結果
| 問題 | No.654 Air E869120 |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2020-09-29 21:44:12 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 231 ms / 2,000 ms |
| コード長 | 1,972 bytes |
| 記録 | |
| コンパイル時間 | 270 ms |
| コンパイル使用メモリ | 82,172 KB |
| 実行使用メモリ | 87,868 KB |
| 最終ジャッジ日時 | 2024-07-04 13:25:22 |
| 合計ジャッジ時間 | 5,186 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 5 |
| other | AC * 35 |
ソースコード
# Dinic's algorithm O(|V|^2|E|)
from collections import deque
class Dinic:
def __init__(self, N):
self.N = N
self.G = [[] for i in range(N)]
def add_edge(self, fr, to, cap):
forward = [to, cap, 0, None]
forward[3] = backward = [fr, 0, 0, forward]
self.G[fr].append(forward)
self.G[to].append(backward)
def add_multi_edge(self, v1, v2, cap1, cap2):
edge1 = [v2, cap1, 0, None]
edge1[3] = edge2 = [v1, cap2, 0, edge1]
self.G[v1].append(edge1)
self.G[v2].append(edge2)
def bfs(self, s, t):
self.level = level = [None]*self.N
deq = deque([s])
level[s] = 0
G = self.G
while deq:
v = deq.popleft()
lv = level[v] + 1
for w, cap, _, _ in G[v]:
if cap and level[w] is None:
level[w] = lv
deq.append(w)
return level[t] is not None
def dfs(self, v, t, f):
if v == t:
return f
level = self.level
for e in self.it[v]:
w, cap, flow, rev = e
if cap and level[v] < level[w]:
d = self.dfs(w, t, min(f, cap))
if d:
e[1] -= d
if rev[2]==0:
e[2] += d
else:
rev[2] -= d
rev[1] += d
return d
return 0
def flow(self, s, t):
flow = 0
INF = 10**9 + 7
G = self.G
while self.bfs(s, t):
*self.it, = map(iter, self.G)
f = INF
while f:
f = self.dfs(s, t, INF)
flow += f
return flow
import sys
readline = sys.stdin.readline
INF = 10**18
N, M, d = map(int, readline().split())
dinic = Dinic(2*M+2)
fr = [0]*M
to = [0]*M
for i in range(M):
u, v, p, q, w = map(int, readline().split())
dinic.add_edge(1+i, 1+M+i, w)
fr[i] = (u,p)
to[i] = (v,q+d)
if u==1:
dinic.add_edge(0,1+i,INF)
if v==N:
dinic.add_edge(1+M+i,2*M+1,INF)
for i,(v,q) in enumerate(to):
for j,(u,p) in enumerate(fr):
if v==u and q<=p:
dinic.add_edge(1+M+i,1+j,INF)
ans = dinic.flow(0, 2*M+1)
print(ans)