結果
| 問題 |
No.294 SuperFizzBuzz
|
| コンテスト | |
| ユーザー |
fmhr
|
| 提出日時 | 2015-10-25 17:48:53 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 1,537 bytes |
| コンパイル時間 | 178 ms |
| コンパイル使用メモリ | 82,528 KB |
| 実行使用メモリ | 128,888 KB |
| 最終ジャッジ日時 | 2024-09-13 08:51:50 |
| 合計ジャッジ時間 | 30,372 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 WA * 2 |
| other | AC * 3 WA * 7 TLE * 2 |
ソースコード
# coding:utf-8
import sys
# from itertools import product
#
#
#ume = [0, 0, 1, 3, 6, 11, 21, 42, 85, 171, 342, 683, 1365, 2730, 5461, 10923, 21846, 43691, 87381, 174762, 349525,
# 699051, 1398102, 2796203, 5592405, 10000001]
ume_i = [0,22, 23, 24, 24, 24, 25, 25, 25, 25, 25]
ume_j = [0,1805703, 3611383, 1222795, 7222771, 13222757, 2445581, 8445561, 14445575, 20445563, 26445559]
def popcount(x):
return bin(x).count("1")
# if N in ume:
# print(ume.index(N))
# sys.exit()
# else:
def solve():
N = int(input())
count = 0
# 100000毎にume
# ume_i = []
# ume_j = []
# c = 1000000
if 0<=N<1000000:
p = 0
elif 1000000<=N<2000000:
p = 1
elif 2000000<=N<3000000:
p = 2
elif 3000000<=N<4000000:
p = 3
elif 4000000<=N<5000000:
p = 4
elif 5000000<=N<6000000:
p = 5
elif 6000000<=N<7000000:
p = 6
elif 7000000<=N<8000000:
p = 7
elif 8000000<=N<9000000:
p = 8
elif 9000000<=N<10000000:
p = 9
elif 10000000<=N:
p = 10
start_i = ume_i[p]
start_j = ume_j[p]
count = p*1000000-1
x = 0
for i in range(start_i,26):
for j in range(start_j,10000000000000):
a = bin(j)[2:]
if len(a)>i:
break
if popcount(j)%3==0 and popcount(j)>=3 and a[-1]=='1':
count += 1
# ====
# if count == c:
# ume_i.append(i)
# ume_j.append(j)
# c += 1000000
# ====
if count==N:
a = '0'*(i-len(a))+a
n = a.replace('0', '3').replace('1', '5')
x = ''.join(n)
x = int(x)
print(x)
# print(ume_i)
# print(ume_j)
sys.exit()
solve()
fmhr