結果
問題 | No.294 SuperFizzBuzz |
ユーザー | fmhr |
提出日時 | 2015-10-25 17:52:36 |
言語 | PyPy3 (7.3.15) |
結果 |
WA
|
実行時間 | - |
コード長 | 1,590 bytes |
コンパイル時間 | 313 ms |
コンパイル使用メモリ | 82,208 KB |
実行使用メモリ | 82,600 KB |
最終ジャッジ日時 | 2024-09-13 09:00:35 |
合計ジャッジ時間 | 30,497 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 40 ms
52,624 KB |
testcase_01 | AC | 42 ms
55,636 KB |
testcase_02 | AC | 41 ms
52,480 KB |
testcase_03 | AC | 43 ms
52,492 KB |
testcase_04 | AC | 41 ms
52,828 KB |
testcase_05 | AC | 41 ms
52,320 KB |
testcase_06 | AC | 60 ms
70,156 KB |
testcase_07 | AC | 79 ms
75,620 KB |
testcase_08 | AC | 3,321 ms
75,628 KB |
testcase_09 | AC | 4,238 ms
75,932 KB |
testcase_10 | WA | - |
testcase_11 | AC | 1,587 ms
75,572 KB |
testcase_12 | AC | 4,070 ms
75,648 KB |
testcase_13 | TLE | - |
testcase_14 | TLE | - |
ソースコード
# coding:utf-8 import sys # from itertools import product # # #ume = [0, 0, 1, 3, 6, 11, 21, 42, 85, 171, 342, 683, 1365, 2730, 5461, 10923, 21846, 43691, 87381, 174762, 349525, # 699051, 1398102, 2796203, 5592405, 10000001] ume_i = [0,22, 23, 24, 24, 24, 25, 25, 25, 25, 25] ume_j = [0,1805703, 3611383, 1222795, 7222771, 13222757, 2445581, 8445561, 14445575, 20445563, 26445559] def popcount(x): return bin(x).count("1") # if N in ume: # print(ume.index(N)) # sys.exit() # else: def solve(): N = int(input()) count = 0 # 100000毎にume # ume_i = [] # ume_j = [] # c = 1000000 # if 0<=N<1000000: # p = 0 # elif 1000000<=N<2000000: # p = 1 # elif 2000000<=N<3000000: # p = 2 # elif 3000000<=N<4000000: # p = 3 # elif 4000000<=N<5000000: # p = 4 # elif 5000000<=N<6000000: # p = 5 # elif 6000000<=N<7000000: # p = 6 # elif 7000000<=N<8000000: # p = 7 # elif 8000000<=N<9000000: # p = 8 # elif 9000000<=N<10000000: # p = 9 # elif 10000000<=N: # p = 10 p = int(N/1000000) start_i = ume_i[p] start_j = ume_j[p] if p!=0: count = p*1000000-1 x = 0 for i in range(start_i,26): for j in range(start_j,10000000000000): a = bin(j)[2:] if len(a)>i: break if popcount(j)%3==0 and popcount(j)>=3 and a[-1]=='1': count += 1 # ==== # if count == c: # ume_i.append(i) # ume_j.append(j) # c += 1000000 # ==== if count==N: a = '0'*(i-len(a))+a n = a.replace('0', '3').replace('1', '5') x = ''.join(n) x = int(x) print(x) # print(ume_i) # print(ume_j) sys.exit() solve()