((ll)dp_factorial.size() <= N) {
factorial2(N, M, dp_factorial);
}
if ((ll)dp_factorial_inverse.size() <= N) {
factorial_inverse(N, M, dp_factorial_inverse);
}
if (N < a) return 0;
ll answer = 1;
answer *= dp_factorial.at(N);
answer %= M;
answer *= dp_factorial_inverse.at(N - a);
answer %= M;
answer *= dp_factorial_inverse.at(a);
answer %= M;
return answer;
}
// base n iv.at(i) ( n )
void ll_to_vector(signed base, long long n, vector<signed>& v) {
long long tempo = n;
long long tempo2 = n;
signed n_digit = 1;
while (tempo2 >= base) {
tempo2 /= base;
n_digit++;
}
v.assign(n_digit, 0); // v 調
// n_digit = v.size(); // v
for (signed i = 0; i < n_digit; i++) {
long long denominator = my_pow(base, n_digit - 1 - i);
v.at(i) = tempo / denominator;
tempo -= v.at(i) * denominator;
}
}
int char_to_int(char c) {
switch (c) {
case '0': return 0; case '1': return 1; case '2': return 2; case '3': return 3; case '4': return 4;
case '5': return 5; case '6': return 6; case '7': return 7; case '8': return 8; case '9': return 9;
default: return 0;
}
}
//prime false O(n loglog n)
void prime_judge(vector<bool>& prime_or_not) {
prime_or_not.assign(prime_or_not.size(), true);
prime_or_not.at(0) = false;
prime_or_not.at(1) = false;
long long n = prime_or_not.size() - 1;
for (long long i = 2; 2 * i <= n; i++) {
prime_or_not.at(2 * i) = false;
}
for (long long i = 3; i * i <= n; i += 2) {
//i false
if (prime_or_not.at(i)) {
long long j = i * i; // i^2 i false
while (j < n + 1) {
prime_or_not.at(j) = false;
j += 2 * i;
}
}
}
};
// n + 1 vector res.at(i) i 1 res.at(i) == i i
// 2e8 3.2 prime_judge 3
vector<long long> sieve(long long n) {
n++; // n +1
vector<long long> res(n, 0);
for (long long i = 1; i < n; i++) {
if (i % 2 == 0) res.at(i) = 2; //
else res.at(i) = i;
}
for (long long i = 3; i * i < n; i += 2) {
//i i
if (res.at(i) == i) {
long long j = i * i; // i^2 i
while (j < n) {
if (res.at(j) == j) res.at(j) = i;
j += 2 * i;
}
}
}
return res;
};
//O (sqrt(n))
bool is_prime(long long N) {
if (N == 1 || N == 0) return false;
if (N == 2 || N == 3) return true;
if (N % 2 == 0) return false;
if (N % 3 == 0) return false;
for (long long i = 1; (6 * i + 1) * (6 * i + 1) <= N; ++i) {
if (N % (6 * i + 1) == 0) return false;
}
for (long long i = 0; (6 * i + 5) * (6 * i + 5) <= N; ++i) {
if (N % (6 * i + 5) == 0) return false;
}
return true;
}
// O(sqrt(N))
map<ll, ll> divide_to_prime(int target) {
map<ll, ll> res;
//sqrt(target) 調
ll upper_lim = ceil(sqrt(target));
vector<bool> prime_or_not(upper_lim + 3, true);
if (upper_lim < 20) prime_or_not.assign(25, true);
prime_or_not.at(0) = false; prime_or_not.at(1) = false;
prime_judge(prime_or_not);
ll tempo = target;
for (int i = 1; i * i <= target; i++) {
if (prime_or_not.at(i)) {
while (tempo % i == 0) {
tempo /= i;
res[i]++;
}
}
if (tempo == 1) break; //
}
if (tempo != 1) res[tempo]++; //sqrt(target) 1
return res;
}
// sieve vector min_factor
map<long long, long long> divide_to_prime2(long long target, vector<long long>& min_factor) {
map<long long, long long> res;
if (min_factor.empty() || (long long)min_factor.size() - 1 < target) min_factor = sieve(target);
while (target > 1) {
res[min_factor[target]]++;
target /= min_factor[target];
}
return res;
}
// O(sqrt(N))
vector<long long> count_dividers(long long target) {
vector <long long> dividers, tempo;
long long i = 1;
while (i * i < target + 1) {
if (target % i == 0) {
dividers.push_back(i);
if (i < target / i) tempo.push_back(target / i); // ifsqrt(target)
}
i++;
}
for (long long j = 0; j < (long long)tempo.size(); j++) {
dividers.push_back(tempo.at(tempo.size() - 1 - j));
}
return dividers;
}
// sieve vector min_factor
vector<long long> count_dividers2(long long target, vector<long long>& min_factor) {
vector <long long> dividers = { 1 };
map<long long, long long> memo = divide_to_prime2(target, min_factor);
for (auto&& iter = memo.begin(); iter != memo.end(); iter++) {
vector <long long> tempo = dividers;
for (long long k = 0; k < (long long)tempo.size(); k++) {
long long times = 1;
for (long long j = 1; j <= (iter->second); j++) {
times *= iter->first;
dividers.push_back(tempo[k] * times);
}
}
}
sort(dividers.begin(), dividers.end()); //sort
return dividers;
}
void BFS_labyrinth(queue<pair<int, int>>& que, vector<vector<int>>& dist, int& area) {
int H = dist.size();
int W = dist.at(0).size();
while (!que.empty()) {
int h, w;
pair<int, int> tempo = que.front(); que.pop();
h = tempo.first;
w = tempo.second;
//cout << temp_i << " " << temp_j << endl;
for (int dh = -1; dh <= 1; dh++) {
for (int dw = -1; dw <= 1; dw++) {
if (h + dh < 0 || H <= h + dh) continue; //
if (w + dw < 0 || W <= w + dw) continue; //
if (dh == 0 && dw == 0) continue; //
if (dh * dw != 0) continue; //
if (dist.at(h + dh).at(w + dw) != -1) continue; // INF ok
dist.at(h + dh).at(w + dw) = dist.at(h).at(w) + 1;
que.push(make_pair(h + dh, w + dw));
}
}
//
if (que.empty()) {
rep(i, H) {
rep(j, W) {
if (dist.at(i).at(j) == -1) {
que.push(make_pair(i, j));
dist.at(i).at(j) = 0;
area++;
break;
}
}
if (!que.empty()) break;
}
}
}
}
void BFS01_labyrinth(deque<pair<int, int>>& que, vector<vector<int>>& dist, vector<vector<int>>& cost) {
int H = dist.size();
int W = dist.at(0).size();
while (!que.empty()) {
int h, w;
pair<int, int> tempo = que.front(); que.pop_front();
h = tempo.first;
w = tempo.second;
//cout << temp_i << " " << temp_j << endl;
for (int dh = -1; dh <= 1; dh++) {
for (int dw = -1; dw <= 1; dw++) {
if (h + dh < 0 || H <= h + dh) continue; //
if (w + dw < 0 || W <= w + dw) continue; //
if (dh == 0 && dw == 0) continue; //
if (dh * dw != 0) continue; //
if (dist.at(h + dh).at(w + dw) != -1) continue; // INF ok
dist.at(h + dh).at(w + dw) = dist.at(h).at(w) + cost.at(h + dh).at(w + dw);
if (cost.at(h + dh).at(w + dw) == 0) {//
que.push_front(make_pair(h + dh, w + dw));
}
else {//
que.push_back(make_pair(h + dh, w + dw));
}
}
}
}
}
int dfs(const vector<int>& cnt, int v, int sum, int tempo) {
if (v == 10) {
if (sum == 0) return tempo;
else return 0;
}
int memo = 0;
for (int i = 0; i <= cnt.at(v); i++) {
int sum2 = sum + i * v;
sum2 %= 10;
memo = max(memo, dfs(cnt, v + 1, sum2, tempo + i));
}
return memo;
}
signed main() {
int N; cin >> N;
vector<int> cnt(10, 0);
int sum = 0;
rep(i, N) {
int A; cin >> A;
cnt.at(A % 10)++;
sum += A % 10;
sum %= 10;
}
if (sum == 0) {
cout << N << endl;
return 0;
}
if (cnt.at(sum) != 0) {
cout << N - 1 << endl;
return 0;
}
int res = 0;
rep(i, 10) {
if (i == 0) {
res += cnt.at(i);
cnt.at(i) = 0;
}
else {
res += (cnt.at(i) / 10) * 10;
cnt.at(i) %= 10;
}
}
int res2 = dfs(cnt, 1, 0, 0);
cout << res + res2 << endl;
}
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