結果
問題 | No.1239 Multiplication -2 |
ユーザー | chocopuu |
提出日時 | 2020-09-25 23:44:09 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 4,218 bytes |
コンパイル時間 | 2,236 ms |
コンパイル使用メモリ | 208,340 KB |
実行使用メモリ | 28,288 KB |
最終ジャッジ日時 | 2024-06-28 08:23:23 |
合計ジャッジ時間 | 7,051 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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テストケース
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ソースコード
#include "bits/stdc++.h" using namespace std; //#include "atcoder/all" //using namespace atcoder; #define int long long #define REP(i, n) for (int i = 0; i < (int)n; ++i) #define RREP(i, n) for (int i = (int)n - 1; i >= 0; --i) #define FOR(i, s, n) for (int i = s; i < (int)n; ++i) #define RFOR(i, s, n) for (int i = (int)n - 1; i >= s; --i) #define ALL(a) a.begin(), a.end() #define IN(a, x, b) (a <= x && x < b) template<class T>istream&operator >>(istream&is,vector<T>&vec){for(T&x:vec)is>>x;return is;} template<class T>inline void out(T t){cout << t << "\n";} template<class T,class... Ts>inline void out(T t,Ts... ts){cout << t << " ";out(ts...);} template<class T>inline bool CHMIN(T&a,T b){if(a > b){a = b;return true;}return false;} template<class T>inline bool CHMAX(T&a,T b){if(a < b){a = b;return true;}return false;} constexpr int INF = 1e18; template<int MOD> struct Fp { long long val; constexpr Fp(long long v = 0) noexcept : val(v % MOD) { if (val < 0) val += MOD; } constexpr int getmod() { return MOD; } constexpr Fp operator - () const noexcept { return val ? MOD - val : 0; } constexpr Fp operator + (const Fp& r) const noexcept { return Fp(*this) += r; } constexpr Fp operator - (const Fp& r) const noexcept { return Fp(*this) -= r; } constexpr Fp operator * (const Fp& r) const noexcept { return Fp(*this) *= r; } constexpr Fp operator / (const Fp& r) const noexcept { return Fp(*this) /= r; } constexpr Fp& operator += (const Fp& r) noexcept { val += r.val; if (val >= MOD) val -= MOD; return *this; } constexpr Fp& operator -= (const Fp& r) noexcept { val -= r.val; if (val < 0) val += MOD; return *this; } constexpr Fp& operator *= (const Fp& r) noexcept { val = val * r.val % MOD; return *this; } constexpr Fp& operator /= (const Fp& r) noexcept { long long a = r.val, b = MOD, u = 1, v = 0; while (b) { long long t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); } val = val * u % MOD; if (val < 0) val += MOD; return *this; } constexpr bool operator == (const Fp& r) const noexcept { return this->val == r.val; } constexpr bool operator != (const Fp& r) const noexcept { return this->val != r.val; } friend constexpr ostream& operator << (ostream &os, const Fp<MOD>& x) noexcept { return os << x.val; } friend constexpr Fp<MOD> modpow(const Fp<MOD> &a, long long n) noexcept { if (n == 0) return 1; auto t = modpow(a, n / 2); t = t * t; if (n & 1) t = t * a; return t; } }; template<class T> struct BiCoef { vector<T> fact_, inv_, finv_; constexpr BiCoef() {} constexpr BiCoef(int n) noexcept : fact_(n, 1), inv_(n, 1), finv_(n, 1) { init(n); } constexpr void init(int n) noexcept { fact_.assign(n, 1), inv_.assign(n, 1), finv_.assign(n, 1); int MOD = fact_[0].getmod(); for(int i = 2; i < n; i++){ fact_[i] = fact_[i-1] * i; inv_[i] = -inv_[MOD%i] * (MOD/i); finv_[i] = finv_[i-1] * inv_[i]; } } constexpr T com(int n, int k) const noexcept { if (n < k || n < 0 || k < 0) return 0; return fact_[n] * finv_[k] * finv_[n-k]; } constexpr T P(int n, int k) const noexcept { if (n < k || n < 0 || k < 0) return 0; return fact_[n] * finv_[n-k]; } constexpr T fact(int n) const noexcept { if (n < 0) return 0; return fact_[n]; } constexpr T inv(int n) const noexcept { if (n < 0) return 0; return inv_[n]; } constexpr T finv(int n) const noexcept { if (n < 0) return 0; return finv_[n]; } }; // const int MOD = 1000000007; const int MOD = 998244353; using mint = Fp<MOD>; BiCoef<mint> bc; // bc.init(500050); mint dp[200020][5][3]; signed main(){ int N; cin >> N; vector<int>a(N); cin >> a; REP(i, N) { REP(j, 5) { int mul = j - 2; if(!IN(-2, mul * a[i], 2 + 1)) continue; dp[i + 1][a[i] * mul + 2][0] += dp[i][j][0]; if(a[i] * mul == -2) { dp[i + 1][0][2] += dp[i][j][0] * modpow(mint(2), max(0ll ,N - i - 2)); } } dp[i + 1][a[i] + 2][0] += modpow(mint(2), max(0ll, i - 1)); if(a[i] + 2 == 0) dp[i + 1][0][2] += modpow(mint(2), max(0ll, i - 1)) * modpow(mint(2), max(0ll, N - i - 2)); } mint ans = 0; REP(i, N + 1) { out(i, dp[i][0][2]); ans += dp[i][0][2]; } out(ans / (modpow((mint)2, N - 1))); }